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期望 bash 和退出代码中包含脚本

tag-icon • tag-icon bash exit expect
期望 bash 和退出代码中包含脚本

我有一个bash调用expect脚本的脚本。

Expect 脚本有几个条件。它通过 ssh 进入一个盒子并执行命令，并且可能会发生不同的错误，我给出了退出代码，如下所示：

expect {
    "passwd: password updated successfully" {
    exit 0
    }
    "Password unchanged" {
    exit 1
    }
    "Bad: new and old password are too similar" {
    exit 2
    }
    "You must choose a longer password" {
    exit 3
    }
}

我计划获取这些退出代码并在调用 Expect 脚本的 bash 脚本中使用它们，如下所示：

            if [ $? -eq 0 ]; then
            echo -e "\n"
            echo "Password successfully changed on $host by $user"

            elif [ $? -eq 1 ]; then
                echo "Failure, password unchanged"
            elif [ $? -eq 2 ]; then
                echo "Failure, new and old passwords are too similar"
            elif [ $? -eq 3 ]; then
                echo "Failure, password must be longer"
            else
                echo "Password failed to change on $host"
        fi

但这是行不通的。看起来expect脚本只在成功时返回0，在失败时返回1，无论在哪里失败。是否可以检索我分配的退出代码并在 bash 脚本中使用它们？

或者在期望脚本中使用“send_user”来描述错误会更好吗？如果是这样，我怎样才能让bash脚本使用expect中“send_user”命令的输出？

答案1

更简单的方法是使用case语句而不是$?重复检查：

case "$?" in
    0) echo "Password successfully changed on $host by $user" ;;
    1) echo "Failure, password unchanged" ;;
    2) echo "Failure, new and old passwords are too similar" ;;
    3) echo "Failure, password must be longer" ;;
    *) echo "Password failed to change on $host" ;;
esac

答案2

您需要将返回值初始化为临时变量。像这样：

   ./my_expect_script.expect
   a=$?
   if [ $a -eq 0 ]; then
        echo -e "\n"
        echo "Password successfully changed on $host by $user"

        elif [ $a -eq 1 ]; then
            echo "Failure, password unchanged"
        elif [ $a -eq 2 ]; then
            echo "Failure, new and old passwords are too similar"
        elif [ $a -eq 3 ]; then
            echo "Failure, password must be longer"
        else
            echo "Password failed to change on $host"
    fi

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