我怎样才能强制“他的”这个词与其他单词保持在同一水平？

Question

我怎样才能尊重边距？正如您在图中看到的，“他的”这个词超出了边距。我怎样才能正确地放置所有单词？

这是代码：

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\begin{document}
    \begin{frame}
\frametitle{The Kelly Criterion - Gambling}
Since the probabilities and the payoffs are all the same in each bet, it seems likely that the gambler will always wager the same fraction \textit{f} of his bankroll. \\ Then, the quantity  $B_{i}$, called \textit{fixed fraction bet}, that he wagers in each bet is: $$B_{i}=f \smallskip W_{i-1},$$ where $0 \leq f \leq 1$. \\
Let \textit{S} and \textit{F} the number of successes and losses. \\Then, the capital  of the gambler after \textit{n} trials is: \\
$$W_{n} =W_{0}(1+f)^{S}(1-f)^{F}$$ 

\end{frame}
\end{document}

Answer 1

它实际上并没有超出范围，但我同意这是一个糟糕的突破。

只需加一条领带即可。

\documentclass[10pt]{beamer}

\setbeamerfont{structure}{family=\rmfamily}
\beamertemplatenavigationsymbolsempty
\setbeamertemplate{blocks}[rounded][shadow=true]
\setbeamertemplate{bibliography item}[text]
\setbeamertemplate{caption}[numbered]

\usetheme{default}
\usecolortheme{seahorse}

\begin{document}

\begin{frame}
\frametitle{The Kelly Criterion -- Gambling}

Since the probabilities and the payoffs are all the same in each bet,
it seems likely that the gambler will always wager the same fraction~$f$ of his~bankroll.

Then, the quantity  $B_{i}$, called \emph{fixed fraction bet}, that he wagers in each bet is
\[
B_{i}=f \, W_{i-1},
\]
where $0 \leq f \leq 1$.

Let $S$ and $F$ be the number of successes and losses.

Then, the capital  of the gambler after $n$ trials is
\[
W_{n} =W_{0}(1+f)^{S}(1-f)^{F}
\]

\end{frame}

\end{document}

我做了一些修复：

• \textit{f}和类似的应该是$f$（它是数学）；
• 我删除了显示方程式前的冒号（样式不好）；
• 我改成$$...$$了合适的\[...\]；
• 我变成\smallskip了\,（前者没有按照你希望的方式运行）；
• \textit为强调最好是\emph。

您定义的命令会有几点注释。

Answer 2

您可以使用包中的环境\raggedright临时对齐相关段落，而不是使用默认值。环境会在后面插入垂直空间以区别于其他段落。为了删除这个垂直空间，我直接在后面使用。justifyragged2ejustify\unskip\end{justify}

\documentclass[10pt]{beamer}
\usepackage{amsthm}
\usepackage{ragged2e}

\begin{document}

\begin{frame}{The Kelly Criterion - Gambling}
  \begin{justify}
    Since the probabilities and the payoffs are all the same in each
    bet, it seems likely that the gambler will always wager the same
    fraction $f$ of his bankroll.
  \end{justify}
  \unskip
  Then, the quantity $B_{i}$, called \emph{fixed fraction bet}, that
  he wagers in each bet is:
  \begin{equation*}
    B_{i}=f \, W_{i-1},
  \end{equation*}
  where $0 \leq f \leq 1$.

  Let $S$ and $F$ the number of successes and losses.

  Then, the capital of the gambler after $n$ trials is:
  \begin{equation*}
    W_{n} =W_{0}(1+f)^{S}(1-f)^{F}
  \end{equation*}
\end{frame}

\end{document}