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我想在 tikz 中显示以下图片，为此我编写了代码。但是缩放此图像会扭曲矩形节点的位置。在我显示的图片中，节点之间有共同的边缘。无论缩放与否，我都不希望它们扭曲。有人能给我一些解决这个问题的提示吗？

在此处输入图片描述

\documentclass{article}
\usepackage{tikz}

\begin{document}
\begin{tikzpicture}

    \node (rxst0) at (0.75,-0.5) [draw,fill=gray!20,minimum height=0.65cm,minimum width=0.5cm] {$st_0$};
    \node (rxst1) at (2.25,-0.5) [draw,fill=gray!20,minimum height=0.65cm,minimum width=0.5cm] {$st_1$};

    \node (c0pos0) at (0,0) [draw,minimum height=0.65cm,minimum width=1.0cm] {$pos_0$};
    \node (c0st0) at (0.75,0) [draw,fill=gray,minimum height=0.65cm,minimum width=0.5cm] {$st_0$};
    \node (c0pos1)  at (1.55,0) [draw,minimum height=0.65cm,minimum width=1.0cm] {$pos_1$};
    \node (c0st1) at (2.25,0) [draw,fill=gray,minimum height=0.65cm,minimum width=0.5cm] {$st_1$};
\end{tikzpicture}
\end{document}

扭曲的图像如下所示 -

在此处输入图片描述

我也尝试了类似下面的操作，但是没有效果。

\node (c0st0) [anchor=west,right of=c0pos0,node distance=0cm,draw,fill=gray,minimum height=0.65cm,minimum width=0.5cm] {$st_0$};

谢谢

答案1

不确定您理解“缩放”是什么意思。下图和代码不受缩放影响，因为位置是相对于其他节点指定的，宽度和高度以绝对单位指定：

\usetikzlibrary{positioning}

\tikzset{
  mybox/.style = {
     minimum width=#1, 
     minimum height=0.65cm, 
     inner sep=3pt, 
     draw},
  mybox/.default=0.5cm,
}

\begin{tikzpicture}[node distance=-\pgflinewidth]
\node [mybox=1cm, fill=white] (c0pos0) {$pos_0$};
\node [mybox,fill=gray,right=of c0pos0] (rxst0) {$st_0$};
\node [mybox,fill=gray!20,below=of rxst0] {$st_0$};
\node [mybox=1cm,fill=white,right=of rxst0] (c0pos1) {$pos_1$};
\node [mybox,fill=gray,right=of c0pos1] (rxst1) {$st_1$};
\node [mybox,fill=gray!20,below=of rxst1] {$st_1$};
\end{tikzpicture}

\begin{tikzpicture}[node distance=-\pgflinewidth, scale=2]
\node [mybox=1cm, fill=white] (c0pos0) {$pos_0$};
\node [mybox,fill=gray,right=of c0pos0] (rxst0) {$st_0$};
\node [mybox,fill=gray!20,below=of rxst0] {$st_0$};
\node [mybox=1cm,fill=white,right=of rxst0] (c0pos1) {$pos_1$};
\node [mybox,fill=gray,right=of c0pos1] (rxst1) {$st_1$};
\node [mybox,fill=gray!20,below=of rxst1] {$st_1$};
\end{tikzpicture}

结果

更新

根据@Ignasi 的建议（我同意），这是mybox风格的另一种定义：

\tikzset{
  mybox/.style = {
     text width=#1, 
     text centered,
     text height=4mm, 
     text depth=2.5mm,
     inner sep=3pt, 
     draw},
  mybox/.default=0.5cm,
}

使用tikzpicture与上面相同的代码，可得到以下结果：

结果2

答案2

PSTricks 解决方案：

\documentclass{article}

\usepackage{amsmath}  % for \text
\usepackage{multido}  % for \multido
\usepackage{pstricks} % for the rest of the drawing

\begin{document}

\def\blocks{2} % the number of different indices
\begin{pspicture}(\numexpr 5*\blocks,4)
\psset{dimen = middle, fillstyle = solid} % `dimen = middle` gives you perfectly overlapping rectangles as wanted
  \multido{\iA = 0+5, \iB = 0+1}{\blocks}{%
    \psframe(\iA,2)(!\iA\space 3 add 4)
    \rput(!\iA\space 1.5 add 3){\Huge $\text{pos}_{\iB}$}
    \psframe[fillcolor = black!60](!\iA\space 3 add 2)(!\iA\space 5 add 4)
    \rput(!\iA\space 4 add 3){\Huge $\text{st}_{\iB}$}
    \psframe[fillcolor = black!20](!\iA\space 3 add 0)(!\iA\space 5 add 2)
    \rput(!\iA\space 4 add 1){\Huge $\text{st}_{\iB}$}}
\end{pspicture}

\end{document}

输出

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