不幸的是，我有一张适合一页的下表
（1）我不知道如何把第三张桌子放下来，这样我就有两张桌子在顶部，两张桌子在底部
（2）另外，如何在 2 个顶部表格和 2 个底部表格之间放置间隙？
\documentclass[12pt]{article}
\usepackage{mathrsfs}
\usepackage{mathtools}
\usepackage{amsmath}
\usepackage{amsthm}
\usepackage{tabularx,ragged2e,booktabs,caption}
\usepackage{tabu}
\usepackage{amssymb,bm}
\usepackage{array}
\begin{document}
\begin{table}[!htbp]
\centering
{\scriptsize
\begin{tabular}[t]{|c|c|c|}
\hline
$k$ & $w_k +\mathcal{O}(5^2)$ & $\bigg(\dfrac{w_k}{5}\bigg)$ \\
\hline
$1$ & $ 1+\mathcal{O}(5^2)$ &$1$ \\
\hline
$2$ & $ 1+\mathcal{O}(5^2)$ &$1$\\
\hline
$3$ & $ 1+\mathcal{O}(5^2)$ &$1$\\
\hline
$4$ & $ 4+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$5$ & $ 3+2\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$6$ & $ 2+\mathcal{O}(5^2)$ &$-1$\\
\hline
$7$ & $ 1+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$8$ & $ 1+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$9$ & $ 1+\mathcal{O}(5^2)$ &$1$\\
\hline
$10$ & $ 2+4\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$11$ & $ 4+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$12$ & $ 2+4\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$13$ & $ 1+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$14$ & $ 4+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$15$ & $ 3+2\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$16$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$17$ & $ 4+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$18$ & $ 3+2\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$19$ & $ 4+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$20$ & $ 2+5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$21$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$22$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$23$ & $4+ 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$24$ & $2+5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$25$ & $3+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$26$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$27$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$28$ & $ 1+5+\mathcal{O}(5^2)$ &$1$\\
\hline
$29$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$30$ & $1+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
\end{tabular}
\hfill % Second tabular
\begin{tabular}[t]{|c|c|c|}
\hline
$k$ & $w_k +\mathcal{O}(5^2)$ &$\bigg(\dfrac{w_k}{5}\bigg)$ \\
\hline
$31$ & $ 4+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$32$ & $ 4+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$33$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$34$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$35$ & $2 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$36$ & $3+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$37$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$38$ & $1+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$39$ & $1+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$40$ & $3 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$41$ & $ 1+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$42$ & $2+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$43$ & $ 1+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$44$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$45$ & $ 2+4\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$46$ & $1+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$47$ & $ 4+\mathcal{O}(5^2)$ &$1$\\
\hline
$48$ & $ 3+2\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$49$ & $1 +\mathcal{O}(5^2)$ &$1$\\
\hline
$50$ & $ 3+4\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$51$ & $1+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$52$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$53$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$54$ & $ 3+\mathcal{O}(5^2)$ &$-1$\\
\hline
$55$ & $2+2\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$56$ & $ 1+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$57$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$58$ & $ 1+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$59$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$60$ & $ 4+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
\end{tabular}
\hfill% Third tabular
\begin{tabular}[t]{|c|c|c|}
\hline
$k$ & $w_k +\mathcal{O}(5^2)$ &$\bigg(\dfrac{w_k}{5}\bigg)$\\
\hline
$61$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$62$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$63$ & $ 4+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$64$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$65$ & $ 2+\mathcal{O}(5^2)$ &$-1$\\
\hline
$66$ & $ 3+\mathcal{O}(5^2)$ &$-1$\\
\hline
$67$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$68$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$69$ & $4+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$70$ & $3+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$71$ & $ 1+4\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$72$ & $3 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$73$ & $ 4+5+\mathcal{O}(5^2)$ &$1$\\
\hline
$74$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$75$ & $ 2+3\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$76$ & $ 1+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$77$ & $1+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$78$ & $ 2+4\cdot 5+\mathcal{O}(5^2)$ &$-1$\\
\hline
$79$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$80$ & $3+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$81$ & $ 1+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$82$ & $ 1+\mathcal{O}(5^2)$ &$1$\\
\hline
$83$ & $ 1+5+\mathcal{O}(5^2)$ &$1$\\
\hline
$84$ & $3 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$85$ & $ 2+\mathcal{O}(5^2)$ &$-1$\\
\hline
$86$ & $ 4+2\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$87$ & $1 +\mathcal{O}(5^2)$ &$1$\\
\hline
$88$ & $ 4+3\cdot 5+\mathcal{O}(5^2)$ &$1$\\
\hline
$89$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$90$ & $4+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
\end{tabular}
\hfill% Fourth tabular
\begin{tabular}[t]{|c|c|c|}
\hline
$k$ & $w_k +\mathcal{O}(5^2)$ &$\bigg(\dfrac{w_k}{5}\bigg)$\\
\hline
$91$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$92$ & $1+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$93$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$94$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$95$ & $3+2\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$96$ & $2+4\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$97$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$98$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$99$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$100$ & $2 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$101$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$102$ & $3+2\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$103$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$104$ & $1+5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$105$ & $3 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$106$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$107$ & $1+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$108$ & $2+3\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$109$ & $4 +\mathcal{O}(5^2)$ &$1$\\
\hline
$110$ & $2+4\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$111$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$112$ & $1+ 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$113$ & $1+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$114$ & $2+ 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$115$ & $3+4\cdot 5 +\mathcal{O}(5^2)$ &$-1$\\
\hline
$116$ & $4+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$117$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$118$ & $4+4\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$119$ & $1+2\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
$120$ & $1+3\cdot 5 +\mathcal{O}(5^2)$ &$1$\\
\hline
\end{tabular}}
\captionof{table}{$w_k$ for $k=1, \cdots, 120$} \label{table:wn2seriess}
\end{table}
\end{document}
看起来像这样：
答案1
您的表格太大，无法放入一页。您有更多方法可以解决您的问题：
- 将表格拆分为两部分并用于编号
\ContinuedFloat - 放大文档的文本宽度。例如，
\usepackage[margin=35mm]{geometry}在 pdocument 序言中，您将获得足够的空间在一行中容纳所有四个表格（如果同时缩小\tabcolsep到 3pt 并减少周围的空间\cdot）：
- 仅在表格中放大文本宽度，例如使用
adjustwidth包中的宏changepage
离题：您可以根据列类型的定义\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}删除表中的所有其他类型$，如下面的 MWE 中所做的那样，它考虑列出的可能性的第二种情况：
\documentclass[12pt]{article}
\usepackage{mathrsfs}
\usepackage{mathtools}
\usepackage{amsmath}
\usepackage{amsthm}
\usepackage{array, booktabs, makecell, tabularx, caption}
\renewcommand\theadfont{\scriptsize}
\usepackage{tabu}
\usepackage{amssymb,bm}
\usepackage{ragged2e}
\usepackage[margin=25mm]{geometry}
%---------------------------------------------------------------%
\usepackage{showframe}
\renewcommand\ShowFrameLinethickness{0.15pt}
\renewcommand*\ShowFrameColor{\color{red}}
%---------------------------------------------------------------%
\begin{document}
\begin{table}[!htbp]
%\centering
\scriptsize
\setlength\tabcolsep{3pt}
\renewcommand\arraystretch{1.2}
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
\hline
\thead{k}
& \thead{w_k +\mathcal{O}(5^2)} & \thead{\left(\dfrac{w_k}{5}\right)} \\
\hline
1 & 1+\mathcal{O}(5^2) &1 \\
\hline
2 & 1+\mathcal{O}(5^2) &1\\
\hline
3 & 1+\mathcal{O}(5^2) &1\\
\hline
4 & 4+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
5 & 3+2{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
6 & 2+\mathcal{O}(5^2) &-1\\
\hline
7 & 1+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
8 & 1+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
9 & 1+\mathcal{O}(5^2) &1\\
\hline
10 & 2+4{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
11 & 4+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
12 & 2+4{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
13 & 1+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
14 & 4+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
15 & 3+2{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
16 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
17 & 4+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
18 & 3+2{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
19 & 4+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
20 & 2+5+\mathcal{O}(5^2) &-1\\
\hline
21 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
22 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
23 & 4+ 5 +\mathcal{O}(5^2) &1\\
\hline
24 & 2+5 +\mathcal{O}(5^2) &-1\\
\hline
25 & 3+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
26 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
27 & 4 +\mathcal{O}(5^2) &1\\
\hline
28 & 1+5+\mathcal{O}(5^2) &1\\
\hline
29 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
30 & 1+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
\end{tabular}
\hfill % Second tabular
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
\hline
\thead{k}
& \thead{w_k +\mathcal{O}(5^2)} & \thead{\left(\dfrac{w_k}{5}\right)} \\
\hline
31 & 4+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
32 & 4+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
33 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
34 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
35 & 2 +\mathcal{O}(5^2) &-1\\
\hline
36 & 3+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
37 & 4 +\mathcal{O}(5^2) &1\\
\hline
38 & 1+5 +\mathcal{O}(5^2) &1\\
\hline
39 & 1+5 +\mathcal{O}(5^2) &1\\
\hline
40 & 3 +\mathcal{O}(5^2) &-1\\
\hline
41 & 1+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
42 & 2+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
43 & 1+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
44 & 4 +\mathcal{O}(5^2) &1\\
\hline
45 & 2+4{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
46 & 1+5 +\mathcal{O}(5^2) &1\\
\hline
47 & 4+\mathcal{O}(5^2) &1\\
\hline
48 & 3+2{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
49 & 1 +\mathcal{O}(5^2) &1\\
\hline
50 & 3+4{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
51 & 1+5 +\mathcal{O}(5^2) &1\\
\hline
52 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
53 & 4 +\mathcal{O}(5^2) &1\\
\hline
54 & 3+\mathcal{O}(5^2) &-1\\
\hline
55 & 2+2{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
56 & 1+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
57 & 4 +\mathcal{O}(5^2) &1\\
\hline
58 & 1+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
59 & 4 +\mathcal{O}(5^2) &1\\
\hline
60 & 4+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
\end{tabular}
\hfill% Third tabular
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
\hline
\thead{k}
& \thead{w_k +\mathcal{O}(5^2)} & \thead{\left(\dfrac{w_k}{5}\right)} \\
\hline
61 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
62 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
63 & 4+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
64 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
65 & 2+\mathcal{O}(5^2) &-1\\
\hline
66 & 3+\mathcal{O}(5^2) &-1\\
\hline
67 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
68 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
69 & 4+5 +\mathcal{O}(5^2) &1\\
\hline
70 & 3+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
71 & 1+4{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
72 & 3 +\mathcal{O}(5^2) &-1\\
\hline
73 & 4+5+\mathcal{O}(5^2) &1\\
\hline
74 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
75 & 2+3{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
76 & 1+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
77 & 1+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
78 & 2+4{\cdot} 5+\mathcal{O}(5^2) &-1\\
\hline
79 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
80 & 3+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
81 & 1+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
82 & 1+\mathcal{O}(5^2) &1\\
\hline
83 & 1+5+\mathcal{O}(5^2) &1\\
\hline
84 & 3 +\mathcal{O}(5^2) &-1\\
\hline
85 & 2+\mathcal{O}(5^2) &-1\\
\hline
86 & 4+2{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
87 & 1 +\mathcal{O}(5^2) &1\\
\hline
88 & 4+3{\cdot} 5+\mathcal{O}(5^2) &1\\
\hline
89 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
90 & 4+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
\end{tabular}
\hfill% Fourth tabular
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
\hline
\thead{k}
& \thead{w_k +\mathcal{O}(5^2)} & \thead{\left(\dfrac{w_k}{5}\right)} \\
\hline
91 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
92 & 1+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
93 & 4 +\mathcal{O}(5^2) &1\\
\hline
94 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
95 & 3+2{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
96 & 2+4{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
97 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
98 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
99 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
100 & 2 +\mathcal{O}(5^2) &-1\\
\hline
101 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
102 & 3+2{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
103 & 4 +\mathcal{O}(5^2) &1\\
\hline
104 & 1+5 +\mathcal{O}(5^2) &1\\
\hline
105 & 3 +\mathcal{O}(5^2) &-1\\
\hline
106 & 4 +\mathcal{O}(5^2) &1\\
\hline
107 & 1+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
108 & 2+3{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
109 & 4 +\mathcal{O}(5^2) &1\\
\hline
110 & 2+4{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
111 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
112 & 1+ 5 +\mathcal{O}(5^2) &1\\
\hline
113 & 1+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
114 & 2+ 5 +\mathcal{O}(5^2) &-1\\
\hline
115 & 3+4{\cdot} 5 +\mathcal{O}(5^2) &-1\\
\hline
116 & 4+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
117 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
118 & 4+4{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
119 & 1+2{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
120 & 1+3{\cdot} 5 +\mathcal{O}(5^2) &1\\
\hline
\end{tabular}
\caption{$w_k$ for $k=1, \cdots, 120$} \label{table:wn2seriess}
\end{table}
\end{document}
对于第一种情况，（缩短的）MWE 为：
...
\begin{table}% first table
\centering
% first tabular
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
...
% second tabular
\end{tabular}
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
...
\end{tabular}
\caption{...}
\end{table}
\begin{table}% second table
\ContinuedFloat
\centering
% third tabular
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
...
% fourth tabular
\end{tabular}
\begin{tabular}[t]{|*{3}{>{$}c<{$}|}}
...
\end{tabular}
\caption{...}% it has the same number as the first (part of) table
\end{table}
对于最后一种情况（结果与上图相同）：
% preamble
\usepackage[strict]{changepage}
...
\begin{table}
\begin{adjustwidth*}{}{-\marginparwidth}% for case of two side document
...
\end{adjustwidth*}
\end{table}
...