如何使用 vim/grep/cat/awk 删除只有数字的行？

Question

我有这个文字

which will be considered further in Chapter 6
    Siannis et al., 2005
    Crowther and Lambert, 2013a
    Schumacher et al., 1994
    2014
    df=4
    2005
    2005
    0, 1
    4.1

我需要

which will be considered further in Chapter 6
Siannis et al., 2005
Crowther and Lambert, 2013a
Schumacher et al., 1994
df=4

我想删除那些没有单词的行。如果你能用 vim/grep/awk/cat 或其他工具来做这件事，欢迎。

Answer 1

您可以使用 grep 执行如下操作：

$ grep '[a-z]' text.txt

Answer 2

如果您正在寻找单词，请检查单词！

$ grep -w '[a-z]\+' file
which will be considered further in Chapter 6
    Siannis et al., 2005
    Crowther and Lambert, 2013a
    Schumacher et al., 1994
    df=4

[a-z]这将打印包含至少 1 个字符长的字符块的行。