图表 - 重复行动

Question

我该如何画出连接箭头的线？这是我设法编写的代码，由于我是 Latex 新手，因此可能比较混乱和不整洁

\begin{center}
    $ \downarrow \linebreak
\fbox{\parbox{4 cm}{In x(n); \hspace{0.1 cm} A/D\linebreak Out x(n-1);%
\hspace{0.1 cm} D/A\linebreak x(n-1) = x(n);\hspace{00.1 cm} Shift}} \linebreak
\downarrow$
\end{center}

Answer 1

这是利用强大力量之间的奇妙互动的一种可能性tcolorbox和listings包装：

代码：

\documentclass{article}
\usepackage[many]{tcolorbox}
\tcbuselibrary{listings}

\lstset{
  basicstyle=\small\ttfamily,
  columns=fullflexible
}

\begin{document}

\begin{tcblisting}{enhanced,listing only,hbox,remember as=mycode,colframe=green!60!black,colback=white}
In x(n);        A/D
Out x(n-1);     D/A
x(n-1) = x(n);  Shift
\end{tcblisting}

\begin{tikzpicture}[remember picture,overlay,>=latex]
\draw[->]
  (mycode.south) -- ([yshift=-30pt]mycode.south);
\draw
  ([yshift=-30pt]mycode.south) -- 
  ([xshift=30pt,yshift=-30pt]mycode.south east) |-
  ([yshift=30pt]mycode.north);
\draw[->]
  ([yshift=30pt]mycode.north) -- (mycode.north);
\end{tikzpicture}

\end{document}