$ rm foobar
rm: remove regular file `foobar'?
文件“常规”意味着什么?为什么将rm
此类文件视为特殊情况?
答案1
测试命令
任何通过测试(-f
)的文件都是常规文件:
$ test -f afile.zip && echo regular
regular
如果您查看手册页,test
您将看到所有各种类型的文件。
统计命令
您还可以使用以下命令检查文件是否正常stat
:
$ stat afile.zip
File: `afile.zip'
Size: 1512 Blocks: 8 IO Block: 4096 regular file
Device: fd02h/64770d Inode: 10370668 Links: 1
Access: (0664/-rw-rw-r--) Uid: ( 500/ saml) Gid: ( 501/ saml)
Access: 2013-11-07 15:52:06.719632792 -0500
Modify: 2013-11-07 15:52:00.949760104 -0500
Change: 2013-11-07 15:52:00.949760104 -0500
stat() 函数
要了解有关常规文件和其他可能类型之间的区别的更多信息,请查看stat
.请务必查看程序员手册的手册页,而不是实际stat
命令的手册页。
$ man 2 stat
本节特别显示了各种类型的文件:
The following flags are defined for the st_mode field:
S_IFMT 0170000 bit mask for the file type bit fields
S_IFSOCK 0140000 socket
S_IFLNK 0120000 symbolic link
S_IFREG 0100000 regular file
S_IFBLK 0060000 block device
S_IFDIR 0040000 directory
S_IFCHR 0020000 character device
S_IFIFO 0010000 FIFO
S_ISUID 0004000 set UID bit
S_ISGID 0002000 set-group-ID bit (see below)
S_ISVTX 0001000 sticky bit (see below)
S_IRWXU 00700 mask for file owner permissions
S_IRUSR 00400 owner has read permission
S_IWUSR 00200 owner has write permission
S_IXUSR 00100 owner has execute permission
S_IRWXG 00070 mask for group permissions
S_IRGRP 00040 group has read permission
S_IWGRP 00020 group has write permission
S_IXGRP 00010 group has execute permission
S_IRWXO 00007 mask for permissions for others (not in group)
S_IROTH 00004 others have read permission
S_IWOTH 00002 others have write permission
S_IXOTH 00001 others have execute permission
答案2
我认为rm
可能是一个别名rm -i
。 “常规”部分并不意味着任何特殊的东西,它只意味着它不是管道、设备、套接字或任何其他“特殊”的东西。