一行上有 2 个方框方程(蓝色轮廓框和阴影)

一行上有 2 个方框方程(蓝色轮廓框和阴影)

我目前正在尝试将 2 个带框的方程式放在同一条线上。我用它{mybox}来创建框的轮廓和颜色。同时将方程式放置在我想要的位置。框内必须有 5% 的灰色。

我有这个代码:

\documentclass[a4paper, 11pt]{report}
\usepackage{amsmath}
\usepackage{empheq}
\usepackage[framemethod=TikZ]{mdframed}
\usepackage{lipsum}
\usepackage[top=15mm, bottom=15mm, left=35mm, right=20mm]{geometry}

\newmdenv[innerlinewidth=0.5pt, roundcorner=4pt,linecolor=blue,innerleftmargin=6pt,
innerrightmargin=6pt,innertopmargin=6pt,innerbottommargin=6pt,
leftmargin=179.5pt, rightmargin=179.5pt]{mybox1}

\newmdenv[innerlinewidth=0.5pt, roundcorner=4pt,linecolor=blue,innerleftmargin=6pt,
innerrightmargin=6pt,innertopmargin=6pt,innerbottommargin=6pt,
leftmargin=179.5pt, rightmargin=179.5pt]{mybox2}

\newmdenv[innerlinewidth=0.5pt, roundcorner=4pt,linecolor=blue,innerleftmargin=6pt,
innerrightmargin=6pt,innertopmargin=6pt,innerbottommargin=6pt,
leftmargin=179.5pt, rightmargin=179.5pt]{mybox3}

\newmdenv[innerlinewidth=0.5pt, roundcorner=4pt,linecolor=blue,innerleftmargin=6pt,
innerrightmargin=6pt,innertopmargin=6pt,innerbottommargin=6pt,
leftmargin=30.5pt, rightmargin=255pt]{mybox4}

\begin{document}

    Simple linear regression relates one dependent variable to one independent variable in the form of a linear equation:

    \begin{mybox1}[backgroundcolor=gray!5, shadowsize=10pt, shadowcolor=gray]
    \begin{center}
    $y = a + bx$
    \end{center}
    \end{mybox1}

    To develop the linear equation, the intercept a and slope b must first be computed using the
    following least squares formulas:

    \begin{mybox2}
    \begin{center}
    $a = \bar{y} +  b \bar{x}$
    \end{center}
    \end{mybox2}
    and
    \begin{mybox3}
    \begin{center}
    $b = \frac{\sum{x y - n \bar{x}\ \bar{y}}}{\sum{x^2 - n \bar{x}^2}}$
    \end{center}
    \end{mybox3}

    Where:

    \begin{mybox4}
    \begin{center}
    $\bar{x} = \frac{\sum{x}}{n} = mean\ of\ x\ data$
    \end{center}
    \end{mybox4}

    We can use correlation to measure the strength of the relationship between the independent and dependent variables. The formula for the 
    correlation coefficient is:

\end{document}

在此处输入图片描述

我明白了,但我必须得到这个:

在此处输入图片描述

如您所见,我必须水平对齐方程式,为框添加阴影,并制作绿色框。提前感谢您的帮助。

答案1

这是一个tcolorbox解决方案(而不是mdframed

\tcboxmath命令可以在方程式内部使用,也可以作为独立框使用,颜色等的配置使用colframecolback等非常简单,可以tcbset在可选参数中本地使用或使用。

\documentclass{article}

\usepackage{mathtools}
\usepackage[most]{tcolorbox}

\tcbset{enhanced,colframe=blue,colback={black!5!white},drop shadow} 

\begin{document}

    Simple linear regression relates one dependent variable to one independent variable in the form of a linear equation:

    \begin{equation}
    \tcboxmath{y = a + bx}
    \end{equation}
    To develop the linear equation, the intercept a and slope b must first be computed using the
    following least squares formulas:

    \begin{equation}
    \tcboxmath{%
      a = \bar{y} +  b \bar{x}
    }
    \text{ and }
    \tcboxmath{%
      b = \frac{\sum{x y - n \bar{x}\ \bar{y}}}{\sum{x^2 - n \bar{x}^2}}
    }
    \end{equation}

    Where:

    \begin{equation}
      \tcboxmath[colframe=green]{%
        \bar{x} = \frac{\sum{x}}{n} = \text{mean\ of\ x\ data}
        }
        \end{equation}
    We can use correlation to measure the strength of the relationship between the independent and dependent variables. The formula for the 
    correlation coefficient is:

\end{document}

在此处输入图片描述

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