正在努力解决这个问题,任何帮助我都会很感激。非常感谢
\documentclass[a4paper,12pt]{report}
\usepackage{multirow}
\usepackage{siunitx,booktabs}%for table decimals number
\usepackage[export]{adjustbox} \begin{table}[!htbp]
\centering
\begin{tabular}{>{\bfseries}l
S[table-format=-1.2(2)]
S[table-format=table-format=1.1e1] }
\toprule
{\textbf{Approach}} & $\boldsymbol{\beta}$ & $\boldsymbol{\chi^{2}}$ \\
\midrule
1 & -0.61(17) & Inf. \\
2 & -0.60(17) & Inf. \\
3 & -0.59(18) & 3$\times$10$^6$\\
4 & -0.56(20) & Inf. \\
\bottomrule
\end{tabular}
\caption[]
\label{}
\end{table}
\FloatBarrier
答案1
我不会在标题中使用粗体:\bm{\beta}
和\beta
是两个不同的数学实体。
第一列也不必是粗体。第三列只有一个数字,因此只需用c
表示\num
数字即可;如果这只是完整版本,则应将非数字条目括起来。
\documentclass[a4paper,12pt]{report}
\usepackage{amsmath,bm}
\usepackage{siunitx,booktabs}%for table decimals number
\begin{document}
\begin{table}[!htbp]
\centering
\begin{tabular}{
>{\bfseries}l
S[table-format=-1.2(2)]
c
}
\toprule
Approach & {$\bm{\beta}$} & $\bm{\chi^{2}}$ \\
\midrule
1 & -0.61(17) & Inf. \\
2 & -0.60(17) & Inf. \\
3 & -0.59(18) & \num{3e6} \\
4 & -0.56(20) & Inf. \\
\bottomrule
\end{tabular}
\caption{A caption}
\label{label}
\end{table}
\begin{table}[!htbp]
\centering
\begin{tabular}{
l
S[table-format=-1.2(2)]
c
}
\toprule
Approach & {$\beta$} & $\chi^{2}$ \\
\midrule
1 & -0.61(17) & Inf. \\
2 & -0.60(17) & Inf. \\
3 & -0.59(18) & \num{3e6} \\
4 & -0.56(20) & Inf. \\
\bottomrule
\end{tabular}
\caption{A caption}
\label{label2}
\end{table}
\begin{table}[!htbp]
\centering
\begin{tabular}{
l
S[table-format=-1.2(2)]
S[table-format=1.0e1]
}
\toprule
Approach & {$\beta$} & $\chi^{2}$ \\
\midrule
1 & -0.61(17) & {Inf.} \\
2 & -0.60(17) & {Inf.} \\
3 & -0.59(18) & 3e6 \\
4 & -0.56(20) & {Inf.} \\
\bottomrule
\end{tabular}
\caption{A caption}
\label{label3}
\end{table}
\end{document}
答案2
这应该是您的表格并且可以编译:
\documentclass[a4paper,12pt]{report}
\usepackage{multirow}
\usepackage{siunitx}
\usepackage{booktabs}
\usepackage{amsmath}
\begin{document}
\begin{table}[!htbp]
\centering
\begin{tabular}{>{\bfseries}c % I think centred column looks better here
S[table-format=-1.2(2)]
S[table-format=1.1e1] }
\toprule
Approach & $\boldsymbol{\beta}$ & $\boldsymbol{\chi^{2}}$ \\
\midrule
1 & -0.61(17) & {Inf.} \\
2 & -0.60(17) & {Inf.} \\
3 & -0.59(18) & 3e6 \\
3 & -0.59(18) & 3.0e6 \\ % for comparison
4 & -0.56(20) & {Inf.} \\
\bottomrule
\end{tabular}
\caption{test}
\label{tab:test}
\end{table}
\end{document}
答案3
\documentclass[a4paper,12pt]{report}
\usepackage{amsmath}
\usepackage{booktabs}
\usepackage{siunitx}
\begin{document}
\begin{table}[htbp]
\centering
\caption[]{My nice table}
\label{tab:mytable}
\begin{tabular}{>{\bfseries}l
S[table-format=-1.2(2)]
S[table-format= 1.0e1] }
\toprule
Approach & {$\boldsymbol{\beta}$} & {$\boldsymbol{\chi^{2}}$} \\
\midrule
1 & -0.61(17) & {Inf.} \\
2 & -0.60(17) & {Inf.} \\
3 & -0.59(18) & 3e6 \\
4 & -0.56(20) & {Inf.} \\
\bottomrule
\end{tabular}
\end{table}
or
\begin{table}[htbp]
\sisetup{separate-uncertainty}%
\centering
\caption[]{My nice table again}
\label{tab:mytable}
\begin{tabular}{>{\bfseries}c
S[table-format=-1.2(2)]
S[table-format= 1.0e1] }
\toprule
Approach & {$\boldsymbol{\beta}$} & {$\boldsymbol{\chi^{2}}$} \\
\midrule
1 & -0.61(17) & {Inf.} \\
2 & -0.60(17) & {Inf.} \\
3 & -0.59(18) & 3e6 \\
4 & -0.56(20) & {Inf.} \\
\bottomrule
\end{tabular}
\end{table}
\end{document}