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如何在 tikz 中将直角三角形定义为节点

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如何在 tikz 中将直角三角形定义为节点

为了得到等边三角形我使用

\tikzstyle{triangle} = [fill=green!20, regular polygon, regular polygon sides=3]

但我正在努力定义直角三角形的 tikz 节点

我想做这样的事

\tikzstyle{anytriangle} = [draw, A--B--C--A]

进而

\begin{tikzpicture}[ auto, node distance=4em]

% Gridline
\draw [step=0.5cm,draw=gray] (-4,-4) grid (4,4);

\coordinate (A) at (0,0);
\coordinate (B) at (4,0);
\coordinate (C) at (0,4);

\node [anytriangle] {};

\end{tikzpicture}

但是我收到一个错误：未知坐标 A

答案1

也许是这样的（但我不得不承认我不完全明白你想要实现什么）：

\documentclass[tikz]{standalone}

\begin{document}

\tikzset{triangle/.append style={fill=green!20, regular polygon, regular polygon sides=3},
         anytriangle/.append style={draw, append after command={ \pgfextra{ \draw (A) -- (B) -- (C) -- (A); } }}}

\begin{tikzpicture}[auto, node distance=4em]

% Gridline
\draw [step=0.5cm,draw=gray] (-4,-4) grid (4,4);

\coordinate (A) at (0,0);
\coordinate (B) at (4,0);
\coordinate (C) at (0,4);

\node [anytriangle] {};

\end{tikzpicture}

\end{document}

答案2

您可以使用isosceles triangle带有 的形状apex angle=90。

\documentclass[tikz,border=2mm]{standalone} 
\usetikzlibrary{positioning, shapes.geometric}

\begin{document}
\begin{tikzpicture}[
    right angle triangle/.style={
        isosceles triangle,
        isosceles triangle apex angle=90},
    every node/.style={right angle triangle, 
        draw, inner sep=0pt,
        anchor=left corner,
        shape border rotate=90},
    paint/.style={draw=#1!75, fill=#1!20}
    ]


\draw[help lines] grid (5,2);

\foreach \a/\c in {1.5/blue, 1/green, 0.5/red}{
    \node[paint=\c, minimum width=\a cm] at (0,0) {};
    \node[paint=\c, minimum height=\a cm] at (2,0) {};
    }

\begin{scope}[yshift=-3cm,
    every node/.style={
        right angle triangle,
        isosceles triangle stretches=false,
        draw, inner sep=0pt,
        minimum height=1cm,
        anchor=apex}
    ]
\draw[help lines] (0,0) grid (2,2);
\foreach \a/\c in {45/blue, 135/green,225/red,315/orange}
     \node[paint=\c, 
        shape border rotate=\a] at (1,1) {};

\end{scope}
\end{tikzpicture}
\end{document}

在此处输入图片描述

答案3

从你的问题中我了解到你正在寻找这个：

在此处输入图片描述

我用大头针标记了坐标 A、B 和 C（您可以看到，那个三角形与它完全匹配。

对于上述图片我建议两种解决方案：

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{shapes.geometric}

\begin{document}
    \begin{tikzpicture}[
trian/.style = {isosceles triangle,
     isosceles triangle apex angle=90,
     minimum size=4cm/sqrt(2), inner sep=0pt,
     anchor=east,rotate=-135,
     draw, fill=green!20}
                        ]
\coordinate[pin=below:A] (A) at (0,0);
\coordinate[pin=below:B] (B) at (4,0);
\coordinate[pin=C]       (C) at (0,4);
%
\node [trian] {};
    \end{tikzpicture}
\end{document}
  • 带有小图片（\pic），它不是节点，但具有类似的特征（从可能的节点锚点中我仅将三个角定义为-a，-b和˙-c`）：

\documentclass[tikz, margin=3mm]{standalone}

\begin{document}
    \begin{tikzpicture}[
trian/.pic = {
    \draw [fill=green!20]
        (0,0) coordinate (-a) --
        (4,0) coordinate (-b) --
        (0,4) coordinate (-c) -- cycle;
            }
                        ]
\coordinate[pin=below:A] (A) at (0,0);
\coordinate[pin=below:B] (B) at (4,0);
\coordinate[pin=C]       (C) at (0,4);
%
\pic[above right] at (A) {trian};
    \end{tikzpicture}
\end{document}

两种情况下的结果都是一样的

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