公式编号的位置是自动放置的。如何选择它的位置?例如,在附图中,索引 G.13 出现在底部,我该如何将其放在第二行?我尝试使用 \nonumber,但没有成功。
代码:
\begin{equation}\begin{split}
&\widetilde{K}(x_{\perp},\, y_{\perp},\, z_{\perp},\, z_{\perp}^{\prime})\,=\,\frac{\alpha_{s}^{2}}{16\pi^{4}\left((X^{\prime})^{2}Y^{2}-X^{2}(Y^{\prime})^{2}\right)}\left(\frac{(Y^{\prime})^{2}}{Z^{2}}-\frac{(Y^{\prime})^{4}X^{2}}{(X^{\prime})^{2}Z^{2}Y^{2}}-\frac{Y^{4}(X^{\prime})^{2}}{Z^{2}X^{2}(Y^{\prime})^{2}}+\frac{Y^{2}}{Z^{2}}\right.\\
&+\frac{(X^{\prime})^{2}Y^{2}}{Z^{2}(Y^{\prime})^{2}}-\frac{X^{2}}{Z^{2}}-\frac{(X^{\prime})^{2}}{Z^{2}}+\frac{X^{2}(Y^{\prime})^{2}}{Z^{2}Y^{2}}+\frac{(X^{\prime})^{2}(X-Y)^{2}}{X^{2}Z^{2}}-\frac{(Y^{\prime})^{2}(X-Y)^{2}}{Z^{2}Y^{2}}-\frac{Y^{2}(X-Y)^{2}}{Z^{2}(Y^{\prime})^{2}}\\
&\left.+\frac{X^{2}(X-Y)^{2}}{(X^{\prime})^{2}Z^{2}}+\frac{Y^{2}(X-Y)^{2}}{X^{2}(Y^{\prime})^{2}}-\frac{(X-Y)^{2}}{(X^{\prime})^{2}}-\frac{(X-Y)^{2}}{X^{2}}+\frac{(Y^{\prime})^{2}(X-Y)^{2}}{(X^{\prime})^{2}Y^{2}}\right)\ln\left(\frac{X^{2}}{(X^{\prime})^{2}}\right)+\left(x_{\perp}\leftrightarrow y_{\perp}\right),\\
\end{split}\end{equation}
答案1
我建议使用以下三种解决方案之一:
要么使用fleqn
来自 的环境nccmath
,它将方程式对齐在左边距,要么使用 `aligned 环境。它需要 $4$ 行才能将方程式放在边距之间。
或者使用flalign
中的环境amsmath
。它只需要 $3$ 行,并将标签放置在中间行,在第一行和最后一行使用 `\notag。
或者使用split
环境,和\mathrlap
作为第三行的结尾,这有点太长了,而它不需要方程编号的空间。我还简化了您的代码,(…^{\prime})^2
用一个简单的替换…'^2
,并且为了获得更好的间距,我将许多对替换\left( … \right)
为 \biggl( … \biggr)
,或( … )
,如果它们不是必需的。
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[showframe]{geometry}%
\usepackage{mathtools, nccmath}
\begin{document}
\mbox{}
\begin{equation}
\begin{aligned}\widetilde{K}(x_{ ⊥ },\, y_{ ⊥ },\, z_{ ⊥ },\, z_{ ⊥ }^{\prime}) = {} & \frac{\alpha_{s}^{2}}{16\pi^{4}(X'^{2}Y^{2}-X^{2}Y'^{2})} \biggl[\frac{Y'^{2}}{Z^{2}}-\frac{Y'^{4}X^{2}}{X'^{2}Z^{2}Y^{2}} - \frac{Y^{4}X'^{2}}{Z^{2}X^{2}Y'^{2}} \\%
& + \frac{Y^{2}}{Z^{2}} + \frac{X'^{2}Y^{2}}{Z^{2}Y'^{2}} - \frac{X^{2}}{Z^{2}} - \frac{X'^{2}}{Z^{2}} + \frac{X^{2}Y'^{2}}{Z^{2}Y^{2}} + \frac{X'^{2}(X-Y)^{2}}{X^{2}Z^{2}} \\ %
& - \frac{Y'^{2}(X-Y)^{2}}{Z^{2}Y^{2}} - \frac{Y^{2}(X-Y)^{2}}{Z^{2}Y'^{2}} +\frac{X^{2}(X-Y)^{2}}{X'^{2}Z^{2}}+\frac{Y^{2}(X-Y)^{2}}{X^{2}Y'^{2}} \\
& - \frac{(X-Y)^{2}}{X'^{2}} - \frac{(X-Y)^{2}}{X^{2}} + \frac{Y'^{2}(X-Y)^{2}}{X'^{2}Y^{2}}\biggr] \ln\biggl(\frac{X^{2}}{X'^{2}}\biggr) + (x_{ ⊥ }\leftrightarrow y_{ ⊥ }),
\end{aligned}
\end{equation}
\bigskip
\begin{flalign} & \widetilde{K}(x_{ ⊥ } ,\, y_{ ⊥ },\, z_{ ⊥ },\, z_{ ⊥ }') = \frac{\alpha_{s}^{2}}{16\pi^{4}(X'^{2}Y^{2}-X^{2}Y'^{2})} \left[\frac{Y'^{2}}{Z^{2}}-\frac{Y'^{4}X^{2}}{X'^{2}Z^{2}Y^{2}} - \frac{Y^{4}X'^{2}}{Z^{2}X^{2}Y'^{2}} + \frac{Y^{2}}{Z^{2}} \right. \notag\\%
& + \frac{X'^{2}Y^{2}}{Z^{2}Y'^{2}} - \frac{X^{2}}{Z^{2}} - \frac{X'^{2}}{Z^{2}} + \frac{X^{2}Y'^{2}}{Z^{2}Y^{2}} + \frac{X'^{2}(X-Y)^{2}}{X^{2}Z^{2}} - \frac{Y'^{2}(X-Y)^{2}}{Z^{2}Y^{2}} - \frac{Y^{2}(X-Y)^{2}}{Z^{2}Y'^{2}} \\ %
& +\frac{X^{2}(X-Y)^{2}}{X'^{2}Z^{2}}+\frac{Y^{2}(X-Y)^{2}}{X^{2}Y'^{2}} -\frac{(X-Y)^{2}}{X'^{2}}-\frac{(X-Y)^{2}}{X^{2}}+ \frac{Y'^{2}(X-Y)^{2}}{X'^{2}Y^{2}}\biggr]\!\ln\biggl(\frac{X^{2}}{X'^{2}}\biggr)+(x_{ ⊥ }\leftrightarrow y_{ ⊥ }),\notag
\end{flalign}
\bigskip
\begin{equation}
\begin{split}
& \widetilde{K}(x_{\perp},\, y_{\perp},\, z_{\perp},\, z_{\perp}^{\prime}) = \frac{\alpha_{s}^{2}}{16\pi^{4}(X'^{2}Y^{2}-X^{2}Y'^{2})}%
\biggl[\frac{Y'^{2}}{Z^{2}}-\frac{Y'^{4}X^{2}}{X'^{2}Z^{2}Y^{2}}%
-\frac{Y^{4}X'^{2}}{Z^{2}X^{2}Y'^{2}}\mathrlap{+\frac{Y^{2}}{Z^{2}}}\\
{}+{} &\frac{X'^{2}Y^{2}}{Z^{2}Y'^{2}}-\frac{X^{2}}{Z^{2}}-\frac{X'^{2}}{Z^{2}}%
+\frac{X^{2}Y'^{2}}{Z^{2}Y^{2}}+\frac{X'^{2}(X-Y)^{2}}{X^{2}Z^{2}}%
-\frac{Y'^{2}(X-Y)^{2}}{Z^{2}Y^{2}}-\frac{Y^{2}(X-Y)^{2}}{Z^{2}Y'^{2}}\\
{}+{} &\frac{X^{2}(X-Y)^{2}}{X'^{2}Z^{2}}+\frac{Y^{2}(X-Y)^{2}}{X^{2}Y'^{2}}%
-\frac{(X-Y)^{2}}{X'^{2}}-\frac{(X-Y)^{2}}{X^{2}}%
+\frac{Y'^{2}(X-Y)^{2}}{X'^{2}Y^{2}}\biggr]\!\ln\biggl(\frac{X^{2}}{X'^{2}}\biggr)%
+(x_{\perp}\mathrlap{\leftrightarrow y_{\perp}),}
\end{split}
\end{equation}
\end{document}
答案2
align
我将使用来自的环境来排版数学包。默认情况下,这会在每一行上放置一个方程编号,但您可以通过在标记每行结尾\notag
之前添加来关闭此功能。\\
这可能是个人问题,但我不喜欢使用,\left(...\right)
因为我认为大多数情况下这会导致过大的分隔符。相反,我使用\bigl
、\Bigl
、\biggl
、\Biggl
、 ... 中的一个,\Biggr
因为它们可以更好地控制括号的大小。无论如何,我认为你使用的\left
和\right
太多了:)同样,我删除了所有的 ,\,
因为 TeX 比我更了解排版数学,我更愿意相信它。我还会将项移动\ln
到带有 的分子中\alpha_s^2
。
考虑到这一点,我会这样编写代码——请注意,我删除了许多不必要的括号等,因为这使其更容易阅读:
\documentclass{article}
\usepackage[hmargin=10mm]{geometry}
\usepackage{amsmath}
\begin{document}
\begin{align}\notag
\widetilde K(x_\perp,&y_\perp, z_\perp, z_\perp^\prime)
=\frac{\alpha_s^2\ln\frac{X^2}{(X^\prime)^2}}{16\pi^4\bigl((X^\prime)^2Y^2-X^2(Y^\prime)^2\bigr)}
\Bigl(\frac{(Y^\prime)^2}{Z^2}-\frac{(Y^\prime)^4X^2}{(X^\prime)^2Z^2Y^2}-\frac{Y^4(X^\prime)^2}{Z^2X^2(Y^\prime)^2}+\frac{Y^2}{Z^2}\\
&+\frac{(X^\prime)^2Y^2}{Z^2(Y^\prime)^2}-\frac{X^2}{Z^2}-\frac{(X^\prime)^2}{Z^2}+\frac{X^2(Y^\prime)^2}{Z^2Y^2}+\frac{(X^\prime)^2(X-Y)^2}{X^2Z^2}-\frac{(Y^\prime)^2(X-Y)^2}{Z^2Y^2}-\frac{Y^2(X-Y)^2}{Z^2(Y^\prime)^2}\\\notag
&+\frac{X^2(X-Y)^2}{(X^\prime)^2Z^2}+\frac{Y^2(X-Y)^2}{X^2(Y^\prime)^2}-\frac{(X-Y)^2}{(X^\prime)^2}-\frac{(X-Y)^2}{X^2}+\frac{(Y^\prime)^2(X-Y)^2}{(X^\prime)^2Y^2}\Bigr)+x_\perp\leftrightarrow y_\perp,\\\notag
\end{align}
\end{document}
输出如下:
最后,你没有简化这个公式有什么原因吗?例如,有很多项以Z^2
作为分母。