我正在尝试使用该包创建一个神经网络图示neuralnetwork
。我想单独标记我的偏置神经元。
现在我有代码:
\documentclass[fleqn,11pt,a4paper,final]{article}
\usepackage{neuralnetwork}
\begin{document}
\begin{figure}[h!]
\begin{neuralnetwork}[height=1.5 ,maintitleheight=1cm,layertitleheight=3cm]
\newcommand{\nodetextx}[2]{$x_{#2}$}
\newcommand{\nodetextz}[2]{$y$}
\newcommand{\nodetexth}[2]{$h_{#2,1}$}
\newcommand{\nodetexthto}[2]{$h_{#2,2}$}
\inputlayer[count=3, title={Input-lag}, text=\nodetextx]
\hiddenlayer[count=5, title={Skjult lag}, text=\nodetexth]
\linklayers
\hiddenlayer[count=4, title={Skjult lag}, text=\nodetexthto]
\linklayers
\outputlayer[count=1, title={Output-lag}, text=\nodetextz]
\linklayers
\end{neuralnetwork}
\end{figure}
\end{document}
我想要x_0
标记 -神经元\textbf{c_1}
,h_{0,1}
标记 -神经元\textbf{c_2}
,最后h_{0,2}
标记 -神经元b
。我该怎么做?
非常感谢您的帮助。谢谢
答案1
这可能比它需要的更复杂,但它似乎确实有效。
\documentclass[border=5mm]{standalone}
\usepackage{xpatch}
\usepackage{neuralnetwork}
% this is the command that prints the first node in a layer
% \node[bias neuron] (L\nn@layerindex-0) at (\nn@node@xb, \nn@node@y) {\nn@nodecaption{\nn@layerindex}{0}};
% we want to modify the last bit to use the loop macro \nn@nodeindex instead of 0
\makeatletter
\xpatchcmd{\layer}{\nn@nodecaption{\nn@layerindex}{0}}{\nn@nodecaption{\nn@layerindex}{\nn@nodeindex}}{}{}
% define the nodeindex to be zero initially
\newcommand\nn@nodeindex{0}
\newcommand{\nodetextx}[2]{
\ifnum \nn@nodeindex=0
$\mathbf{c_1}$
\else
$x_{#2}$
\fi
}
\newcommand{\nodetextz}[2]{$y$}
\newcommand{\nodetexth}[2]{
\ifnum \nn@nodeindex=0
$\mathbf{c_2}$
\else
$h_{#2,1}$
\fi
}
\newcommand{\nodetexthto}[2]{
\ifnum \nn@nodeindex=0
$b$
\else
$h_{#2,2}$
\fi
}
\makeatother
\begin{document}
\begin{neuralnetwork}[height=1.5 ,maintitleheight=1cm,layertitleheight=3cm]
\inputlayer[count=3, title={Input-lag}, text=\nodetextx]
\hiddenlayer[count=5, title={Skjult lag}, text=\nodetexth]
\linklayers
\hiddenlayer[count=4, title={Skjult lag}, text=\nodetexthto]
\linklayers
\outputlayer[count=1, title={Output-lag}, text=\nodetextz]
\linklayers
\end{neuralnetwork}
\end{document}
答案2
解决
我想为我的解决方案做出贡献。通过添加标签来解决问题bias = false
。我不知道偏见是什么,我在另一个博客上找到了它,它有效。
\documentclass[border=5mm]{standalone}
\usepackage{xpatch}
\usepackage{neuralnetwork}
% this is the command that prints the first node in a layer
% \node[bias neuron] (L\nn@layerindex-0) at (\nn@node@xb, \nn@node@y) {\nn@nodecaption{\nn@layerindex}{0}};
% we want to modify the last bit to use the loop macro \nn@nodeindex instead of 0
\makeatletter
\xpatchcmd{\layer}{\nn@nodecaption{\nn@layerindex}{0}}{\nn@nodecaption{\nn@layerindex}{\nn@nodeindex}}{}{}
% define the nodeindex to be zero initially
\newcommand\nn@nodeindex{0}
\newcommand{\nodetextx}[2]{
\ifnum \nn@nodeindex=0
$\mathbf{c_1}$
\else
$i_{#2}$
\fi
}
\newcommand{\nodetextz}[2]{$o_1$}
\newcommand{\nodetexth}[2]{
\ifnum \nn@nodeindex=0
$\mathbf{c_2}$
\else
$h_{1, #2}$
\fi
}
\newcommand{\nodetexthto}[2]{
\ifnum \nn@nodeindex=0
$b$
\else
$h_{2, #2}$
\fi
}
\makeatother
\begin{document}
\begin{neuralnetwork}[height=1.5 ,maintitleheight=1cm,layertitleheight=5cm]
\inputlayer[count=5, bias=false, title={Input}, text=\nodetextx]
\hiddenlayer[count=10, bias=false, title={Oc1}, text=\nodetexth]
\linklayers
\hiddenlayer[count=10, bias=false, title={Oc2}, text=\nodetexthto]
\linklayers
\outputlayer[count=1, title={Output}, text=\nodetextz]
\linklayers
\end{neuralnetwork}
\end{document}