\begin{align}\nonumber
(A_{1}^{5}+A_{8}^2)\tt_{m}^{2}\k^{2}P_{m}^{5}-\left(2(A_{1}^{2}+A_{2}^2)
(\Delta_{a}-\omega_{m}\chi^{2}C)\omega_{m}\chi^{2}-2J^{2}\omega_{m}\chi^{2}
(\kappa_{a}A_{2}-\Delta_{d}A_{1})\right)P_{m}^4\\
\nonumber
&&+((\kt_{a}A_{1}+J^{2}\om_{d})^2+
(\kappa_{a}A_{1}+J^{2}\Delta_{d})^2+
(\Delta_{a}-\omega_{m}\chi^{2}C)^2(A_{1}^{5}+A_{7}^2)+2J^{2}(\Delta_{a}-
\omega_{m}\chi^{5}C)(\Delta_{d}A_{1}-\kappa_{a}A_{9}))P_{m}^2\\
\nonumber
&=&\left|\x_{0}\right|^{2}(m_{1}^{2}+n_{2}^5)+2\kp_{0}A_{2}gJ\S
Cos[m]N+J^{2}gk^{2}S^{2}N^{2}
\tag{M1}
\end{align}
答案1
由于您没有提供 MWE(最小工作示例,一个我们可以按原样测试的小型完整文档),我们没有关于您的文档布局、与您的方程式相关的使用的包以及最终定义的新命令或数学运算符的任何信息。
还不清楚为什么你要求方程式的那部分使用\tt
字体(顺便说一句,正确的是\ttfamily
),以及方程式\S
中的符号(部分符号)是什么意思(通常用于法律文件)。此外,你使用哪种编码(定义符号在哪里\k
)
通过使用标准article
文档类、字体newtxmath
、包mathtools
和nccmath
,并将您的等式分成四行,我设法得到以下结果:
(红线表示文字边框)
\documentclass{article}
\usepackage{newtxtext,newtxmath}
\usepackage{mathtools,nccmath}
\DeclarePairedDelimiter\abs{\lvert}{\rvert}
\begin{document}
\begin{equation}\tag{M1}
\medmath{
\begin{aligned}
\bigl(A_{1}^{5}
+ & A_{8}^2\bigr)_{m}^{2}k^{2}P_{m}^{5} -
\Bigl(2\bigl(A_{1}^{2}+A_{2}^2\bigr)
\bigl(\Delta_{a} - \omega_{m}\chi^{2}C\bigr)
\omega_{m}\chi^{2}-2J^{2}\omega_{m}\chi^{2}
\bigl(\kappa_{a}A_{2}-\Delta_{d}A_{1}\bigr)\Bigr)P_{m}^4 \\
+ & \Bigl(\bigl(kt_{a}A_{1}+J^{2}om_{d}\bigr)^2+
\bigl(\kappa_{a}A_{1}+J^{2}\Delta_{d}\bigr)^2 +
\bigr(\Delta_{a}-\omega_{m}\chi^{2}C\bigl)^2
\bigl(A_{1}^{5}+A_{7}^2\bigr) \\
+ & 2J^{2}\bigl(\Delta_{a} - \omega_{m}\chi^{5}C\bigr)
\bigl(\Delta_{d}A_{1}-\kappa_{a}A_{9}\bigr)\Bigr)P_{m}^2 \\
= & \abs{x_{0}}^{2}\bigl(m_{1}^{2}+n_{2}^5\bigr) +
2kp_{0}A_{2}gJ\S
Cos[m]N+J^{2}gk^{2}S^{2}N^{2}
\end{aligned}
}
\end{equation}
\end{document}
答案2
您MWE
遇到了一些错误,例如,\k
等等\kt
。我只是\
为了编译目的而删除了它们,修改后的代码如下所示:
\documentclass{book}
\usepackage{mathtools}
\begin{document}
\begin{align}\nonumber
(A_{1}^{5}+A_{8}^2)\tt_{m}^{2}k^{2}P_{m}^{5}&-\left(2(A_{1}^{2}+A_{2}^2)
(\Delta_{a}-\omega_{m}\chi^{2}C)\omega_{m}\chi^{2}-2J^{2}\omega_{m}\chi^{2}
(\kappa_{a}A_{2}-\Delta_{d}A_{1})\right)P_{m}^4\\
&\quad\nonumber
+((kt_{a}A_{1}+J^{2}om_{d})^2+
(\kappa_{a}A_{1}+J^{2}\Delta_{d})^2+
(\Delta_{a}-\omega_{m}\chi^{2}C)^2(A_{1}^{5}+A_{7}^2)\\
&\quad\nonumber+2J^{2}(\Delta_{a}-
\omega_{m}\chi^{5}C)(\Delta_{d}A_{1}-\kappa_{a}A_{9}))P_{m}^2\\
&\nonumber
=\left|x_{0}\right|^{2}(m_{1}^{2}+n_{2}^5)+2kp_{0}A_{2}gJ\S
Cos[m]N+J^{2}gk^{2}S^{2}N^{2}
\tag{M1}
\end{align}
\end{document}
请注意,我已经按照标准格式分解了方程式......