我想删除分隔符 : 之前的行中重复的用户名并仅保留这些用户名的第一行。
线条示例:
zzzz:000000zl
zzzz:000000zl!
zzzz:000000zl1
zzzz:000000zl123
zzzz:000000zl69
zzzz:000000zl?
AdSFF12:Sample198445
AdSFF12:Sample198445!
AdSFF12:Sample198445#
AdSFF12:Sample198445$
AdSFF12:Sample1984456
TestOf13:Smpletest1211
TestOf13:Smpletest1211!
TestOf13:Smpletest1211#
TestOf13:Smpletest1211$
TestOf13:Smpletest12112
TestOf13:Smpletest561
TestOf13:Smpletest561!
TestOf13:Smpletest561#
TestOf13:Smpletest561$
TestOf13:Smpletest5612
TestOf13:SmpletestZ2
TestOf13:SmpletestZ2!
TestOf13:SmpletestZ2#
TestOf13:SmpletestZ2$
TestOf13:SmpletestZ23
TestOf13:Smpletestz3qwe
TestOf13:Smpletestz3qwe!
TestOf13:Smpletestz3qwe1
TestOf13:Smpletestz3qwe123
TestOf13:Smpletestz3qwe69
TestOf13:Smpletestz3qwe?
所需结果:
zzzz:000000zl
AdSFF12:Sample198445
TestOf13:Smpletest1211
非常感谢您的帮助,提前谢谢您<3。
答案1
- Ctrl+H
- 找什么:
^((.*?:).+\R)(\2.+\R)+
- 用。。。来代替:
$1
- 查看 环绕
- 查看 正则表达式
- 取消选中
. matches newline
- Replace all
解释:
^ # beginning of line
( # start group 1
( # start group 2
.*? # 0 or more any character but newline, not greedy
: # a colon
) # end group 2
.+ # 0 or more any character but newline
\R # any kind of linebreak (i.e. \r, \n, \r\n)
) # end group 1
( # group 3, you can use (?: for non capture group
\2 # back reference to group 2 (i.e. the part before the colon)
.+ # 0 or more any character but newline
\R # any kind of linebreak (i.e. \r, \n, \r\n)
)+ # end of group 3, may appear 0 or more times
替代品:
$1 # content of group 1, the value of the first line
截图(之前):
截图(之后):