自定义 Beamer 框架标题

Question

如何将 beamer 框架标题更改为如下形式

到目前为止我所做的（我想要像我的代码中的背景颜色）：

\documentclass{beamer}
\usepackage{tikz}
\usetheme{CambridgeUS}

\begin{document}

\setbeamertemplate{background canvas}[vertical shading][top=red!5,bottom=blue!15]{

\begin{frame}{}

\begin{tikzpicture}[remember picture,overlay]
\node[anchor= north east,xshift=0cm,yshift=-0.8cm] at (current page.north){
     \begin{tikzpicture}[remember picture,overlay]%\tikz[overlay]
     \draw[fill=blue!15,line width=2pt] (-2,-1.3) rectangle (2,0.3);
     \draw[fill=blue!15,line width=2pt] (-1.8,-1.1) rectangle (1.8,0.1); 
     \node[] at (1,-0.2) {\Large Conclusions}; 
     \fill[color=red!5] (2.1,0.4) circle (0.6cm);
     \fill[color=red!5] (-2.1,-1.4) circle (0.6cm);
     \fill[color=red!5] (2.1,-1.3) circle (0.6cm);
     \fill[color=red!5] (-2.1,-0.1) circle (0.6cm);
    % \draw[step=.1cm,gray,very thin] (-2.5,-2.5) grid (2.5,2.5);
     \end{tikzpicture}
     };
\end{tikzpicture}


\end{frame}  
}
\end{document}

Answer 1

这样可以避免嵌套tikzpicture并\setbeamertemplate正确使用。它还为所需的设计提供了基础。调整和增强留给读者练习。

特别要注意的是，可变宽度的线条实际上并不是 TikZ 的拿手好戏。如果认为这些是必不可少的，请考虑另一种方法。（有几个答案迫使 TikZ 近似于此，但价格很高，结果永远不会完全令人满意。最好为工作选择合适的工具，并按照 TikZ 的设计用途使用它。）

\documentclass{beamer}
\usepackage{tikz}
\usetheme{CambridgeUS}
\usetikzlibrary{calc}
\usepackage[T1]{fontenc}
\DeclareRobustCommand{\zapfstyle}{%
  \fontencoding{T1}%
  \fontseries{mb}%
  \fontshape{it}%
  \fontfamily{pzc}%
  \selectfont}
\begin{document}
\setbeamertemplate{background canvas}[vertical shading][top=red!5,bottom=blue!15]
\begin{frame}{}
  \begin{tikzpicture}
    [
      remember picture,
      overlay,
      ribbon width/.store in=\ribbonwidth,
      edging width/.store in=\edgingwidth,
      edging colour/.store in=\edgingcolour,
      ribbon colour/.store in=\ribboncolour,
      ribbon width=5mm,
      edging width=1pt,
      edging colour=red!5!gray!75!blue!25,
      ribbon colour=gray!25!red!5!white,
    ]
    \node (c) [anchor=north, font=\zapfstyle\Large, inner sep=\ribbonwidth+1mm] at ([yshift=-8mm]current page.north) {Conclusions};
    \begin{scope}
      \clip ([xshift=-\ribbonwidth]c.north east) coordinate (a1) arc (180:270:\ribbonwidth) coordinate (a2) -- ([yshift=\ribbonwidth]c.south east) coordinate (a3) arc (90:180:\ribbonwidth) coordinate (a4) -- ([xshift=\ribbonwidth]c.south west) coordinate (a5) arc (0:90:\ribbonwidth) coordinate (a6) -- ([yshift=-\ribbonwidth]c.north west) coordinate (a7) arc (270:360:\ribbonwidth) coordinate (a8) -- cycle;
      \path [fill=\ribboncolour, even odd rule] (c.north east) rectangle (c.south west) ($(c.north east)+(-135:\ribbonwidth)$) coordinate (c1) rectangle ($(c.south west)+(45:\ribbonwidth)$) coordinate (c2);
      \draw [draw=\edgingcolour, opacity=.5] (c1) rectangle (c2);
    \end{scope}
    \begin{scope}
      \clip ([xshift=2.5*\edgingwidth,yshift=2.5*\edgingwidth]c.north east) rectangle  ([xshift=-2.5*\edgingwidth,yshift=-2.5*\edgingwidth]c.south west);
      \draw [draw=\edgingcolour, opacity=.75, line width=\edgingwidth] (a1) -- (a8) (a2) -- (a3) (a4) -- (a5) (a6) -- (a7) \foreach \i [count=\j, evaluate=\j as \k using 90*\j-45] in {north east, north west, south west, south east} {($(c.\i)+(\k:.5\edgingwidth)$) circle (\ribbonwidth)}  ;
    \end{scope}
  \end{tikzpicture}
\end{frame}
\end{document}