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修改“texample.net”中 Jang Soo Kim 的示例 Plane 分区代码

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修改“texample.net”中 Jang Soo Kim 的示例 Plane 分区代码

从答案到这个问题，是否可以将下方的立方体位置设为空，以创建此绘图

\documentclass{beamer}
\setbeamertemplate{navigation symbols}{}% to suppresses (hide) navigation symbols bar
\usepackage{tikz}
\usepackage{verbatim}
% Three counters
\newcounter{x}
\newcounter{y}
\newcounter{z}
% The angles of x,y,z-axes
\newcommand\xaxis{210}
\newcommand\yaxis{-30}
\newcommand\zaxis{90}
% The top side of a cube
\newcommand\topside[3]{
  \fill[fill=yellow, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (30:1) -- (0,1) --(150:1)--(0,0);
}
% The left side of a cube
\newcommand\leftside[3]{
  \fill[fill=green, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (0,-1) -- (210:1) --(150:1)--(0,0);
}
% The right side of a cube
\newcommand\rightside[3]{
  \fill[fill=blue, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (30:1) -- (-30:1) --(0,-1)--(0,0);
}
% The cube 
\newcommand\cube[3]{
  \topside{#1}{#2}{#3} \leftside{#1}{#2}{#3} \rightside{#1}{#2}{#3}
}
\newcommand\planepartition[1]{
 \setcounter{x}{-1}
  \foreach \a in {#1} {
\addtocounter{x}{1}
\setcounter{y}{-1}
\foreach \b in \a {
  \addtocounter{y}{1}
  \setcounter{z}{-1}
 \ifnum \b>0
  \foreach \c in {1,...,\b} {
   \addtocounter{z}{1}
   \cube{\value{x}}{\value{y}}{\value{z}}
}\fi}}}
\begin{document} 
\begin{tikzpicture}
\planepartition{{2,1,2,1,2,1,2},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{2,1,2,1,2,1,2}}%1st column from back to front{row1,... from left to right}%0 is the same as 2% it does not allow void for 0
\end{tikzpicture}
\end{document}

在此处输入图片描述

答案1

在这种情况下，逐层构建就足够了（逐层）从最低到最高。

为此，我修改了循环，添加了一个0默认设置为的可选参数。这样您就可以保留以前图形的旧语法。

这个可选参数只是添加到z循环中的计数器：

\addtocounter{z}{#1}

默认情况下，此参数是0和旧代码一样构建分区，即在底层。

  • 当此参数等于时1，它会在上一层构建一个分区。
  • 当它等于时2，它会在上面建造两层，等等。

总是可以构建多个层（或楼层）与旧代码同时。

\newcommand\planepartition[2][0]{
 \setcounter{x}{-1}
  \foreach \a in {#2} {
        \addtocounter{x}{1}
        \setcounter{y}{-1}
            \foreach \b in \a {
            \addtocounter{y}{1}
            \setcounter{z}{-1}
            \addtocounter{z}{#1} %partition of the desired floor (layer)
            \ifnum \b>0
            \foreach \c in {1,...,\b} {
                \addtocounter{z}{1}
                \cube{\value{x}}{\value{y}}{\value{z}}
      }\fi
    }
  }
}

立方体

\documentclass{beamer}
\setbeamertemplate{navigation symbols}{}% to suppresses (hide) navigation symbols bar
\usepackage{tikz}
\usepackage{verbatim}
% Three counters
\newcounter{x}
\newcounter{y}
\newcounter{z}
% The angles of x,y,z-axes
\newcommand\xaxis{210}
\newcommand\yaxis{-30}
\newcommand\zaxis{90}
% The top side of a cube
\newcommand\topside[3]{
  \fill[fill=yellow,fill opacity=.7, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}] (0,0) -- (30:1) -- (0,1) --(150:1)--(0,0);
}
% The left side of a cube
\newcommand\leftside[3]{
  \fill[fill=green,fill opacity=.7, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}] (0,0) -- (0,-1) -- (210:1) --(150:1)--(0,0);
}
% The right side of a cube
\newcommand\rightside[3]{
  \fill[fill=blue,fill opacity=.7, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}] (0,0) -- (30:1) -- (-30:1) --(0,-1)--(0,0);
}
% The cube 
\newcommand\cube[3]{
  \topside{#1}{#2}{#3} \leftside{#1}{#2}{#3} \rightside{#1}{#2}{#3}
}
% Definition of \planepartition
% To draw the following plane partition, just write \planepartition{ {a, b, c}, {d,e} }.
%  a b c
%  d e
\newcommand\planepartition[2][0]{
 \setcounter{x}{-1}
  \foreach \a in {#2} {
        \addtocounter{x}{1}
        \setcounter{y}{-1}
            \foreach \b in \a {
            \addtocounter{y}{1}
            \setcounter{z}{-1}
            \addtocounter{z}{#1} %partition of the desired floor (layer)
            \ifnum \b>0
            \foreach \c in {1,...,\b} {
                \addtocounter{z}{1}
                \cube{\value{x}}{\value{y}}{\value{z}}
      }\fi
    }
  }
}
\begin{document} 


\begin{tikzpicture}% Old syntax is functional
\planepartition{{2,1,2,1,2,1,2},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{2,1,2,1,2,1,2}}
\end{tikzpicture}
\begin{tikzpicture}% The optional argument allow to build layer by layer
\planepartition{{1,1,0,1,0,1,1},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{1,1,0,1,0,1,1}}
\planepartition[1]{{1,0,1,0,1,0,1},{0,0,0,0,0,0,0},{0,0,0,0,0,0,0},{0,0,0,0,0,0,0},{1,0,1,0,1,0,1}}
\end{tikzpicture}
\end{document}

答案2

是的。我添加了一个可选参数，表示要跳过多少个框。这2/1意味着两个框，但跳过第一个。

\documentclass{beamer}
\setbeamertemplate{navigation symbols}{}% to suppresses (hide) navigation symbols bar
\usepackage{tikz}
\usepackage{verbatim}
% Three counters
\newcounter{x}
\newcounter{y}
\newcounter{z}
% The angles of x,y,z-axes
\newcommand\xaxis{210}
\newcommand\yaxis{-30}
\newcommand\zaxis{90}
% The top side of a cube
\newcommand\topside[3]{
  \fill[fill=yellow, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (30:1) -- (0,1) --(150:1)--(0,0);
}
% The left side of a cube
\newcommand\leftside[3]{
  \fill[fill=green, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (0,-1) -- (210:1) --(150:1)--(0,0);
}
% The right side of a cube
\newcommand\rightside[3]{
  \fill[fill=blue, draw=black,shift={(\xaxis:#1)},shift={(\yaxis:#2)},
  shift={(\zaxis:#3)}, opacity=.7] (0,0) -- (30:1) -- (-30:1) --(0,-1)--(0,0);
}
% The cube 
\newcommand\cube[3]{
  \topside{#1}{#2}{#3} \leftside{#1}{#2}{#3} \rightside{#1}{#2}{#3}
}
\newcommand\planepartition[1]{
 \setcounter{x}{-1}
  \foreach \a in {#1} {
\addtocounter{x}{1}
\setcounter{y}{-1}
\foreach \b/\d in \a {
  \addtocounter{y}{1}
  \setcounter{z}{-1}
 \ifnum\b>0
  \ifnum\b=\d
   \foreach \c in {1,...,\b} {
    \addtocounter{z}{1}
    \cube{\value{x}}{\value{y}}{\value{z}}}
   \else
   \pgfmathtruncatemacro{\cmin}{1+\d}
   \addtocounter{z}{\d}
   \foreach \c in {\cmin,...,\b} {
    \addtocounter{z}{1}
    \cube{\value{x}}{\value{y}}{\value{z}}}
   \fi
  \fi}}}
\begin{document} 
\begin{tikzpicture}
\planepartition{{2,1,2/1,1,2/1,1,2},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{1,0,0,0,0,0,1},{2,1,2/1,1,2/1,1,2}}%1st column from back to front{row1,... from left to right}%0 is the same as 2% it does not allow void for 0
\end{tikzpicture}
\end{document}

在此处输入图片描述

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