这篇文章中使用 tikz 制作的垂直时间线看起来很棒,但在 beamer 海报中,行距计算错误。tikz 代码来自 szantaii 的回答针对这个问题基于 Tikz 的高级宏和环境,并入本工作示例中:
%\documentclass{article}
%\usepackage{geometry}
\documentclass{beamer}
\usepackage{beamerposter}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, decorations.markings, positioning}
\makeatletter
\newenvironment{timeline}[6]{%
% #1 is startyear
% #2 is tlendyear
% #3 is yearcolumnwidth
% #4 is rulecolumnwidth
% #5 is entrycolumnwidth
% #6 is timelineheight
\newcommand{\startyear}{#1}
\newcommand{\tlendyear}{#2}
\newcommand{\yearcolumnwidth}{#3}
\newcommand{\rulecolumnwidth}{#4}
\newcommand{\entrycolumnwidth}{#5}
\newcommand{\timelineheight}{#6}
\newcommand{\templength}{}
\newcommand{\entrycounter}{0}
% https://tex.stackexchange.com/questions/85528/checking-whether-or-not-a-node-has-been-previously-defined
% https://tex.stackexchange.com/questions/37709/how-can-i-know-if-a-node-is-already-defined
\long\def\ifnodedefined##1##2##3{%
\@ifundefined{pgf@sh@ns@##1}{##3}{##2}%
}
\newcommand{\ifnodeundefined}[2]{%
\ifnodedefined{##1}{}{##2}
}
\newcommand{\drawtimeline}{%
\draw[timelinerule] (\yearcolumnwidth+5pt, 0pt) -- (\yearcolumnwidth+5pt, -\timelineheight);
\draw (\yearcolumnwidth+0pt, -10pt) -- (\yearcolumnwidth+10pt, -10pt);
\draw (\yearcolumnwidth+0pt, -\timelineheight+15pt) -- (\yearcolumnwidth+10pt, -\timelineheight+15pt);
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[year] (year-\startyear) at (\yearcolumnwidth, \templength) {\startyear};
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\tlendyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[year] (year-\tlendyear) at (\yearcolumnwidth, \templength) {\tlendyear};
}
\newcommand{\entry}[2]{%
% #1 is the year
% #2 is the entry text
\pgfmathtruncatemacro{\lastentrycount}{\entrycounter}
\pgfmathtruncatemacro{\entrycounter}{\entrycounter + 1}
\ifdim \lastentrycount pt > 0 pt%
\node[entry] (entry-\entrycounter) [below of=entry-\lastentrycount] {##2};
\else%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[entry] (entry-\entrycounter) at (\yearcolumnwidth+\rulecolumnwidth+10pt, \templength) {##2};
\fi
\ifnodeundefined{year-##1}{%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(##1, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\draw (\yearcolumnwidth+2.5pt, \templength) -- (\yearcolumnwidth+7.5pt, \templength);
\node[year] (year-##1) at (\yearcolumnwidth, \templength) {##1};
}
\draw ($(year-##1.east)+(2.5pt, 0pt)$) -- ($(year-##1.east)+(7.5pt, 0pt)$) -- ($(entry-\entrycounter.west)-(5pt,0)$) -- (entry-\entrycounter.west);
}
\newcommand{\plainentry}[2]{% plainentry won't print date in the timeline
% #1 is the year
% #2 is the entry text
\pgfmathtruncatemacro{\lastentrycount}{\entrycounter}
\pgfmathtruncatemacro{\entrycounter}{\entrycounter + 1}
\ifdim \lastentrycount pt > 0 pt%
\node[entry] (entry-\entrycounter) [below of=entry-\lastentrycount] {##2};
\else%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[entry] (entry-\entrycounter) at (\yearcolumnwidth+\rulecolumnwidth+10pt, \templength) {##2};
\fi
\ifnodeundefined{invisible-year-##1}{%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(##1, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\draw (\yearcolumnwidth+2.5pt, \templength) -- (\yearcolumnwidth+7.5pt, \templength);
\node[year] (invisible-year-##1) at (\yearcolumnwidth, \templength) {};
}
\draw ($(invisible-year-##1.east)+(2.5pt, 0pt)$) -- ($(invisible-year-##1.east)+(7.5pt, 0pt)$) -- ($(entry-\entrycounter.west)-(5pt,0)$) -- (entry-\entrycounter.west);
}
\begin{tikzpicture}
\tikzstyle{entry} = [%
align=left,%
text width=\entrycolumnwidth,%
node distance=10mm,%
anchor=west]
\tikzstyle{year} = [anchor=east]
\tikzstyle{timelinerule} = [%
draw,%
decoration={markings, mark=at position 1 with {\arrow[scale=1.5]{latex'}}},%
postaction={decorate},%
shorten >=0.4pt]
\drawtimeline
}
{
\end{tikzpicture}
\let\startyear\@undefined
\let\tlendyear\@undefined
\let\yearcolumnwidth\@undefined
\let\rulecolumnwidth\@undefined
\let\entrycolumnwidth\@undefined
\let\timelineheight\@undefined
\let\entrycounter\@undefined
\let\ifnodedefined\@undefined
\let\ifnodeundefined\@undefined
\let\drawtimeline\@undefined
\let\entry\@undefined
}
\makeatother
\begin{document}
\begin{timeline}{1940}{2020}{5cm}{2cm}{20cm}{15cm}
\plainentry{1941}{1941 this timeline entry is long enough to continue on a second line}
\plainentry{1946}{1946 this entry gets stepped on}
\plainentry{1947}{1947 this entry is long enough to continue on a second line and then even a third line it is quite the run-on entry that runs on and on and on do you see it run on?}
\plainentry{1947}{This is another entry for the same year}
\plainentry{1948}{1948 1948 1948 1948 1948 1948 1948 1948 1948 1948 1948 }
\plainentry{1951}{1951 some text}
\entry{1955}{1955 some other text}
\entry{1960}{1960 yet more text}
\entry{1970}{1970 and still more}
\entry{2015}{2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 }
\plainentry{2018}{2018 2018 2018 2018 2018 2018 2018 2018 2018 2018 2018}
\end{timeline}
\end{document}
结果如下:
答案1
欢迎使用 TeX.SE。您只需将设置node distance
为适当的量即可获得正确的标签间距。我做到了node distance=20mm
。我将时间线添加到两列框架中,看起来不错。您需要调整节点距离和时间线的长度以满足您的特定需求。
%\documentclass{article}
%\usepackage{geometry}
\documentclass{beamer}
\usepackage[size=custom,height=150,width=90,scale=1]{beamerposter}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, decorations.markings, positioning}
\makeatletter
\newenvironment{timeline}[6]
{
% #1 is startyear
% #2 is tlendyear
% #3 is yearcolumnwidth
% #4 is rulecolumnwidth
% #5 is entrycolumnwidth
% #6 is timelineheight
\newcommand{\startyear}{#1}
\newcommand{\tlendyear}{#2}
\newcommand{\yearcolumnwidth}{#3}
\newcommand{\rulecolumnwidth}{#4}
\newcommand{\entrycolumnwidth}{#5}
\newcommand{\timelineheight}{#6}
\newcommand{\templength}{}
\newcommand{\entrycounter}{0}
% http://tex.stackexchange.com/questions/85528/checking-whether-or-not-a-node-has-been-previously-defined
% http://tex.stackexchange.com/questions/37709/how-can-i-know-if-a-node-is-already-defined
\long\def\ifnodedefined##1##2##3{%
\@ifundefined{pgf@sh@ns@##1}{##3}{##2}%
}
\newcommand{\ifnodeundefined}[2]{%
\ifnodedefined{##1}{}{##2}
}
\newcommand{\drawtimeline}{%
\draw[timelinerule] (\yearcolumnwidth+5pt, 0pt) -- (\yearcolumnwidth+5pt, -\timelineheight);
\draw (\yearcolumnwidth+0pt, -10pt) -- (\yearcolumnwidth+10pt, -10pt);
\draw (\yearcolumnwidth+0pt, -\timelineheight+15pt) -- (\yearcolumnwidth+10pt, -\timelineheight+15pt);
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[year] (year-\startyear) at (\yearcolumnwidth, \templength) {\startyear};
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\tlendyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[year] (year-\tlendyear) at (\yearcolumnwidth, \templength) {\tlendyear};
}
\newcommand{\entry}[2]{%
% #1 is the year
% #2 is the entry text
\pgfmathtruncatemacro{\lastentrycount}{\entrycounter}
\pgfmathtruncatemacro{\entrycounter}{\entrycounter + 1}
\ifdim \lastentrycount pt > 0 pt%
\node[entry] (entry-\entrycounter) [below of=entry-\lastentrycount] {##2};
\else%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[entry] (entry-\entrycounter) at (\yearcolumnwidth+\rulecolumnwidth+10pt, \templength) {##2};
\fi
\ifnodeundefined{year-##1}{%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(##1, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\draw (\yearcolumnwidth+2.5pt, \templength) -- (\yearcolumnwidth+7.5pt, \templength);
\node[year] (year-##1) at (\yearcolumnwidth, \templength) {##1};
}
\draw ($(year-##1.east)+(2.5pt, 0pt)$) -- ($(year-##1.east)+(7.5pt, 0pt)$) -- ($(entry-\entrycounter.west)-(5pt,0)$) -- (entry-\entrycounter.west);
}
\newcommand{\plainentry}[2]{% plainentry won't print date in the timeline
% #1 is the year
% #2 is the entry text
\pgfmathtruncatemacro{\lastentrycount}{\entrycounter}
\pgfmathtruncatemacro{\entrycounter}{\entrycounter + 1}
\ifdim \lastentrycount pt > 0 pt%
\node[entry] (entry-\entrycounter) [below of=entry-\lastentrycount] {##2};
\else%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(\startyear, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\node[entry] (entry-\entrycounter) at (\yearcolumnwidth+\rulecolumnwidth+10pt, \templength) {##2};
\fi
\ifnodeundefined{invisible-year-##1}{%
\pgfmathsetlengthmacro{\templength}{neg(add(multiply(subtract(##1, \startyear), divide(subtract(\timelineheight, 25), subtract(\tlendyear, \startyear))), 10))}
\draw (\yearcolumnwidth+2.5pt, \templength) -- (\yearcolumnwidth+7.5pt, \templength);
\node[year] (invisible-year-##1) at (\yearcolumnwidth, \templength) {};
}
\draw ($(invisible-year-##1.east)+(2.5pt, 0pt)$) -- ($(invisible-year-##1.east)+(7.5pt, 0pt)$) -- ($(entry-\entrycounter.west)-(5pt,0)$) -- (entry-\entrycounter.west);
}
\begin{tikzpicture}
\tikzstyle{entry} = [%
align=left,%
text width=\entrycolumnwidth,%
node distance=20mm,% <-- Adjust this to get wider spacing of the labels
anchor=west]
\tikzstyle{year} = [anchor=east]
\tikzstyle{timelinerule} = [%
draw,%
decoration={markings, mark=at position 1 with {\arrow[scale=1.5]{latex'}}},%
postaction={decorate},%
shorten >=0.4pt]
\drawtimeline
}
{
\end{tikzpicture}
\let\startyear\@undefined
\let\tlendyear\@undefined
\let\yearcolumnwidth\@undefined
\let\rulecolumnwidth\@undefined
\let\entrycolumnwidth\@undefined
\let\timelineheight\@undefined
\let\entrycounter\@undefined
\let\ifnodedefined\@undefined
\let\ifnodeundefined\@undefined
\let\drawtimeline\@undefined
\let\entry\@undefined
}
\makeatother
\begin{document}
\begin{frame}{}
\begin{columns}[t]
\begin{column}{.45\linewidth}
\begin{block}{FOOBAR}
\begin{timeline}{1940}{2020}{5cm}{2cm}{20cm}{20cm}
\plainentry{1941}{1941 this timeline entry is long enough to continue on a second line}
\plainentry{1946}{1946 this entry gets stepped on}
\plainentry{1947}{1947 this entry is long enough to continue on a second line and then even a third line it is quite the run-on entry that runs on and on and on do you see it run on?}
\plainentry{1947}{This is another entry for the same year}
\plainentry{1948}{1948 1948 1948 1948 1948 1948 1948 1948 1948 1948 1948 }
\plainentry{1951}{1951 some text}
\entry{1955}{1955 some other text}
\entry{1960}{1960 yet more text}
\entry{1970}{1970 and still more}
\entry{2015}{2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 2015 }
\plainentry{2018}{2018 2018 2018 2018 2018 2018 2018 2018 2018 2018 2018}
\end{timeline}
\end{block}
\end{column}
\begin{column}{.45\linewidth}
\begin{block}{FOOBAR}
foobar
\end{block}
\end{column}
\end{columns}
\end{frame}
\end{document}