现有包中是否有一个包或宏可以计算下一个工作日或n从今天算起的第 1 个工作日(考虑到节假日列表)还是任意一个日期?(如果没有,我想我最终会编写一些代码并发布在 CTAN 上)
答案1
我不知道有哪个软件包可以做到这一切,但是日历包非常强大。以下 MWE 处理下一个工作日(假设没有整整一周的假期)
\documentclass{article}
\usepackage{pgfkeys}
\usepackage{pgfcalendar}
\usepackage{etoolbox}
\newif\ifholiday
\def\holidays{2016-09-12, 2016-09-16, 2016-09-20, 2016-09-21, 2016-09-23, 2016-09-26}
\newcount\nextjulianday
\newcount\julianholiday
\newcommand{\isholiday}[2]{%
\holidayfalse%
\def\do##1{%
\pgfcalendardatetojulian{##1}{\julianholiday}%
\ifnumequal{\the\julianholiday}{\the\nextjulianday}{\holidaytrue}{}%
}%
\docsvlist{#1}%
}
\newcommand{\nextbusinessday}[1]{\begingroup%
\pgfcalendardatetojulian{#1}{\nextjulianday}%
\advance\nextjulianday 1\relax%
\loop
\expandafter\isholiday\expandafter{\holidays}{\the\nextjulianday}%
\ifholiday%
\advance\nextjulianday 1\relax%
\repeat%
\pgfcalendarjuliantodate{\the\nextjulianday}{\theyear}{\themonth}{\theday}%
\pgfcalendarifdate{\theyear-\themonth-\theday}{Saturday}{%
\advance\nextjulianday 1\relax%
\pgfcalendarjuliantodate{\the\nextjulianday}{\theyear}{\themonth}{\theday}%
}{}%
\pgfcalendarifdate{\theyear-\themonth-\theday}{Sunday}{%
\advance\nextjulianday 1\relax%
\pgfcalendarjuliantodate{\the\nextjulianday}{\theyear}{\themonth}{\theday}%
}{}%
\loop
\expandafter\isholiday\expandafter{\holidays}{\the\nextjulianday}%
\ifholiday%
\advance\nextjulianday 1\relax%
\repeat%
\pgfcalendarjuliantodate{\the\nextjulianday}{\theyear}{\themonth}{\theday}%
\theyear-\themonth-\theday
\endgroup}
\begin{document}
Holidays:
\def\do#1{#1\par}
\expandafter\docsvlist\expandafter{\holidays}
\def\do#1{2016-09-#1 -- \nextbusinessday{2016-09-#1}\par}
\docsvlist{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30}
\end{document}
应该可以扩展该方法来处理第 n 个工作日。