在柯西序列上画两条包络线

Question

我想画两条像第二张图那样的红虚线。

\documentclass{minimal}
\usepackage{tikz,pgfplots}
\begin{document}
\begin{tikzpicture}
     \draw[->] (-0.2,0) -- (4.5,0) node[right] {$x$};
     \draw[->] (0,-1.2) -- (0,2.5) node[above] {$f(x)$};
     \draw[dash pattern=on 0pt off 2\pgflinewidth,line cap=round,line width=0.5mm,color=blue,domain=0:4,samples=100]  plot (\x,{1+ sin(10*\x r)*e^(-\x)})  ;
\end{tikzpicture}

\end{document}

Answer 1

您想要的行是您的初始函数的“周围的行”（我不知道名称）。

该sin(x)函数总是在 -1 和 1 之间......所以，数学表明：

 1+ sin(10*\x r)*e^(-\x)

总是在之间

1+ (+1)*e^(-\x) 

和

1+ (-1)*e^(-\x)


\documentclass{minimal}
\usepackage{tikz,pgfplots}
\begin{document}
\begin{tikzpicture}
     \draw[->] (-0.2,0) -- (4.5,0) node[right] {$x$};
     \draw[->] (0,-1.2) -- (0,2.5) node[above] {$f(x)$};
     \draw[dash pattern=on 0pt off 2\pgflinewidth,line cap=round,line width=0.5mm,color=blue,domain=0:4,samples=100]  plot (\x,{1+ sin(10*\x r)*e^(-\x)})  ;
     \draw[dash pattern=on 0pt off 2\pgflinewidth,line cap=round,line width=0.5mm,color=red,dashed,thin,domain=0:4,samples=100]  plot (\x,{1+e^(-\x)})  ;
      \draw[dash pattern=on 0pt off 2\pgflinewidth,line cap=round,line width=0.5mm,color=red,dashed,thin,domain=0:4,samples=100]  plot (\x,{1-e^(-\x)})  ;
\end{tikzpicture}

\end{document}