作为 bash 例程的一部分，我在终端中打印一些有关工作流程状态的消息。消息分为两部分（第 1 部分：任务开始，第 2 部分：任务完成状态）
echo -n "Dataset is being processed ! "; execution of some AWK script; echo " Processing has been COMPLETED!"
以下是 bash 中的实现，其中包含 AWK 代码的一部分：
# print pharase 1: initiation of the process
echo -n "Dataset is being rescored.. Please wait"; sleep 0.5
# this is the process: makedir for the result and execute AWK code to process input file
mkdir ${results}
# Apply the following AWK code on the directory contained input file
while read -r d; do
awk -F, '
}' "${d}_"*/target_file.csv > "${results}/"${d%%_*}".csv"
done < <(find . -maxdepth 1 -type d -name '*_*_*' | awk -F '[_/]' '!seen[$2]++ {print $2}')
# print pharase 2: finish of the result, which would appear in the terminal near phrase 1
# this will print "COMPLETED" letter-by-letter with the pause of 0.2 sec between each letter
echo -n " C"; sleep 0.2; echo -n "O"; sleep 0.2; echo -n "M"; sleep 0.2; echo -n "P"; sleep 0.2; echo -n "L"; echo -n "E"; sleep 0.2; echo -n "T"; echo -n "E"; sleep 0.2; echo "D!"
在 bash 中执行此脚本时，一切似乎都正常，我没有注意到与两个“echo -n”块之间的代码部分相关的任何问题。使用“echo -n”对状态短语进行这种分割可能会导致 bash 中的例程出现一些错误吗？