![校准方程错误](https://linux22.com/image/405927/%E6%A0%A1%E5%87%86%E6%96%B9%E7%A8%8B%E9%94%99%E8%AF%AF.png)
我使用该环境\begin{align}...\end{align}
来对齐一些方程式,看起来一切都正确(MWE),但是我收到了以下错误:
软件包 amsmath 错误:多个 \label:标签‘eq:Equat_2’将丢失
问题是什么?
MWE:
\documentclass[a4paper,french,11pt,oneside]{book}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[french]{babel}
%----------------------------------------------------------------
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{bm}
\usepackage{mathtools}
%-----------------------------------------
%\usepackage{a4wide}
\usepackage{amsfonts}
\usepackage{amstext}
\usepackage{amsthm}
\begin{document}
\begin{align}
\mathbf{X}_{i,k|k-1}
& \!\begin{aligned}[t] &=
\hat{\mathbf{x}}_{k|k-1} +\mathbf{S}_{k|k-1}\bm{\xi}_i
\end{aligned}\\
\label{eq:Equat_1}
\mathbf{Y}_{i,k|k-1}
& \!\begin{aligned}[t] &=
\mathbf{h}(\mathbf{X}_{i,k|k-1},\bm{\theta})\\
\end{aligned}\\
\label{eq:Equat_2}
\hat{\mathbf{y}}_{k|k-1}
& \!\begin{aligned}[t] &=
\frac{1}{m}\sum_{i=1}^m \mathbf{Y}_{i,k|k-1}
\end{aligned}
\label{eq:Equat_3}
\end{align}
\end{document}
答案1
问题在于第三个等式中有两个\label
s。以下是代码的注释视图:
\begin{align}
\mathbf{X}_{i,k|k-1}
& \!\begin{aligned}[t] &=
\hat{\mathbf{x}}_{k|k-1} +\mathbf{S}_{k|k-1}\bm{\xi}_i
\end{aligned}\\
\label{eq:Equat_1} % <--- \label for SECOND equation
\mathbf{Y}_{i,k|k-1}
& \!\begin{aligned}[t] &=
\mathbf{h}(\mathbf{X}_{i,k|k-1},\bm{\theta})\\
\end{aligned}\\
\label{eq:Equat_2}% <--- \label for THIRD equation
\hat{\mathbf{y}}_{k|k-1}
& \!\begin{aligned}[t] &=
\frac{1}{m}\sum_{i=1}^m \mathbf{Y}_{i,k|k-1}
\end{aligned}
\label{eq:Equat_3}% <--- \label for THIRD equation
\end{align}
请注意,a\\
将构造移至下一个方程。这就是为什么\label{eq:Equat_1}
实际上是\label
第二个方程的 a,而不是第一个方程的 a。
这是您的想法的更清晰的实现align
;您不需要嵌套aligned
构造:
\documentclass{article}
\usepackage{amsmath,bm}
\begin{document}
\begin{align}
\mathbf{X}_{i, k \mid k - 1}
&= \hat{\mathbf{x}}_{k \mid k - 1} + \mathbf{S}_{k \mid k - 1} \bm{\xi}_i
\label{eq:Equat_1} \\
\mathbf{Y}_{i, k \mid k - 1}
&= \mathbf{h}(\mathbf{X}_{i, k \mid k - 1}, \bm{\theta})
\label{eq:Equat_2} \\
\hat{\mathbf{y}}_{k \mid k - 1}
&= \frac{1}{m} \sum_{i = 1}^m \mathbf{Y}_{i, k \mid k - 1}
\label{eq:Equat_3}
\end{align}
\end{document}