我想知道我将如何去做
printf "Credentials found!"
当找到多个凭据时仅一次。
Attempting Dictionary Attack on 192.168.91.130
Credentials Found!
Log into the telnet server by running telnet -l admin 192.168.91.130
When prompted enter the password found 'admin'
Credentials Found!
Log into the telnet server by running telnet -l sfx 192.168.91.130
When prompted enter the password found 'toor'
循环bash
:
for i in "${!user[@]}"; do
printf "The Username & Password is %s : %s\n\n" "${user[i]}" "${pass[i]}" >> SSH-Credentials.txt
printf "${NCB}Credentials Found!${NC}\n\n"
printf "Log into the SSH server by running ${YELLOW}ssh ${user[i]}@$ip${NC}\n\nWhen prompted enter the password found ${YELLOW}'${pass[i]}'\n"
printf "${NC}\n"
done
答案1
$i
您可以进行如下测试:
[[ "$i" -lt 1 ]] && printf "I am only printed once\n"
# OR
(( i < 1 )) && printf "I am only printed once\n"
# OR
! (( i )) && printf "I am only printed once\n"
# OR
[ "$i" -lt 1 ] && printf "I am only printed once\n"
# OR
if [[ "$i" -lt 1 ]]; then
printf "I am only printed once\n"
fi
假设你不使用关联 bash 数组。
简而言之:如果索引小于 1,则打印。
为了便于阅读,我也会分解这些行。路宽。请注意,您还可以说:
printf '%s %s some long text' \
"$var1" "$var2"
使用大写字母表示变量也是一个坏习惯。
信息通常还应打印在stderr
, 所以>&2
。
还会使用:
prinf '%s@%s' "${user[i]}" "$ip" >&2
代替:
prinf "${user[i]}@$ip" >&2
答案2
user
如果数组中有元素,则输出标头。
if [[ ${#user[@]} -gt 0 ]]; then
printf '%sCredentials Found!%s\n\n' "$NCB" "$NC"
fi
然后做你的循环。
for i in "${!user[@]}"; do
printf 'The Username & Password is %s : %s\n\n' "${user[i]}" "${pass[i]}" >> SSH-Credentials.txt
cat <<END_MESSAGE
Log into the SSH server using ${YELLOW}ssh ${user[i]}@$ip$NC
When prompted, enter the password found: ${YELLOW}${pass[i]}$NC
END_MESSAGE
done