使用 TeX 和 LaTeX 相关的工具和包，您将如何绘制火鸡、南瓜派、山核桃派、肉汁船或任何其他传统上与感恩节相关的物品？
答案1
需要生动的想象力...
\documentclass{article}
\usepackage{stackengine,graphicx,xcolor}
\begin{document}
Turkey?\quad
\sffamily\color{brown!80!black}
\stackinset{c}{-4.8pt}{c}{5pt}{\color{brown}\LARGE Y}{%
\stackinset{c}{0pt}{c}{-1pt}{\scalebox{1.2}{\color{orange}\LARGE e}}{%
\stackinset{c}{0.5pt}{c}{-8.5pt}{\color{yellow}K}{%
\stackinset{c}{7.5pt}{c}{4.5pt}{\color{red}\LARGE r}{%
\stackinset{c}{8.5pt}{c}{5pt}{\color{blue!50!cyan}\tiny T}{%
\Huge U%
}}}}}
\fboxsep=.5pt
\color{black}\rmfamily\raisebox{3ex}{--}\kern-.3pt%
\raisebox{3.5ex}{\fbox{\scalebox{.5}{%
\tiny\textbackslash@gobble}}}
\end{document}
第二次尝试： 南瓜派）
\documentclass{article}
\usepackage{xcolor}
\definecolor{pumpkin}{rgb}{1,0.459,0.094}
\begin{document}
\ooalign{$\pi$\cr\kern.15pt\textcolor{pumpkin}{$\pi$}}
\end{document}
答案2
这有点像自己做意大利面——麻烦多于价值。
不过，这里有一只小小的感恩节火鸡元帖子。祝你在那边度假愉快！
prologues := 3;
outputtemplate := "%j%c.eps";
beginfig(1);
u = 1cm;
color brown, light_brown, dark_brown, orange, dark_orange, gold;
brown = (159/255, 92/255, 55/255);
orange = (255/255, 170/255, 45/255);
gold = (255/255, 183/255, 11/255);
light_brown = 0.2[brown,white];
dark_brown = 0.2[brown,black];
dark_orange = 0.4[orange,red];
path body, wing, thigh, head, neck, foot, leg, feather, brim, beak, crop, eye, crown, buckle, band;
body = fullcircle scaled 2.1u;
neck = halfcircle rotated 180 scaled 0.4u shifted (0,0.2u) --
halfcircle scaled 0.4u shifted (0,1.2u) -- cycle;
head = fullcircle scaled 1.0u shifted (0,1.4u);
eye = fullcircle scaled 3 shifted center head shifted (5,2);
wing = (subpath (-0.8,1.6) of body {down} .. {curl 0} cycle) rotatedabout(point 1.6 of body,5);
leg = (origin -- (0,-2/3u)) shifted point 6.4 of body shifted 2 up;
foot = (5 down rotated -60 -- origin -- 5 down rotated 60) shifted point 0.7 of leg;
thigh = fullcircle scaled 0.32u shifted point 0 of leg;
feather = (origin {curl 0} .. (2,1/2) .. (3,0) .. (2,-1/2) .. {curl 0} cycle) scaled 1/2u;
brim = fullcircle xscaled 1.6u yscaled 1/3u shifted center head shifted 4 up;
crown = point 1/2 of head -- subpath (1.5,2.5) of brim shifted (0,5/8u) -- point 7/2 of head
.. {right} point 2 of head shifted 8 down .. cycle;
band = buildcycle( subpath (1,3) of brim,
subpath (4,3) of crown,
subpath (3,1) of brim shifted 5 up,
subpath (1,0) of crown);
buckle = (origin -- right -- (1,1) -- (-1,1) -- (-1,-1) -- (1,-1) -- right) scaled 2.4 shifted center band shifted 1/2up ;
beak = (origin -- subpath (0,1) of fullcircle rotated 142 --cycle) scaled 12 shifted center head shifted (6,-3);
crop = subpath (1,2) of beak {dir 275} .. {left} point 5.8 of head shifted 2 up .. {dir 20} point 1 of beak .. cycle;
picture whole_leg;
whole_leg = image(
draw leg withpen pencircle scaled 3 withcolor dark_orange;
draw foot withpen pencircle scaled 3 withcolor dark_orange;
fill thigh withcolor brown;
);
% feathers first
for t=-29 step 48 until 229+eps: fill feather rotated t shifted 10 up withcolor orange; endfor
for t= -5 step 48 until 205+eps: fill feather rotated t shifted 10 up withcolor dark_orange; endfor
% start hat
fill brim withcolor black;
% bird
fill body withcolor brown;
fill neck withcolor light_brown;
fill head withcolor light_brown;
fill eye withcolor 1/2[brown,black];
fill eye reflectedabout(up,down) withcolor 1/2[brown,black];
fill beak withcolor gold;
fill crop withcolor .67 red;
fill wing withcolor dark_brown;
fill wing reflectedabout(up,down) withcolor dark_brown;
draw whole_leg;
draw whole_leg reflectedabout(up,down);
% rest of hat
fill crown withcolor black;
fill band withcolor .3 white;
draw buckle withpen pencircle scaled 7/9 withcolor gold;
endfig;
end.
我应该补充一点，虽然设计不是我的，上面的实现都是我的。
答案3
我们先从原料开始吧？这是南瓜：
代码
\documentclass[tikz, border=2mm]{standalone}
\usepackage{pgfplots}
\pgfplotsset{compat=1.12, width=15cm}
\begin{document}
\pgfmathsetmacro{\RMax}{3}
\pgfmathsetmacro{\RMin}{2}
\pgfmathsetmacro{\r}{2.3}
\pgfmathsetmacro{\n}{5}
\begin{tikzpicture}
\begin{axis}
[ view={60}{30},
hide axis=true,
]
\addplot3
[ surf,
shader=interp,
samples=120,
samples y=16,
%color=orange,
opacity=1,
domain=0:360,
y domain=0:360,
z buffer=sort,
point meta={sqrt(x*x+y*y+z*z)},
colormap={pumpkin}{rgb255(0cm)=(215,102,0);rgb255(1cm)=(250,175,1);rgb255(2cm)=(255,138,32);rgb255(3cm)=(255,193,111)},
]
({(\RMin+(\RMax-\RMin)*abs(sin(\n*x))+\r*cos(y))*cos(x)}, {(\RMin+(\RMax-\RMin)*abs(sin(\n*x))+\r*cos(y))*sin(x)}, {\r*sin(y)});
\addplot3
[ surf,
shader=interp,
samples=90,
samples y=10,
opacity=1,
domain=0:360,
y domain=0.5*\RMax:1.2*\RMax,
colormap={stem}{rgb255(0cm)=(0,121,6);rgb255(1cm)=(0,191,10)},
z buffer=sort,
point meta=z,
]
({y/20*cos(x)+y/10*cos(y)},{y/20*sin(x)+y/10*sin(y)},{y});
\end{axis}
\end{tikzpicture}
\end{document}
输出
还有一个南瓜派：
代码
\begin{tikzpicture}
\begin{axis}
[ view={45}{30},
hide axis=true,
unit vector ratio=1 1 1,
]
\addplot3
[ domain=\R:1.05*\R,
y domain=45:225,
surf,
shader=interp,
point meta={z*z},
z buffer=sort,
samples=5,
samples y=180,
colormap={mantle}{rgb255(0cm)=(206,165,108);rgb255(1cm)=(163,117,54)},
]
( {x*cos(y)},
{x*sin(y)},
{ and(x>\R,x<=1.005*\R) + and(x>=\R,x<1.045*\R)*(1.05+0.05*abs(cos(10*y)))});
\addplot3
[ domain=0:\R,
y domain=0:360,
surf,
shader=interp,
point meta={cos(sqrt(x*x+y*y)/pi*180*4)},
z buffer=sort,
colormap={filling}{rgb255(0cm)=(204,97,0);rgb255(1cm)=(221,105,0)},
]
({x*cos(y)},{x*sin(y)},{1});
\addplot3
[ domain=\R:1.05*\R,
y domain=225:405,
surf,
shader=interp,
point meta={z*z},
z buffer=sort,
samples=5,
samples y=180,
colormap={mantle}{rgb255(0cm)=(206,165,108);rgb255(1cm)=(163,117,54)},
]
( {x*cos(y)},
{x*sin(y)},
{ and(x>\R,x<=1.005*\R) + and(x>=\R,x<1.045*\R)*(1.05+0.15*abs(cos(10*y)))});
\end{axis}
\end{tikzpicture}
答案4
挑剔的图形系统当然是picture模式。
\documentclass{article}
\begin{document}
\setlength{\unitlength}{3947sp}%
%
\hspace*{-100pt}\begin{picture}(7935,9057)(6076,-10606)
\thinlines
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\multiput(12076,-3136)(6.00000,6.00000){26}{\makebox(1.6667,11.6667){\tiny.}}
\put(12226,-2986){\line( 0, 1){300}}
\put(12226,-2686){\line(-1, 0){150}}
\multiput(12076,-2686)(-3.75000,-7.50000){21}{\makebox(1.6667,11.6667){\tiny.}}
}%
{\put(11701,-5236){\line(-5, 2){969.828}}
\put(10726,-4861){\line(-1, 0){600}}
\put(10126,-4861){\line(-5,-1){1197.115}}
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\put(8401,-5461){\line(-3,-2){1211.539}}
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\put(6826,-6811){\line( 3,-4){225}}
\put(7051,-7111){\line( 1,-1){225}}
\put(7276,-7336){\line( 1, 1){225}}
\multiput(7501,-7111)(2.02703,-8.10811){38}{\makebox(1.6667,11.6667){\tiny.}}
\put(7576,-7411){\line( 2,-1){300}}
\put(7876,-7561){\line( 1, 0){300}}
\multiput(8176,-7561)(1.66667,-8.33333){46}{\makebox(1.6667,11.6667){\tiny.}}
\put(8251,-7936){\line( 3,-1){225}}
\put(8476,-8011){\line( 3, 2){225}}
\multiput(8701,-7861)(1.66667,-8.33333){46}{\makebox(1.6667,11.6667){\tiny.}}
\put(8776,-8236){\line( 1, 0){300}}
\put(9076,-8236){\line( 3, 1){225}}
\multiput(9301,-8161)(2.67857,-8.03571){29}{\makebox(1.6667,11.6667){\tiny.}}
\put(9376,-8386){\line( 1, 0){375}}
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\put(12001,-5911){\line( 0, 1){450}}
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\multiput(13576,-5161)(3.75000,-7.50000){41}{\makebox(1.6667,11.6667){\tiny.}}
\put(13726,-5461){\line( 0,-1){750}}
}%
{\put(12076,-5536){\line( 6, 1){450}}
\put(12526,-5461){\line( 3, 1){450}}
}%
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}%
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\put(9826,-8686){\line(-5, 3){518.382}}
}%
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\end{picture}\hspace*{-100pt}
\end{document}