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hyperref 包的宏，以便它返回的结果像 1-3,5-7,9,11-12，而不是 1,2,3,5,6,7,9,11,12

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hyperref 包的宏，以便它返回的结果像 1-3,5-7,9,11-12，而不是 1,2,3,5,6,7,9,11,12

我想要请求您就以下问题提供协助： 使用 hyperref 包后，我的参考书目中出现了许多反向引用，如 1,1,1,2,2,3,5,8,9,10,11,11,11,12,12,13,17,19 现在我想编写一个宏将此结果转换为： if Kind = 0 1-3,5,8-13,17,19 if Kind = 1 1,3;2,2;3;5;8;9;10;11,3;12,2;13;17;19 其中 Kind 是一个变量，可根据您的选择采用特定的布局 当我运行文件 PROBEERTEST.TEX 时，上面的例子是正确的，但下面的例子前面有很多“我假设有空格”（我尝试在每一行后添加 % 并删除所有空格，但仍然会出现这些空格）。有人能帮助我吗（我希望 aa 后面立即跟着结果，而不是后面跟着这个空闲的房间）

  • 文件探测器.TEX *

     % To turn 1,1,1,2,2,3,5,8,9,10,11,11,11,12,12,13,17,19 into
 %         1-3,5,8-13,17,19 if Kind = 0
 % To turn 1,1,1,2,2,3,5,8,9,10,11,11,11,12,12,13,17,19 into
 %         1,3;2,2;3;5;8;9;10;11,3;12,2;13;17;19 if Kind = 1
 % Based on TeX by Topic p 105

\newcount\Kind % 0: like 1--3,5,7,10--12,
       % 1: like 1,2;3,2;number,# of number; 
\newcount\CountP % Previous
\newcount\CountN % Next
\newcount\CountT % Temp
\newcount\CTimes % Number of times 
\newcount\State % 3: using kind=1 after reading in
                %    first element (state=2)
                % 2: start, first element printed
                % 1: during {--}.
                % 0: otherwise (non-sequential)
\CountP=-10000
\CTimes=0
\Kind=0

% --- begin TO STORE THE RESULT 

\def\ResultDef{} % def to hold the result

% USING DEF TO STORE THE RESULT

\def\addToResultDef#1{
\edef\ResultDef{\ResultDef #1}
}

\def\printResultDef{
\ResultDef
}

% --- end TO STORE THE RESULT

\def\Combine#1{\xCombine#1,xxx, 
\printResultDef
\CountP=-10000
\CTimes=0
\def\ResultDef{}
}   

\def\endpiece{xxx}

\def\xCombine#1,{\def\temp{#1}
\ifx\temp\endpiece
  \advance \CountN by 3 % to process the last element
  \Process{\the\CountN}
\else \Process{#1} 
      \expandafter \xCombine 
\fi}

\def\Process#1{
\CountN=#1
\ifnum\CountP=-10000
  \CountP=\CountN
  \State=2
  \advance \CTimes by 1
  %\the\CountP
  \addToResultDef{\the\CountP}
\else
  \ifnum\CountP=\CountN
     \advance \CTimes by 1
  \else             % \CountP<\CountN
     \ifnum\Kind=0     
        \ProcessA{#1} 
     \else
        \ProcessB{#1} 
     \fi
     \CTimes=1
     \CountP=\CountN
  \fi
\fi
}

\def\ProcessA#1{ % \Kind=0
\CountT=\CountP
\advance\CountT by 1
\ifnum\CountN=\CountT
  \ifnum\State=0
    %\the\CountP
    \addToResultDef{,\the\CountP}
  \fi
  \State=1
\else
  \ifnum\State=0
    %, \the\CountP
    \addToResultDef{,\the\CountP}
  \else
    \ifnum\State=1
       %{--} \the\CountP
       \addToResultDef{{--}\the\CountP}
       \State=0
    \else 
      \ifnum\State=2
        \State=0
      \else
        \typeout{Invalid State!!}
      \fi
    \fi
  \fi
\fi
}

\def\ProcessB#1{ % \Kind=1
 \ifnum\State=2
    \ifnum\CTimes=1
    \else
      \addToResultDef{,\the\CTimes}
    \fi
    \State=3
 \else % State=3
    \ifnum\CTimes=1
      \addToResultDef{;\the\CountP}
    \else
      \addToResultDef{;\the\CountP,\the\CTimes}
    \fi
 \fi
}

  • 文件 PROBEERTEST.TEX *

    %% To test probeer.tex in TeX itself to see if it works accordonly
\magnification\magstep1
\hsize 5.5 true in
\hoffset 0.5 true in
\vsize 8.25 true in
\voffset = 2\baselineskip
\vbadness11000

\input probeer

\noindent 1,1,1,2,3,4,5,6,7,11,12,13,15,17 \hfill \break 
becomes \hfill \break
\Combine{1,1,1,2,3,4,5,6,7,11,12,13,15,17} \hfill \break
\hfill

\noindent New attempt: \hfill \break
1,2,3,4,5,6,7,11,12,12,13,15,17,17,21,22,23 \hfill \break  
becomes \hfill \break 
\Combine{1,2,3,4,5,6,7,11,12,12,13,15,17,17,21,22,23} \hfill \break
\hfill

\vbox{
\hbox to \hsize{1,2,3,4,5,5,6,7,11,12,13,15,17,21,22,23 \hfill}
\hbox to \hsize {becomes \hfill}
\hbox to \hsize{aa\Combine{1,2,3,4,5,5,6,7,11,12,13,15,17,21,22,23}bb \hfill}
\vfill}

\bye

答案1

每个非宏，特别是宏定义内部的宏{或}后面跟着换行符的宏都会创建一个空格。

如果你不相信那些人有责任，你可以把

\endlinechar=-1

在文件顶部

\endlinechar=13

在底部恢复到之前的行为。在这种情况下，您必须注意“反向”问题：您有几个数字实际上在该行末尾正确终止，但不再如此。您可以通过编写类似

\ifnum\State=1 %

即使关闭了行末字符，注释符号前的空格仍然可见。

不过我不得不同意 wasteofspace 的评论：这个组合超链接应该指向哪里并不明显。

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