我如何才能将两个组环境并排放置?\hfill
和都\quad
不起作用。
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[italian]{babel}
\usepackage[
a4paper,
margin=15mm,
bindingoffset=2mm,
heightrounded,
]{geometry}
\usepackage{amsmath}
\usepackage{microtype}
\usepackage{xcolor}
\usepackage{varwidth}
\usepackage{etoolbox}
\usepackage{enumitem}
\usepackage{hyperref}
\definecolor{lightgray}{HTML}{EFEFEF}
\newtoggle{odditem}
\def\myitem{\iftoggle{odditem}%
{\color{black}\togglefalse{odditem}}%
{\color{blue}\toggletrue{odditem}}%
\olditem}
\newenvironment{myitemize}[1]{%
\begin{varwidth}[t]{\textwidth}
#1
\begin{itemize}[leftmargin=*]%
\toggletrue{odditem}%
\let\olditem\item%
\let\item\myitem}{
\end{itemize}
\end{varwidth}
}
\begin{document}
\begingroup\setlength{\fboxsep}{6pt}
\colorbox{white}{%
\begin{myitemize}{POTENZE}
\item $a^{1} = a$
\item $a^{0} = 1$
\item $a^{n} \cdot a^{m} = a^{n+m}$
\item $\dfrac{a^{n}}{a^{m}} = a^{n-m}$
\item $a^{-n} = \dfrac{1}{a^{n}}$
\item ${(a^{n})}^{m} = a^{n \cdot m}$
\item $a^{n} \cdot b^{n} = \left(a \cdot b\right)^{n}$
\item $\dfrac{a^{n}}{b^{n}} = \left(\dfrac{a}{b}\right)^{n},\; b \neq 0$
\item $a^{\tfrac{m}{n}} = \sqrt[n]{a^{m}}$
\end{myitemize}
}\endgroup
\begingroup\setlength{\fboxsep}{6pt}
\colorbox{white}{%
\begin{myitemize}{LOGARITMI}
\item $a^{\log_a b} = b$
\item $\log_{a} bc = \log_{a} b + \log_{a} c$
\item $\log_{a} \dfrac{b}{c} = \log_{a} b - \log_{a} c$
\item $\dfrac{a^{n}}{a^{m}} = a^{n-m}$
\item $c\log_{a} b = \log_{a} b^{c}$
\item $\log_{a} b = \dfrac{1}{\log_{b} a}$
\end{myitemize}
}\endgroup
\end{document}
答案1
tcbraster
带有和盒子的解决方案tcolorbox
。
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[italian]{babel}
\usepackage[
a4paper,
margin=15mm,
bindingoffset=2mm,
heightrounded,
]{geometry}
\usepackage{amsmath}
\usepackage{microtype}
\usepackage{xcolor}
\usepackage[most]{tcolorbox}
\usepackage{etoolbox}
\usepackage{enumitem}
\usepackage{hyperref}
\definecolor{lightgray}{HTML}{EFEFEF}
\newtcolorbox{powlogbox}[1][]{%
enhanced jigsaw,
sharp corners,
colback=white,
nobeforeafter,
#1
}
\newtoggle{odditem}
\def\myitem{\iftoggle{odditem}%
{\color{black}\togglefalse{odditem}}%
{\color{blue}\toggletrue{odditem}}%
\olditem}
\newenvironment{myitemize}[1]{%
#1
\begin{itemize}[leftmargin=*]%
\toggletrue{odditem}%
\let\olditem\item%
\let\item\myitem}{
\end{itemize}
}
\begin{document}
\begin{tcbraster}[raster columns=2, raster equal height]
\begin{powlogbox}
\begin{myitemize}{POTENZE}
\item $a^{1} = a$
\item $a^{0} = 1$
\item $a^{n} \cdot a^{m} = a^{n+m}$
\item $\dfrac{a^{n}}{a^{m}} = a^{n-m}$
\item $a^{-n} = \dfrac{1}{a^{n}}$
\item ${(a^{n})}^{m} = a^{n \cdot m}$
\item $a^{n} \cdot b^{n} = \left(a \cdot b\right)^{n}$
\item $\dfrac{a^{n}}{b^{n}} = \left(\dfrac{a}{b}\right)^{n},\; b \neq 0$
\item $a^{\tfrac{m}{n}} = \sqrt[n]{a^{m}}$
\end{myitemize}
\end{powlogbox}
\begin{powlogbox}
\begin{myitemize}{LOGARITMI}
\item $a^{\log_a b} = b$
\item $\log_{a} bc = \log_{a} b + \log_{a} c$
\item $\log_{a} \dfrac{b}{c} = \log_{a} b - \log_{a} c$
\item $\dfrac{a^{n}}{a^{m}} = a^{n-m}$
\item $c\log_{a} b = \log_{a} b^{c}$
\item $\log_{a} b = \dfrac{1}{\log_{b} a}$
\end{myitemize}
\end{powlogbox}
\end{tcbraster}
\end{document}