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korn shell 将 for 循环输出“值”存储在数组中并传递到另一个循环

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korn shell 将 for 循环输出“值”存储在数组中并传递到另一个循环

需要 korn shell 中数组的帮助。我需要将值从第一个 for 循环传递到第二个循环。

第一个循环返回 /opt/IBM/db2/V11.5 /opt/IBM/db2/V11.5.8 /opt/IBM/db2/V11.5.8

然后我很欣赏“uniq”价值观。所以我想传递以下 uniq 值 /opt/IBM/db2/V11.5 /opt/IBM/db2/V11.5.8

但是，我的脚本只传递最后一个值。任何帮助都会很棒。

db2instance=`ps -eaf | grep db2sysc |grep -v grep | awk '{print $1}' | sort`
for instance in ${db2instance}; do
       set -A db2dirpath
       db2dirpath=$(su - $instance -c db2level| grep "Product is installed at" | awk '{print $5}' | sed 's/"//g' | sed 's/.$//')
do
DIRDB2=$(echo ${db2dirpath[@]} | uniq)
for db2dir in "${DIRDB2[@]}"
do
      su - $instance -c "/db/data1/Ansible/db2dirpath.sh $instance $db2dir"
done

答案1

我能够解决这个问题。下面是正在运行的代码。

db2instance=`ps -eaf | grep db2sysc |grep -v grep | awk '{print $1}' | sort`

DIRDB2=$(
for instance in ${db2instance}; do
      db2dirpath=$(su - $instance -c db2level| grep "Product is installed at" | awk '{print $5}' | sed 's/"//g' | sed 's/.$//')
      echo "$db2dirpath"
done
)
DIRPATH=$(echo "$DIRDB2" | sort -u | uniq)
for db2dir in $DIRPATH
do
      su - $instance -c "/db/data1/Ansible/db2dirpath.sh $db2dir"
done

答案2

由于OP似乎不愿意回答澄清问题，这只是一个猜测。

# get a list of usernames that are running db2sysc. No need to sort them
# Assumption is the user names don't have unusual characters in them.
db2instance=$(ps -eaf | awk '/db2sys[c]/ {print $1}')
# set up an associative array to map dirpath to user name.
# probably should be called dpbath2user
typeset -A db2dirpath
# Loop over the usernames. Use associate array so we only record each
# db path once in the array.
for instance in ${db2instance}; do
       db2dirpath[$(su - $instance -c db2level| awk '/Product is installed a[t]/" {print $5}' | sed 's/"//g;s/.$//')]=$instance
done
# Loop over the paths
for db2dir in "${!db2dirpath[@]}"
do
      # process the path with the correct user name
      su - ${db2dirpath[db2dir]} -c "/db/data1/Ansible/db2dirpath.sh $instance $db2dir"
done

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