我曾在这里看到过这些符号文章
答案1
也许使用tikz
并编写一个简短的宏:
\documentclass{article}
\usepackage{tikz}
\newcommand{\piercebox}[1]{%
\def\parr{{#1}}%
\tikz[line cap=round,scale=.25]{
\pgfmathparse{\parr[0]}
\draw[black!0] (0,0) -- (0,1) -- (1,1) -- (1,0);
\ifnum\pgfmathresult=1
\draw (0,0) -- (0,1);
\fi
\pgfmathparse{\parr[1]}
\ifnum\pgfmathresult=1
\draw (1,0) -- (1,1);
\fi
\pgfmathparse{\parr[2]}
\ifnum\pgfmathresult=1
\draw (0,1) -- (1,1);
\fi
\pgfmathparse{\parr[3]}
\ifnum\pgfmathresult=1
\draw (0,0) -- (1,0);
\fi
\pgfmathparse{\parr[4]}
\ifnum\pgfmathresult=1
\draw (0,0) -- (1,1);
\fi
\pgfmathparse{\parr[5]}
\ifnum\pgfmathresult=1
\draw (1,0) -- (0,1);
\fi
}%
}
\begin{document}
\piercebox{1,0,0,0,0,0}
\piercebox{0,1,0,0,0,0}
\piercebox{0,0,1,0,0,0}
\piercebox{0,0,0,1,0,0}
\piercebox{0,0,0,0,1,0}
\piercebox{0,0,0,0,0,1}
\bigskip
\piercebox{1,1,1,1,1,1}
\piercebox{1,1,1,0,1,1}
\piercebox{1,0,1,1,1,1}
\piercebox{0,1,1,1,1,1}
\piercebox{1,1,0,1,1,1}
\piercebox{0,1,0,1,1,1}
\piercebox{1,0,0,1,1,1}
\piercebox{1,1,0,0,1,1}
\piercebox{0,0,1,1,1,1}
\piercebox{0,1,1,0,1,1}
\piercebox{1,0,1,0,1,1}
\piercebox{0,0,1,0,1,1}
\piercebox{1,0,0,0,1,1}
\piercebox{0,1,0,0,1,1}
\piercebox{0,0,0,1,1,1}
\piercebox{0,0,0,0,1,1}
\end{document}
得出的结果是:
答案2
图片模式来救援:
\documentclass{article}
\newcommand\zz[6]{%
\begin{picture}(10,10)
\ifnum#1=1 \put(0,0){\line(1,0){10}}\fi
\ifnum#2=1 \put(10,0){\line(0,1){10}}\fi
\ifnum#3=1 \put(0,10){\line(1,0){10}}\fi
\ifnum#4=1 \put(0,0){\line(0,1){10}}\fi
\ifnum#5=1 \put(0,0){\line(1,1){10}}\fi
\ifnum#6=1 \put(0,10){\line(1,-1){10}}\fi
\end{picture}}
\begin{document}
\zz111111 + \zz010101 + \zz000011 + \zz111110
\end{document}
答案3
主题的变体picture
。这提供了适应当前字体大小的符号。需要较小的符号,例如文章中的表 5。
\documentclass{article}
\usepackage{amsmath}
\usepackage{pict2e}
\makeatletter
\DeclareRobustCommand{\peirceconn}[1]{%
% #1 = four bit binary number: top, left, right, bottom
% 0 = false, 1 = true
\mathrel{\mathpalette\peirce@conn{#1}}%
}
\newcommand{\peirce@conn}[2]{%
\peirce@@conn#1#2....\@nil
}
\def\peirce@@conn#1#2#3#4#5#6\@nil{
\settoheight{\unitlength}{$#1F$}
\begin{picture}(1.2,1)
\roundcap
\peirce@linethickness{#1}
\ifnum#2=0 % top is false
\Line(0.1,1)(1.1,1)
\fi
\ifnum#3=0 % left is false
\Line(0.1,0)(0.1,1)
\fi
\ifnum#4=0 % right is false
\Line(1.1,0)(1.1,1)
\fi
\ifnum#5=0 % bottom is false
\Line(0.1,0)(1.1,0)
\fi
\Line(0.1,0)(1.1,1)
\Line(0.1,1)(1.1,0)
\end{picture}
}
\newcommand{\peirce@linethickness}[1]{%
\linethickness{%
\fontdimen8
\ifx#1\displaystyle\textfont\else
\ifx#1\textstyle\textfont\else
\ifx#1\scriptstyle\scriptfont\else
\scriptscriptfont\fi\fi\fi 3
}%
}
\makeatother
\begin{document}
$\peirceconn{0000}$
$\peirceconn{0001}$
$\peirceconn{0010}$
$\peirceconn{0100}$
$\peirceconn{1000}$
$\peirceconn{1100}$
$\peirceconn{1010}$
$\peirceconn{1001}$
$\peirceconn{0110}$
$\peirceconn{0101}$
$\peirceconn{0011}$
$\peirceconn{0111}$
$\peirceconn{1011}$
$\peirceconn{1101}$
$\peirceconn{1110}$
$\peirceconn{1111}$
$x\peirceconn{1111}y\frac{x\peirceconn{1110}y}{x\peirceconn{0001}y}$
\footnotesize
$x\peirceconn{0101}y$
\Large
$x\peirceconn{1010}y$
\end{document}
与原表比较