答案1
我将@jfbu 的评论变成了答案。
\documentclass{article}
\usepackage{tasks}
\begin{document}
\settasks{after-item-skip=4em,
after-skip=2cm,
label-width=3ex,
counter-format=(tsk[a]),
column-sep=2em
}
\begin{tasks}(2)
\task First left column
\task First right column
\task Second left column
\task Second right column
\task Third left column
\task Third right column
\end{tasks}
\end{document}
答案2
对代码进行一些修改使用枚举和多列实现等间距, 我们有
\documentclass{article}
\usepackage[margin=1.5cm]{geometry}
\usepackage{amsmath}
\newlength{\subproblemhang}
\newcommand{\subproblem}[3][.45\linewidth]{%
\settowidth{\subproblemhang}{(#2)~}%
\begin{minipage}[t]{#1}
\hangindent=\subproblemhang\hangafter=1%
(#2)~#3
\end{minipage}%
}
\newcommand{\dg}{\ensuremath{^\circ}}
\begin{document}
\begin{enumerate}
%Problem 1
\item[] \textbf{Exercise \#2}. Consider the trigonometric equation $\sin(\theta)=-\dfrac13$ over the interval $0\dg\leq\theta\leq360\dg$. \\
\subproblem{a}{determine the reference angle for this problem by evaluating $\sin^{-1}(1/3)$. Round to nearest \textit{tenth} of a degree.}\hfill
\subproblem{b}{In what quadrants is the sine function negative?}
\vfill
\subproblem{c}{Draw the rotation diagrams for the two angles that terminate in the quadrants specified in (b) that have the reference angle from (a).}\hfill
\subproblem{d}{Using your answers from (a), (b) and (c), solve the equation $\sin(\theta)=-\dfrac13$ over the interval $0\dg\leq\theta\leq360\dg$. State your answer to the nearest \textit{tenth} of a degree.}
\vfill
%Problem 2
\item Second problem goes here.
\vfill
\end{enumerate}
\end{document}