答案1
您可以将评论放在 parboxes 中。
\documentclass{article}
\usepackage{mathtools}
\begin{document}
\begin{alignat*}{2}
\lim_{x\to 1} \frac{x^2-1}{1-x} &= \lim_{x\to 1} \frac{(x-1)(x+1)}{-(x-1)} &\quad&
\parbox{160pt}{\raggedright Factoring the numerator and factoring $-1$ from the denominator.} \\
&= \lim_{x\to1}\frac{x+1}{-1}=-2, &&
\parbox{100pt}{\raggedright Simplifying and subsituting $x=1$.}
\end{alignat*}
\end{document}