答案1
这是一种方法。
\documentclass{article}
\usepackage{circledsteps}
\begin{document}
\begin{enumerate}
\item $\Circled{~\alpha\vphantom{\beta}~}\hspace{-1ex}\Circled{~\beta~}$
\item $\Circled{~\alpha~\Circled{\beta}~}$
\item $\Circled{~\beta~\Circled{\alpha}~}$
\item $\Circled{~\alpha\vphantom{\beta}~}\,\Circled{~\beta~}$
\item $\Circled{~\alpha\equiv\beta~}$
\end{enumerate}
\end{document}
\documentclass{article}
\usepackage{circledsteps}
\usepackage{tasks}
\begin{document}
\begin{tasks}(3)
\task $\Circled{~\alpha\vphantom{\beta}~}\hspace{-1ex}\Circled{~\beta~}$
\task $\Circled{~\alpha~\Circled{\beta}~}$
\task $\Circled{~\beta~\Circled{\alpha}~}$
\task $\Circled{~\alpha\vphantom{\beta}~}\,\Circled{~\beta~}$
\task $\Circled{~\alpha\equiv\beta~}$
\end{tasks}
\end{document}
如果你想要真正的椭圆,使用 Ti钾Z。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{fit,shapes.geometric,positioning}
\tikzset{elli/.style={ellipse,inner xsep=1ex,inner ysep=1pt,draw,execute at
begin node={\vphantom{$\beta$}}}}
\usepackage{tasks}
\begin{document}
\begin{tasks}(3)
\task \begin{tikzpicture}[baseline={(alpha.base)}]
\node[elli](alpha){$\alpha$};
\node[base right=-1ex of alpha,elli](beta){$\beta$};
\end{tikzpicture}
\task \begin{tikzpicture}[baseline={(alpha.base)}]
\node(alpha){$\alpha$};
\node[base right=1ex of alpha,elli](beta){$\beta$};
\node[draw,fit=(alpha)(beta),elli]{};
\end{tikzpicture}
\task \begin{tikzpicture}[baseline={(alpha.base)}]
\node[elli](alpha){$\alpha$};
\node[base left=1ex of alpha](beta){$\beta$};
\node[draw,fit=(alpha)(beta),elli]{};
\end{tikzpicture}
\task \begin{tikzpicture}[baseline={(alpha.base)}]
\node[elli](alpha){$\alpha$};
\node[base right=1ex of alpha,elli](beta){$\beta$};
\end{tikzpicture}
\task \begin{tikzpicture}[baseline={(alpha.base)}]
\node[elli](alpha){$\alpha\equiv\beta$};
\end{tikzpicture}
\end{tasks}
\end{document}