电阻状符号中的多部分节点/锚点已被水平分割

Question 1

定义节点形状时会遇到一些问题：

您不能使用 TikZ，您需要使用 PGF。
PGF 区分已保存的锚点和其他锚点，这些锚点的位置将根据已保存的锚点和/或已保存的尺寸和/或已保存的宏进行计算。在计算这些其他锚点的位置时，您不能使用minimum width或之类的值\pgflinewidth来计算某些东西。它们会发生变化（想象一个thick节点，但thin会连接该节点的一条线）。
所有坐标都将位于其节点的特殊本地坐标系中（这是一件好事，创建节点时将保存变换）。其原点位于基线的左点（锚点所在的位置.text）。

让我们看一个基本形状，（rectangle）pgfmoduleshapes.code.tex。由于您的形状基于它，因此它的工作将有助于理解我稍后将进行的调整。

形状rectangle仅定义两个锚点：\northeast和\southwest。它们的定义（以开头\savedanchor）非常相似。它们计算节点的最小尺寸，这包括本身的尺寸\pgfnodeparttextbox（它是第一个且几乎是唯一的节点部分的始终存在的框）。

如果这些尺寸小于键的值minimum width，则minimum height它们将被设置为这些。

然后计算锚点的实际坐标。节点的中心始终位于文本框的中心。在定义的末尾，\pgf@x应该\pgf@y保持正确的尺寸。此后，其他一切都会丢失，需要再次计算。（\pgf@x并存\pgf@y活下来，但我不会依赖它。）

的形状定义rectangle包含许多形式的锚点定义\anchor{<name of anchor>}{<definition>}。这些是使用时将首先计算的锚点。在形状中，rectangle它们仅依赖于已保存的锚点\northeast和\southwest以及一些基本的给定事实，例如基线在是= 0。

路径和锚点边框的定义是完全不同的主题，这里不作讨论。（我们还将在形状定义中定义锚点\northeast，以便我们可以再次继承所有内容，我们也可以继承背景路径和锚点边框。）\southwestrectangle

多部分节点还有一些附加规则：

每个节点部分都需要自己的 TeX 框。

它们以前（我猜是在旧版本的 TikZ 中）被称为\pgfnodepartsecondbox、\…third…，\…fourth…但后来改为…two…、…three…、…four…。该rectangle split形状甚至可以处理多达 20 个盒子/部件。

家庭circle split也定义了lower盒子。

线条
```
\let\pgfnodeparttrbox\pgfnodeparttwobox
\let\pgfnodepartblbox\pgfnodepartthreebox
\let\pgfnodepartbrbox\pgfnodepartfourbox
```
不要声明新的框，而只是“镜像”这些框名称。我们可以使用可能在链接案例中更受欢迎的\nodepart{tr}名称。\nodepart{two}

以同样的方式…second…和…two…链接起来。
每个节点部分都需要它的锚点！

第一个节点部分 ( text= one) 已经在原点处具有其原始锚点，因此无需每次都定义它。它不需要是已保存的锚点，事实上，仅定义\anchor{two}{…}就足够了\pgfnodeparttwobox。（但它将是一个已保存的锚点，因为它依赖于文本框，并且通常依赖于内部分隔符等。）

shapes.multipart我们这里不需要图书馆。

\northeast正如前面所说，我们只更改和的定义\southwest，并添加的定义\textbanchor。因子\barratio将是一个已保存的宏（或者我们需要将其中一个bar宏设为已保存的锚点（如果我们不想要text center和textb center锚点，这就足够了）。由于\northeast和\southwest锚点已经包括outer xsep（我们不认为它是节点宽度的一部分），我们还将其保存在名为的宏中\outerxsep。

0和的比率1将被捕获（否则我们将执行除以零的操作）。测试某个范围（例如被认为是不安全的）可能更安全，< 0.05但我希望用户能够有所了解。;)

主要保存的锚点的定义中有很多注释，一开始就非常相似。

另请查看形状split rectangle with rounded corners我已经使用过一 \savedmacro保存一些其他宏（可用作锚点）。如果所有保存的值（宏、尺寸、锚点）都依赖于共同的因子/值，这将非常有用。

circuits正如您所注意到的，在路径上使用形状时，没有直接的方法可以通过库设置实际的节点内容to。但是，我们可以修补circuit handle symbol每次使用符号时内部使用的键。该etoolbox包帮助我们完成此修补，而无需再次编写整个定义。被\patchcmd使用了三次，替换{}为{\tikz@lib@circ@Text}而Text键被设置为设置\tikz@lib@circ@Text。（小写text键已用于设置节点文本的颜色。）

由于库默认circuits安装了一个内部 sep ，我们可以将其恢复为默认值，将其设置为键的值。我们现在可以在路径上使用形状和：0.5pt.333emset symbol graphicTextto

\draw (0,0) to [symbol={symbol shape ratio=.2,Text=B \nodepart{textb} C}] (6,0);

代码

\documentclass[tikz,convert=false]{standalone}
\usetikzlibrary{circuits,circuits.ee.IEC}
\usepackage{etoolbox}
\makeatletter
\tikzset{Text/.code=\def\tikz@lib@circ@Text{#1}}
\expandafter\patchcmd\csname pgfk@/tikz/circuit handle symbol/.@cmd\endcsname
 {{}}{{\tikz@lib@circ@Text}}{}{}
\expandafter\patchcmd\csname pgfk@/tikz/circuit handle symbol/.@cmd\endcsname
 {{}}{{\tikz@lib@circ@Text}}{}{}
\expandafter\patchcmd\csname pgfk@/tikz/circuit handle symbol/.@cmd\endcsname
 {{}}{{\tikz@lib@circ@Text}}{}{}
\tikzset{
  circuit declare symbol=symbol,
  set symbol graphic={
    shape=symbol shape,
    draw,
    transform shape,
    circuit symbol size=width 14 height 2,
    inner sep=+.3333em
  }
}
%% We need a box for the second node part. We could use a possibly already existing 'lower' or 'two' here but let's use our own:
\newbox\pgfnodeparttextbbox

\pgfkeys{/pgf/symbol shape ratio/.initial=.5}
\pgfdeclareshape{symbol shape}{%
  \nodeparts{text,textb}% needed
  % Let's start with saving the '\barratio'
  \savedmacro\barratio{%
    \pgfmathsetmacro\barratio{\pgfkeysvalueof{/pgf/symbol shape ratio}}%
  }
  \saveddimen\outerxsep{%
    \pgfmathsetlength\pgf@x{\pgfkeysvalueof{/pgf/outer xsep}}%
  }
  \savedanchor\southwest{%
    \pgfmathsetlength\pgf@xc{\pgfkeysvalueof{/pgf/inner xsep}}%
    \pgfmathsetlength\pgf@yc{\pgfkeysvalueof{/pgf/inner ysep}}%
    %
    % We start with calculating the minimal width with text boxes
    %
    % First: Include the inner xseps
    \pgf@xa=\wd\pgfnodeparttextbox
    \advance\pgf@xa by 2\pgf@xc
    \pgf@xb=\wd\pgfnodeparttextbbox
    \advance\pgf@xb by 2\pgf@xc
    \ifdim\barratio pt=0pt\relax
      \pgf@xa=0pt%
    \else
      \pgfmathsetlength\pgf@xa{\pgf@xa/\barratio}% calculate the horizontal dimension for the total shape if nodepart one would be dominant
    \fi
    \ifdim\barratio pt=1pt\relax
      \pgf@xb=0pt
    \else
      \pgfmathsetlength\pgf@xb{\pgf@xb/(1-\barratio)}% same for the second node part
    \fi
    % Which one is dominant? \pgf@xa will hold the horizontal dimension of the node
    \ifdim\pgf@xa<\pgf@xb
      \pgf@xa\pgf@xb
    \fi
    \pgfmathsetlength\pgf@xb{\pgfkeysvalueof{/pgf/minimum width}}%
    \ifdim\pgf@xa<\pgf@xb % oh minimum width was greater anyway
      \pgf@xa=\pgf@xb
    \fi
    % So, \pgf@xa holds the final width.
    % Where now lies the most left vertical line (and thus the x value of the south west anchor)?
    % Well it lies at (<width of first node part>-<final width>*<bar ratio>)/2
    \pgf@x=\wd\pgfnodeparttextbox
    \advance\pgf@x by -\barratio\pgf@xa
    \pgf@x=.5\pgf@x
    \pgfmathsetlength\pgf@xa{\pgfkeysvalueof{/pgf/outer xsep}}%
    \advance\pgf@x by -\pgf@xa
    %
    %
    % Now the height, that's easier, we just check the maximum of the depths and the heights of the nodeparts
    %
    \pgf@ya=\dp\pgfnodeparttextbox
    \pgf@yb=\dp\pgfnodeparttextbbox
    \ifdim\pgf@ya<\pgf@yb
      \pgf@ya=\pgf@yb
    \fi
    \pgf@yb=\ht\pgfnodeparttextbox
    \ifdim\pgf@yb<\ht\pgfnodeparttextbbox
      \pgf@yb=\ht\pgfnodeparttextbbox
    \fi
    \advance\pgf@ya by \pgf@yb
    \advance\pgf@ya by 2\pgf@yc
    \pgfmathsetlength\pgf@yb{\pgfkeysvalueof{/pgf/minimum height}}%
    \ifdim\pgf@ya<\pgf@yb
      \pgf@ya=\pgf@yb
    \fi
    % So, \pgf@ya holds the final height.
    \pgf@y=-.5\pgf@ya
    \pgf@ya=\dp\pgfnodeparttextbox
    \pgf@yb=\dp\pgfnodeparttextbbox
    \ifdim\pgf@ya>\pgf@yb
      \advance\pgf@y by -.5\pgf@ya
    \else
      \advance\pgf@y by -.5\pgf@yb
    \fi
    \pgf@yb=\ht\pgfnodeparttextbox
    \ifdim\pgf@yb>\ht\pgfnodeparttextbbox
      \advance\pgf@y by .5\pgf@yb
    \else
      \advance\pgf@y by .5\ht\pgfnodeparttextbox
    \fi
    \pgfmathsetlength\pgf@ya{\pgfkeysvalueof{/pgf/outer ysep}}%
    \advance\pgf@y by -\pgf@ya
  }
  \savedanchor\northeast{%
    \pgfmathsetlength\pgf@xc{\pgfkeysvalueof{/pgf/inner xsep}}%
    \pgfmathsetlength\pgf@yc{\pgfkeysvalueof{/pgf/inner ysep}}%
    %
    % We start with calculating the minimal width with text boxes
    %
    % First: Include the inner xseps
    \pgf@xa=\wd\pgfnodeparttextbox
    \advance\pgf@xa by 2\pgf@xc
    \pgf@xb=\wd\pgfnodeparttextbbox
    \advance\pgf@xb by 2\pgf@xc
    \ifdim\barratio pt=0pt\relax
      \pgf@xa=0pt%
    \else
      \pgfmathsetlength\pgf@xa{\pgf@xa/\barratio}% calculate the horizontal dimension for the total shape if nodepart one would be dominant
    \fi
    \ifdim\barratio pt=1pt\relax
      \pgf@xb=0pt
    \else
      \pgfmathsetlength\pgf@xb{\pgf@xb/(1-\barratio)}% same for the second node part
    \fi
    % Which one is dominant? \pgf@xa will hold the horizontal dimension of the node
    \ifdim\pgf@xa<\pgf@xb
      \pgf@xa\pgf@xb
    \fi
    \pgfmathsetlength\pgf@xb{\pgfkeysvalueof{/pgf/minimum width}}%
    \ifdim\pgf@xa<\pgf@xb % oh minimum width was greater anyway
      \pgf@xa\pgf@xb
    \fi
    % So, \pgf@xa holds the final width.
    % Where now lies the most right vertical line (and thus the x value of the north east anchor)?
    \pgf@x=\wd\pgfnodeparttextbox
    \advance\pgf@x by \barratio\pgf@xa
    \pgf@x=.5\pgf@x
    \pgfutil@tempdima=-\barratio pt
    \advance\pgfutil@tempdima by 1pt\relax
    \advance\pgf@x by \pgfmath@tonumber\pgfutil@tempdima\pgf@xa
    \pgfmathsetlength\pgf@xa{\pgfkeysvalueof{/pgf/outer xsep}}%
    \advance\pgf@x by \pgf@xa
    %
    %
    % Now the height, that's easier, we just check the maximum of the depths and the heights of the nodeparts
    %
    \pgf@ya=\dp\pgfnodeparttextbox
    \pgf@yb=\dp\pgfnodeparttextbbox
    \ifdim\pgf@ya<\pgf@yb
      \pgf@ya=\pgf@yb
    \fi
    \pgf@yb=\ht\pgfnodeparttextbox
    \ifdim\pgf@yb<\ht\pgfnodeparttextbbox
      \pgf@yb=\ht\pgfnodeparttextbbox
    \fi
    \advance\pgf@ya by \pgf@yb
    \advance\pgf@ya by 2\pgf@yc
    \pgfmathsetlength\pgf@yb{\pgfkeysvalueof{/pgf/minimum height}}%
    \ifdim\pgf@ya<\pgf@yb
      \pgf@ya=\pgf@yb
    \fi
    % So, \pgf@ya holds the final height.
    \pgf@y=.5\pgf@ya
    \pgf@ya=\dp\pgfnodeparttextbox
    \pgf@yb=\dp\pgfnodeparttextbbox
    \ifdim\pgf@ya>\pgf@yb
      \advance\pgf@y by -.5\pgf@ya
    \else
      \advance\pgf@y by -.5\pgf@yb
    \fi
    \pgf@yb=\ht\pgfnodeparttextbox
    \ifdim\pgf@yb>\ht\pgfnodeparttextbbox
      \advance\pgf@y by .5\pgf@yb
    \else
      \advance\pgf@y by .5\ht\pgfnodeparttextbox
    \fi
    \pgfmathsetlength\pgf@ya{\pgfkeysvalueof{/pgf/outer ysep}}%
    \advance\pgf@y by \pgf@ya
  }
  \savedanchor\textbanchor{%
    \pgfmathsetlength\pgf@xc{\pgfkeysvalueof{/pgf/inner xsep}}%
    %
    % We start with calculating the minimal width with text boxes
    %
    % First: Include the inner xseps
    \pgf@xa=\wd\pgfnodeparttextbox
    \advance\pgf@xa by 2\pgf@xc
    \pgf@xb=\wd\pgfnodeparttextbbox
    \advance\pgf@xb by 2\pgf@xc
    \ifdim\barratio pt=0pt\relax
      \pgf@xa=0pt%
    \else
      \pgfmathsetlength\pgf@xa{\pgf@xa/\barratio}% calculate the horizontal dimension for the total shape if nodepart one would be dominant
    \fi
    \ifdim\barratio pt=1pt\relax
      \pgf@xb=0pt
    \else
      \pgfmathsetlength\pgf@xb{\pgf@xb/(1-\barratio)}% same for the second node part
    \fi
    % Which one is dominant? \pgf@xa will hold the horizontal dimension of the node
    \ifdim\pgf@xa<\pgf@xb
      \pgf@xa\pgf@xb
    \fi
    \pgfmathsetlength\pgf@xb{\pgfkeysvalueof{/pgf/minimum width}}%
    \ifdim\pgf@xa<\pgf@xb % oh minimum width was greater anyway
      \pgf@xa\pgf@xb
    \fi
    % So, \pgf@xa holds the final width.
    % Where now lies the most right vertical line (and thus the x value of the north east anchor)?
%    % Well it lies at (<width of first node part>-<final width>*<bar ratio>)/2
    \pgf@x=\wd\pgfnodeparttextbox
    \advance\pgf@x by \barratio\pgf@xa
    \pgf@x=.5\pgf@x
    \pgfutil@tempdima=-\barratio pt
    \pgfutil@tempdima=.5\pgfutil@tempdima
    \advance\pgfutil@tempdima by .5pt\relax
    \advance\pgf@x by \pgfmath@tonumber\pgfutil@tempdima\pgf@xa
    \advance\pgf@x by -.5\wd\pgfnodeparttextbbox
    %
    \pgf@y=0pt
  }

%  \inheritsavedanchors[from=rectangle ee]
  \inheritanchor[from=rectangle ee]{center}
  \inheritanchor[from=rectangle ee]{north}
  \inheritanchor[from=rectangle ee]{south}
  \inheritanchor[from=rectangle ee]{east}
  \inheritanchor[from=rectangle ee]{west}
  \inheritanchor[from=rectangle ee]{north east}
  \inheritanchor[from=rectangle ee]{north west}
  \inheritanchor[from=rectangle ee]{south east}
  \inheritanchor[from=rectangle ee]{south west}
  \inheritanchor[from=rectangle ee]{input}
  \inheritanchor[from=rectangle ee]{output}
  \inheritanchor[from=rectangle ee]{mid east}
  \inheritanchor[from=rectangle ee]{mid west}
  \inheritanchor[from=rectangle ee]{mid}
  \inheritanchor[from=rectangle ee]{base west}
  \inheritanchor[from=rectangle ee]{base east}
  \inheritanchor[from=rectangle ee]{base}
  \anchor{bar north}{%
    \pgf@process{\pgfpointadd{\southwest}{\pgfqpoint{\outerxsep}{0pt}}}%
    \pgf@xa\pgf@x
    \pgf@process{\pgfpointadd{\northeast}{\pgfpointscale{-1}{\pgfqpoint{\outerxsep}{0pt}}}}%
    \advance\pgf@x-\pgf@xa
    \advance\pgf@xa\barratio\pgf@x
    \pgf@x\pgf@xa
  }
  \anchor{bar south}{%
    \pgf@process{\pgfpointadd{\southwest}{\pgfqpoint{\outerxsep}{0pt}}}%
    \pgf@xa\pgf@x\pgf@ya\pgf@y
    \pgf@process{\pgfpointadd{\northeast}{\pgfpointscale{-1}{\pgfqpoint{\outerxsep}{0pt}}}}%
    \advance\pgf@x-\pgf@xa
    \advance\pgf@xa\barratio\pgf@x
    \pgf@x\pgf@xa
    \pgf@y\pgf@ya
  }
  \anchor{bar center}{%
    \pgf@process{\pgfpointadd{\southwest}{\pgfqpoint{\outerxsep}{0pt}}}%
    \pgf@xa\pgf@x\[email protected]\pgf@y
    \pgf@process{\pgfpointadd{\northeast}{\pgfpointscale{-1}{\pgfqpoint{\outerxsep}{0pt}}}}%
    \advance\pgf@x-\pgf@xa\[email protected]\pgf@y
    \advance\pgf@xa\barratio\pgf@x
    \pgf@x\pgf@xa
    \advance\pgf@y\pgf@ya
  }
  \anchor{textb}{\textbanchor}% anchor for textb
  \anchor{text west}{\pgf@sh@reanchor{symbol shape}{west}}
  \anchor{textb east}{\pgf@sh@reanchor{symbol shape}{east}}
  \anchor{text east}{\pgf@sh@reanchor{symbol shape}{bar center}}
  \anchor{textb west}{\pgf@sh@reanchor{symbol shape}{bar center}}
  \anchor{text center}{%
    \southwest
    \pgf@xa\pgf@x
    \advance\pgf@xa\outerxsep
    \pgf@process{\pgf@sh@reanchor{symbol shape}{bar center}}%
    \[email protected]\pgf@x
    \advance\[email protected]\pgf@xa
  }
  \anchor{text base}{\pgf@sh@reanchor{symbol shape}{text center}\pgf@y=0pt}
  \anchor{textb center}{%
    \northeast
    \pgf@xa\pgf@x
    \advance\pgf@xa-\outerxsep
    \pgf@process{\pgf@sh@reanchor{symbol shape}{bar center}}%
    \[email protected]\pgf@x
    \advance\[email protected]\pgf@xa
  }
  \anchor{textb base}{\pgf@sh@reanchor{symbol shape}{textb center}\pgf@y=0pt}
  \inheritanchorborder[from=rectangle ee]
  \inheritbackgroundpath[from=rectangle ee]
  \beforebackgroundpath{%
    \pgf@process{\pgfpointadd{\southwest}{\pgfpoint{\outerxsep}{\pgfkeysvalueof{/pgf/outer ysep}}}}%
    \pgf@xa\pgf@x\pgf@ya\pgf@y
    \pgf@process{\pgfpointadd{\northeast}{\pgfpointscale{-1}{\pgfpoint{\outerxsep}{\pgfkeysvalueof{/pgf/outer ysep}}}}}%
    \pgf@xb\pgf@x\pgf@yb\pgf@y
    % The center point: c = .5 * (a + b)
%     \[email protected]\pgf@xb
%     \advance\pgf@xc+.5\pgf@xa
%     \[email protected]\pgf@yb
%     \advance\pgf@yc+.5\pgf@ya
    % we don't want to overdraw lines and subtract/add half the line width (not affected by outer seps)
%     \pgfutil@tempdima\pgf@xa
%     \advance\[email protected]\pgflinewidth
%     \[email protected]\pgf@xc
%     \advance\[email protected]\pgf@xa
%     \pgfpathmoveto{\pgfqpoint{\pgfutil@tempdima}{\pgf@yc}}%
%     \pgfpathlineto{\pgfqpoint{\pgfutil@tempdimb}{\pgf@yc}}%
%     \pgfutil@tempdima\pgf@xb
%     \advance\pgfutil@tempdima+.5\pgflinewidth
%     \[email protected]\pgf@xc
%     \advance\[email protected]\pgf@xb
%     \pgfpathmoveto{\pgfqpoint{\pgfutil@tempdima}{\pgf@yc}}%
%     \pgfpathlineto{\pgfqpoint{\pgfutil@tempdimb}{\pgf@yc}}%
    %
    \advance\pgf@xb-\pgf@xa%                                              \pgf@xb contains the width
    \advance\pgf@xa\barratio\pgf@xb%                                      left x value + ratio*width
    \advance\[email protected]\pgflinewidth
    \advance\[email protected]\pgflinewidth
    \pgfpathmoveto{\pgfqpoint{\pgf@xa}{\pgf@ya}}%
    \pgfpathlineto{\pgfqpoint{\pgf@xa}{\pgf@yb}}%
    \pgfsetbuttcap
    \pgfusepathqstroke
  }%
}
\makeatother
\tikzset{
  shape example/.style={
    color=black!30,
    draw,
    fill=yellow!30,
    line width=.5cm,
    inner xsep=2.5cm,
    inner ysep=0.5cm}
}
\begin{document}\Huge
\begin{tikzpicture}[circuit ee IEC]
\node[symbol, symbol shape ratio=.3, shape example, name=s] {A\vrule width 1pt height 2cm \nodepart{textb} \TeX t\vrule width 1pt height 2cm};
\foreach \anchor/\placement in {north west/above left, north/above, north east/above right,
                                west/left, center/above, east/right,
                                mid west/right, mid/above, mid east/left,
                                base west/left, base/below, base east/right,
                                south west/below left, south/below, south east/below right,
                                text/left, 10/right, 130/above}
  \draw[shift=(s.\anchor)] plot[mark=x] coordinates{(0,0)} node[\placement] {\scriptsize\texttt{(s.\anchor)}};
\foreach \anchor/\placement in {bar north/above, bar south/below, bar center/above,
                                text west/above, textb east/above, textb/left,
                                text east/left, textb west/right, text center/above,%
                                text base/below, textb center/above, textb base/below%
                                }
  \draw[red,shift=(s.\anchor)] plot[mark=x] coordinates{(0,0)} node[\placement] {\scriptsize\texttt{(s.\anchor)}};
\end{tikzpicture}
\begin{tikzpicture}[circuit ee IEC]
  \draw (0,0) to [symbol={symbol shape ratio=.2,Text=B \nodepart{textb} C}] (6,0);
\end{tikzpicture}
\end{document}

输出

在此处输入图片描述

Answer