答案1
欢迎使用 TeX-SE!是的,可以用 Ti 绘制这些东西钾Z. 我将子弹形状存储在这样一种pic
位置,如果您想改变这种形状,只需要改变一次。
\documentclass[tikz,border=3.14mm]{standalone}
\begin{document}
\begin{tikzpicture}[pics/bullet/.style={code={
\draw[#1] (-0.5,-0.2) to[out=0,in=-150] (0.5,0) to[out=150,in=0] (-0.5,0.2) --
cycle;}},
pics/bullet/.default={fill=white},font=\sffamily]
\begin{scope}[local bounding box=YAW]
\draw (0,0) -- (6,0) pic[pos=0.15,rotate=180]{bullet}
pic[pos=0.325,rotate=135]{bullet} pic[pos=0.5,rotate=180]{bullet}
pic[pos=0.675,rotate=225]{bullet} pic[pos=0.85,rotate=180]{bullet};
\end{scope}
\node[below right] at (0,0|-YAW.south) {YAW};
\begin{scope}[local bounding box=PRECESSION,yshift=-2.5cm]
\draw plot[smooth,variable=\t,domain=0:5.05,samples=301] ({\t+0.15*sin(\t*1200)},
{\t*cos(\t*1200)/8});
\draw (0,0) -- (6,0) pic[pos=0.9,rotate=150]{bullet={fill=gray!50}}
pic[pos=0.9,rotate=225]{bullet};
\end{scope}
\node[below right] at (0,0|-PRECESSION.south) {PRECESSION};
\begin{scope}[local bounding box=NUTATION,yshift=-5cm]
\draw plot[smooth,variable=\t,domain=0:360,samples=101]
({1+0.6*cos(\t)+0.2*cos(10*\t)},
{0.6*sin(\t)+0.2*sin(10*\t)});
\draw plot[smooth,variable=\t,domain=0:360,samples=101]
({4+0.7*cos(\t)+0.2*cos(10*\t)},
{0.7*sin(\t)+0.2*sin(10*\t)});
\fill (1,0) circle[radius=2pt] (4,0) circle[radius=2pt];
\end{scope}
\node[below right] at (0,0|-NUTATION.south) {NUTATION};
\end{tikzpicture}
\end{document}