我无法正确对齐它们。
我怎样才能拥有多条线方程,并且每条方程都有正确的标记。
以下是一个例子:
\documentclass{article}
\usepackage{amsmath} % for 'align*' environment
\begin{document}
\begin{equation} \label{eq:sr}
\mbox{Inductive reactance as:} X_L = 2 \pi f L = \omega L \\
\mbox{Capacitive reactance as:} X_c = \frac{1}{2 \pi f C} = \frac{1}{\omega C} \\
\mbox{Total circuit reactance:} X_T = X_L - X_C or X_C - X_L \\
\mbox{Total circuit impedance:} Z = \sqrt{R^2 + X_T^2} = R + jX \\
\mbox{When} X_L = X_C \rightarrow 2 \pi f L = \frac{1}{2 \pi f C} \\
f_r = \frac{1}{2 \pi \sqrt{L C}} (Hz) or \omega_r = \frac{1}{L C} (rads) \\
\end{equation}
\end{document}
答案1
最好使用类似以下方法实现枚举的多重比alignat
对amsmath
:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{alignat}{2}
\text{Inductive reactance as:} & \quad & X_L &= 2 \pi f L = \omega L \\
\text{Capacitive reactance as:} & & X_c &= \frac{1}{2 \pi f C} = \frac{1}{\omega C} \\
\text{Total circuit reactance:} & & X_T &= X_L - X_C or X_C - X_L \\
\text{Total circuit impedance:} & & Z &= \sqrt{R^2 + X_T^2} = R + jX \\
\text{When} & & X_L &= X_C \rightarrow 2 \pi f L = \frac{1}{2 \pi f C} \\
& & f_r &= \frac{1}{2 \pi \sqrt{L C}} \text{ (Hz) or }
\omega_r = \frac{1}{L C} \text{ (rads)}
\end{alignat}
\end{document}