我尝试多次编写此文本,但发现错误missing $
。您能帮我编写此文本吗?
C & = n L \nonumber \\
& = n 2 R \sin(\phi/n) \nonumber \\ \intertext{As :} \nonumber \\
\phi & = 2\pi/n \nonumber \\ \intertext{Thus :} \nonumber \\
C & = 2 n R \sin(\pi/n) \\ \intertext{If n\mapsto\infty (It's mean a polygon with infinite sides) we find :} \nonumber \\
C_{\infty} & = 2R \lim_{n\to \infty} n\sin(\phi/n) \nonumber \\ \intertext{Thus :} \nonumber \\
C_{\infty} & = 2\pi R \nonumber
答案1
您需要使用数学模式进行内部数学运算\intertext
。这样的行既不需要也不\nonumber
需要\\
。
更适合用于\shortintertext
短线。
\documentclass[a4paper]{article}
\usepackage{amsmath,mathtools}
\begin{document}
\begin{align}
C & = n L \nonumber \\
& = n 2 R \sin(\phi/n) \nonumber \\
\shortintertext{As:}
\phi & = 2\pi/n \nonumber \\
\shortintertext{Thus:}
C & = 2 n R \sin(\pi/n) \\
\intertext{If $n\to\infty$ (meaning a polygon with infinite sides) we find:}
C_{\infty} & = 2R \lim_{n\to \infty} n\sin(\phi/n) \nonumber \\
\shortintertext{Thus:}
C_{\infty} & = 2\pi R \nonumber
\end{align}
\end{document}
计算有误,可能应该\sin{\phi/2)
在第二行。\phi
极限中的 应该是\pi
。
另一方面,没有必要对齐所有内容,某些内容应该内联而不是显示。
\documentclass[a4paper]{article}
\usepackage{amsmath,mathtools}
\begin{document}
\begin{align*}
C & = n L\\
& = n\, 2 R \sin(\phi/2)
\end{align*}
As $\phi = 2\pi/n$, we have
\begin{equation}
C = 2 n R \sin(\pi/n)
\end{equation}
If $n\to\infty$ (meaning a polygon with infinitely many sides) we find
\begin{equation*}
C_{\infty} = 2R \lim_{n\to \infty} n\sin(\pi/n)
\end{equation*}
and therefore
\begin{equation*}
C_{\infty} = 2\pi R
\end{equation*}
\end{document}