这是我的代码:
\documentclass{article}
\usepackage[paperheight=6\baselineskip]{geometry}% just for the example
\usepackage{algorithm}
\usepackage{algcompatible}
\begin{document}
\begin{algorithm}[H]
\caption{My algo}
\begin{algorithmic}[1]
\STATE instruction 1
\STATE instruction 2
\algstore{testcont}
\end{algorithmic}
\end{algorithm}
\begin{algorithm}[H]
\caption{My algo - Part 2}
\begin{algorithmic}[1]
\algrestore{testcont}
\STATE instruction 3
\STATE instruction 4
\end{algorithmic}
\end{algorithm}
\end{document}
它显示:
Algorithm1 My algo and Algorithm2 My algo - Part 2
请问我怎样才能获得:
Algorithm1 My algo and Algorithm1 My algo - Part 2
无增量?
谢谢
答案1
使用
\begin{algorithm}[H]
\caption{My algo}
\begin{algorithmic}[1]
\STATE instruction 1
\STATE instruction 2
\algstore{testcont}
\end{algorithmic}
\addtocounter{algorithm}{-1}%% <===
\end{algorithm}
对于第一个算法
答案2
从包\ContinuedFloat
中caption
您还可以获得持续的行编号。
\documentclass{article}
\usepackage{algorithm}
\usepackage{algcompatible}
\usepackage{caption}
\begin{document}
\begin{algorithm}
\caption{My algo}
\begin{algorithmic}[1]
\STATE instruction 1
\STATE instruction 2
\algstore{testcont}
\end{algorithmic}
\end{algorithm}
\begin{algorithm}
\ContinuedFloat
\caption{My algo - Part 2}
\begin{algorithmic}[1]
\algrestore{testcont}
\STATE instruction 3
\STATE instruction 4
\end{algorithmic}
\end{algorithm}
\end{document}