如何在 Beamer 中延长 Tcolorbox 的长度

Question

我正在使用以下代码

\documentclass{beamer}  
\usepackage[latin1]{inputenc} 
\usepackage[T1]{fontenc}
\usepackage{amsmath,amssymb,amsfonts} %math
\usepackage{graphicx}
\usepackage{pifont} %bouni
%--------------------
\usepackage[most]{tcolorbox}
\newtcolorbox{mybox}[2][]{%
colback=bg,
colframe=blue!75!black,
fonttitle=\bfseries,
coltitle=blue!75!black,
colbacktitle=bg,
enhanced,
attach boxed title to top left={yshift=-1.2mm, xshift=2mm},
title=#2,
#1}

\usepackage{color} %couleur

\usetheme{Warsaw}

\begin{document}
\begin{frame}{}
\begin{mybox}
[colframe=blue!75!black,coltitle=black!75!black,colbacktitle=white!90!blue, 
]{\ding{43} Definition}
Let ${\bf T} = (T_1,\cdots, T_d)$ be $d$-tuple of operators in $\mathcal{B}
 (\mathcal{H}).$ The joint numerical range of ${\bf T}$ is the set $JtW({\bf 
 T})$ of  $\mathbb{C}^d$  such
 that
 $$JtW({\bf T})=\{(\langle T_1 x\; |\;x\rangle,\langle T_1 x\; 
 |\;x\rangle,\cdots,\langle T_d x
  |\;x\rangle)\;:x \in \mathcal{H},\;\;\|x\|=1\}.$$
\end{mybox}
\end{frame}
\end{document}

我明白了

我想延长区块的长度。你能帮我吗？

Answer 1

发生这种情况是因为您的公式太长，并且不尊重边距，因此我建议将其分成两行。但是，您可以通过将选项添加到来实现所需的oversize效果mybox。

\documentclass{beamer} 
\usepackage[latin1]{inputenc} 
\usepackage[T1]{fontenc}
%-----
\usepackage{amsmath,amssymb,amsfonts} %math
\usepackage{graphicx}
\usepackage{pifont} %bouni
%--------------------
\usepackage[most]{tcolorbox}
\newtcolorbox{mybox}[2][]{%
colback=bg,
colframe=blue!75!black,
fonttitle=\bfseries,
coltitle=blue!75!black,
colbacktitle=bg,
enhanced,
attach boxed title to top left={yshift=-1.2mm, xshift=2mm},
title=#2,
#1}

\usepackage{color} %couleur

\usetheme{Warsaw}

\begin{document}
\begin{frame}{}
    \begin{mybox}
        [oversize, colframe=blue!75!black,coltitle=black!75!black,colbacktitle=white!90!blue, 
        ]{\ding{43} Definition}
        Let ${\bf T} = (T_1,\cdots, T_d)$ be $d$-tuple of operators in $\mathcal{B}
        (\mathcal{H}).$ The joint numerical range of ${\bf T}$ is the set $JtW({\bf 
        T})$ of  $\mathbb{C}^d$  such
        that
        $$JtW({\bf T})=\{(\langle T_1 x\; |\;x\rangle,\langle T_1 x\; 
        |\;x\rangle,\cdots,\langle T_d x
        |\;x\rangle)\;:x \in \mathcal{H},\;\;\|x\|=1\}.$$
    \end{mybox}

\end{frame}
\end{document}

Answer 2

mybox这是另一种解决方法。您需要在定义中添加几行：width=1.05\textwidth并left skip=-0.5cm保留tcolorbox长方程并将其置于框架的中心。

\documentclass{beamer}

\usepackage[latin1]{inputenc} 
\usepackage[T1]{fontenc}
\usepackage{amsmath,amssymb,amsfonts} %math
\usepackage{graphicx}
\usepackage{pifont} %bouni
\usepackage[most]{tcolorbox}
\usepackage{color} %couleur

\usetheme{Warsaw}

\newtcolorbox{mybox}[2][]{%
        width=1.05\textwidth,
        left skip=-0.5cm,
        colback=bg,
        colframe=blue!75!black,
        fonttitle=\bfseries,
        coltitle=blue!75!black,
        colbacktitle=bg,
        enhanced,
        attach boxed title to top left={yshift=-1.2mm, xshift=2mm},
        title=#2,
        #1}

\begin{document}

\begin{frame}{}
\begin{mybox}[%
        colframe=blue!75!black,
        coltitle=black!75!black,
        colbacktitle=white!90!blue, 
        ] {\ding{43} Definition}

Let ${\bf T} = (T_1,\cdots, T_d)$ be $d$-tuple of operators in $\mathcal{B} (\mathcal{H}).$ The joint numerical range of ${\bf T}$ is the set $JtW({\bf T})$ of $\mathbb{C}^d$ such that

\[
JtW({\bf T})=\{(\langle T_1 x|x\rangle,\langle T_1 x|x\rangle,\cdots,\langle T_d x|x\rangle):x \in \mathcal{H},\|x\|=1\}.
\]

\end{mybox}
\end{frame}

\end{document}