你好,我该如何删除电子邮件中@domain 之前包含少于 3 个字母的行,因为@domains 已经包含超过 3 个字母或 3 个字母,我想跳过它并在@domain 之前搜索
因此其为 s1111g@domain。“anything”:密码行
因此搜索将在“@”域名之前进行,例如@gmail 或@yahoo 或任何电子邮件
文件的完整示例包含:
[email protected]:Keepline1
[email protected]:Removeline0
S*556&[email protected]:Removeline0
*[email protected]:Keepline1
3%6%768()[email protected]:Removeline0
¿H£1§¥[email protected]:Removeline0
[email protected]:Keepline1
§[email protected]:Keepline1
需要结果:
[email protected]:Keepline1
*[email protected]:Keepline1
[email protected]:Keepline1
§[email protected]:Keepline1
答案1
以下是一种方法:
- Ctrl+H
- 找什么:
^(?:[^a-z@]*[a-z]){0,3}[^a-z@]*@.+(?:\R|$)
- 用。。。来代替:
EMPTY
- Replace all
解释:
^ : begining of line
(?: : start non capture group
[^a-z@]* : 0 or more non alphabetic or @
[a-z] : an alphabetic
){0,3} : group exists from 0 up to 3 times
[^a-z@]* : 0 or more non alphabetic or @
@ : literally @
.+ : 1 or more any character but newline
(?:\R|$) : any kind of linebreak (\r, \n, \r\n) or end of line
请勿检查. matches newline
给定示例的结果:
[email protected]:Keepline1
*[email protected]:Keepline1
[email protected]:Keepline1
§[email protected]:Keepline1