tikz块对角线划分

Question

我正在尝试绘制下图：

我目前能做的是：

代码：

\documentclass[tikz,border=20pt]{standalone}

\usetikzlibrary{shapes,arrows}
\usetikzlibrary{decorations.pathreplacing}
\usetikzlibrary{babel}
\usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
\usetikzlibrary{shapes.multipart}

\tikzstyle{block} = [draw, rectangle, rounded corners, minimum size=1cm, text centered]
\tikzstyle{transform} = [draw, block, path picture={\draw (path picture bounding box.south west)--(path picture bounding box.north east);}]
\tikzstyle{state} = [draw, rectangle split,rectangle split parts=2,rounded corners, minimum size=1cm, text centered]

\begin{document}

\begin{tikzpicture}
    \node at (0.0,0.0) [transform](inverter){$qd0$};
    \node at (2.0,0.0) [state] {$qd0$ \nodepart{two} $abc$};
\end{tikzpicture}

\end{document}

我需要一些帮助 ：）

Answer 1

计算很简单，

如果您考虑使用pic而不是完整的节点形状，那么实现也很简单。自由参数被视为完整形状的高度。然后以对角线不切割任何节点的方式计算宽度（其中“安全距离”由 给出）inner sep。

\documentclass{article}
\usepackage{tikz}
\tikzset{pics/dbox/.style 2 args={code={%
\pgfmathsetmacro{\w}{max((width("#1")+2*\pgfkeysvalueof{/pgf/inner xsep})/(\pgfkeysvalueof{/tikz/dbox/height}-2*\pgfkeysvalueof{/pgf/inner xsep}-height("#1")),%
(width("#2")+2*\pgfkeysvalueof{/pgf/inner xsep})/(\pgfkeysvalueof{/tikz/dbox/height}-2*\pgfkeysvalueof{/pgf/inner xsep}-height("#2")))*\pgfkeysvalueof{/tikz/dbox/height}}
\path[pic actions] (-\w*1pt/2,-\pgfkeysvalueof{/tikz/dbox/height}/2) 
 node[above right] {#2}
 rectangle
(\w*1pt/2,\pgfkeysvalueof{/tikz/dbox/height}/2)
 node[below left] {#1} (-\w*1pt/2,\pgfkeysvalueof{/tikz/dbox/height}/2)
 -- (\w*1pt/2,-\pgfkeysvalueof{/tikz/dbox/height}/2) ;
}},dbox/.cd,height/.initial=2cm}
\begin{document}
\begin{tikzpicture}
 \path pic[draw]{dbox={abc}{xyzuv}} (3,0) pic[draw,blue]{dbox={abc}{xyz}}
 (6,0) pic[draw,red,thick]{dbox={abcdefgh}{xyz}};
\end{tikzpicture}
\end{document}

您可以使用一个简单的技巧为该形状赋予通常的锚点：只需使用 将其转换为节点即可fit。然后使用 设置名称dbox/name=<name>。

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{fit}
\tikzset{pics/dbox/.style 2 args={code={%
\pgfmathsetmacro{\w}{max((width("#1")+2*\pgfkeysvalueof{/pgf/inner xsep})/(\pgfkeysvalueof{/tikz/dbox/height}-2*\pgfkeysvalueof{/pgf/inner xsep}-height("#1")),%
(width("#2")+2*\pgfkeysvalueof{/pgf/inner xsep})/(\pgfkeysvalueof{/tikz/dbox/height}-2*\pgfkeysvalueof{/pgf/inner xsep}-height("#2")))*\pgfkeysvalueof{/tikz/dbox/height}}
\path (-\w*1pt/2,-\pgfkeysvalueof{/tikz/dbox/height}/2) 
 node[above right] (bl) {#2}
 rectangle
(\w*1pt/2,\pgfkeysvalueof{/tikz/dbox/height}/2)
 node[below left] (tr) {#1};
 \node[pic actions,inner sep=0pt,fit=(bl)(tr),path picture={\path[pic actions]
 (path picture bounding box.north west)
 -- (path picture bounding box.south east);}] 
 (\pgfkeysvalueof{/tikz/dbox/name}){};
}},dbox/.cd,height/.initial=2cm,name/.initial=}
\begin{document}
\begin{tikzpicture}
 \path pic[draw]  {dbox={abc}{xyzuv}} (3,0) 
 pic[draw,blue,dbox/name=A] {dbox={abc}{xyz}}
 (6,0) pic[draw,red,thick,rounded corners,dbox/name=B] {dbox={abcdefgh}{xyz}};
 \draw[stealth-stealth] (A.north) to[out=80,in=100](B.100);
\end{tikzpicture}
\end{document}

Answer 2

您是否在寻找像这样的简单代码？从几何角度思考：只是一个（缩放）正方形，里面有一些可以手动调整的文本。

\documentclass[border=5mm]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[xscale=.8,yscale=1.5]
\draw[thick] (1,0)--(0,1) (0,0) rectangle (1,1);
\path[magenta] 
(0,0)+(.3,.3)    node{$dq$}
(1,1)+(-.4,-.15) node{$abc$};
\end{tikzpicture}

\begin{tikzpicture}[xscale=2.5,yscale=1.5]
\draw[thick] (1,0)--(0,1) (0,0) rectangle (1,1);
\path[blue] 
(0,0)+(.2,.15)    node{$TikZ$}
(1,1)+(-.4,-.15)  node{$Asymptote$};
\end{tikzpicture}

\end{document}