\vspace{}
我有以下代码,但即使在使用之后也无法删除表格前的空白\subsection{Nomenclature}
。
\section{Mathematical Modeling}
In this section we present the mixed integer linear programming (MILP) models that form the basis of decision-making and the subsequent computational testing. We first present a listing of notation used, then we present the UC-SOC model that corresponds to current practice / state-of-the art benchmark, and finally we present the new model being proposed in this paper.
\subsection{Nomenclature}\label{nom}
\vspace{-6.17mm}
\begin{table}[H]
\begin{tabular}{>{$}l<{$} l}
\multicolumn{2}{l}{\textit{A. Indices and Sets}}\\
\\
t & Index of time period, with $t \in T$, the set of time periods.\\
s &Index of supplier, with $s \in S$, the set of suppliers .\\
j &Index of customer, with $j \in J$, the set of customers.\\
k &Index of attribute, with $k \in K$, the set of attributes, $k$ = 1 denotes fixed payment,\\
& $k$ = 2 denotes variable payment, $k$ = 3 denotes interruption ceiling.\\
%k =1 denotes fixed payments to customers,\\
%k =2 denotes interruption ceiling.\\ %need to find out 5_12
\ell_k &Index of level of $k^{th}$ attribute, with $\ell_k$ $\in$ $L_k$, the set of levels for attribute $k$.\\%need to find out 5_12
SOC &Set of SOC customers\\
\\
\end{tabular}
\end{center}
\end{table}
答案1
一个常见的误解是,atabular
必须放在table
环境中。事实并非如此,它可以放在环境中。任何地方。
在展示代码之前需要注意一些事项。
- 斜线周围没有空格
- 句号前没有空格
- 第一列中的大多数条目应位于
$
符号之间 $k$ = 1
应该$k=1$
$k^{th}$
应该是$k$\textsuperscript{th}
,或者更好的是,$k$th
$\ell_k$ $\in$ $L_k$
应该是一个单一的公式$\ell_k\in L_k$
这是代码,我只是猜测了第二列的宽度值。
\documentclass{article}
\begin{document}
\section{Mathematical Modeling}
In this section we present the mixed integer linear programming (MILP)
models that form the basis of decision-making and the subsequent
computational testing. We first present a listing of notation used,
then we present the UC-SOC model that corresponds to current
practice/state-of-the art benchmark, and finally we present the new
model being proposed in this paper.
\subsection{Nomenclature}\label{nom}
\begin{center}
\begin{tabular}{lp{.5\textwidth}}
\multicolumn{2}{l}{\textit{A. Indices and Sets}}\\
\\
$t$ & Index of time period, with $t \in T$, the set of time periods.\\
$s$ & Index of supplier, with $s \in S$, the set of suppliers.\\
$j$ & Index of customer, with $j \in J$, the set of customers.\\
$k$ & Index of attribute, with $k \in K$, the set of attributes,
$k = 1$ denotes fixed payment, $k = 2$ denotes variable payment,
$k = 3$ denotes interruption ceiling.\\
$\ell_k$ & Index of level of $k$\textsuperscript{th} attribute,
with $\ell_k\in L_k$, the set of levels for attribute $k$.\\
SOC & Set of SOC customers\\
\end{tabular}
\end{center}
\end{document}
答案2
感谢大家。以下解决方案有效。请注意,表格中的额外空白行 ( \\
) 已被删除,并\centering
用于代替中心。
\subsection{Nomenclature}\label{nom}
\begin{table}[H]
\centering
\begin{tabular}{>{$}l<{$} l}%for math mode in table
\multicolumn{2}{l}{\textit{A. Indices and Sets}}\\
%\\
t & Index of time period, with $t \in T$, the set of time periods.\\
s &Index of supplier, with $s \in S$, the set of suppliers .\\
j &Index of customer, with $j \in J$, the set of customers.\\
k &Index of attribute, with $k \in K$, the set of attributes, $k= 1 $denotes fixed payment,\\
& $k = 2$ denotes variable payment, $k = 3$ denotes interruption ceiling.\\
%k =1 denotes fixed payments to customers,\\
%k =2 denotes interruption ceiling.\\ %need to find out 5_12
\ell_k &Index of level of $k$\textsuperscript{th} attribute, with $\ell_k \in L_k$, the set of levels for attribute $k$.\\%need to find out 5_12
SOC &Set of SOC customers\\
\\
\end{tabular}
\end{table}