我正在制作一个 latex beamer 演示文稿,我有一张表格。我的表格包含数学模式的方程式,看起来像
在最后一部分,分解,我想将 chi 12 的第二个 Delta 与最后一行的 psi 12 对齐。完成后,我想将 chi 10 的箭头与 chi10 的箭头对齐。我尝试了很多方法,但目前没有任何效果。这是我的代码
\documentclass{beamer}
\usepackage[french]{babel}
\usepackage[utf8x]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{lmodern}
\usepackage{multirow}
\usepackage[font=small,skip=0pt]{caption}
\usepackage{tabu}
\usetheme{Warsaw}
\usecolortheme{seahorse}
\begin{document}
\begin{frame}
\frametitle{Siegel modular forms}
\begin{center}
\tabulinesep=1.2mm
\begin{tabu}{|c| c| c|}
\hline %inserts horizontal line
&Genus 1 & Genus 2 \\[0.5ex]
\hline
Generators & $\phi_4$, $\phi_6$ & $\psi_4,\psi_6,\chi_{10},\chi_{12}$ \\
\hline
Siegel operator & $\Phi(\phi_4) = \Phi(\phi_6) = 1 $& $\Phi(\psi_i)=\phi_i, \Phi(\chi_{j})= 0$\\
\hline
Discriminant & $\Delta =\frac{\phi_4^3-\phi_6^2}{1728} = \eta^{24}$ & $\psi_{12} = \frac{\psi_4^3-\psi_6^2}{1728}$
\\\hline
Siegel operator & $\Phi(\Delta)=0$ $\rightarrow$ cusp form & $\Phi(\psi_{12})=\Delta$\\ \hline
\multicolumn{3}{c}{}\\[-0.7em]
\hline
Factorization & \multicolumn{2}{c|}{$\begin{array} {lcllcl} \psi_4 & \rightarrow &\phi_4\otimes\phi_4 &\chi_{10}&\rightarrow &0\\ \psi_6 & \rightarrow & \phi_6\otimes\phi_6 & \chi_{12} & \rightarrow & \Delta\otimes\Delta\\
\psi_{12} & \rightarrow & \multicolumn{4}{l}{\phi_4^3\otimes \Delta + \Delta \otimes \phi_4^3-1728\Delta\otimes\Delta }
\end{array}$}\\
\hline
\end{tabu}
\end{center}
\end{frame}
\end{document}
非常感谢。
答案1
\documentclass{article}
\begin{document}
\(\begin{array}{l@{\;}lr@{}l}
\psi_4 & \rightarrow \phi_4\otimes\phi_4 & \chi_{10} \rightarrow {} & 0\\
\psi_6 & \rightarrow \phi_6\otimes\phi_6 & \chi_{12} \rightarrow {} & \Delta\otimes\Delta\\
\psi_{12} & \multicolumn{2}{@{}l@{}}{\rightarrow \phi_4^3\otimes \Delta +
\Delta \otimes \phi_4^3-1728} & \Delta\otimes\Delta
\end{array}
\)
\end{document}