我正在尝试将下图与中心对齐。
不知怎的,我就是做不到。我试过scope
,baseline
甚至\vbox
用包裹\begin{matrix}\end{matrix}
。它们都给出与上面相同的结果。
这是我使用的代码
\begin{equation}
\begin{tikzpicture}
\node[scale=0.6] at (0.3,-0.2) {5};
\node[scale=0.6] at (0.6,-0.2) {3};
\node[scale=0.6] at (0.9,-0.2) {4};
\node[scale=0.6] at (1.2,-0.2) {1};
\node[scale=0.6] at (1.5,-0.2) {2};
\node[scale=0.6] at (0.3,0.9) {1};
\node[scale=0.6] at (0.6,0.9) {2};
\node[scale=0.6] at (0.9,0.9) {3};
\node[scale=0.6] at (1.2,0.9) {4};
\node[scale=0.6] at (1.5,0.9) {5};
\PlanarDiagram(5){{1/3,2/4,3/1,4/2,5/5}};
\end{tikzpicture}
=1
\end{equation}
使用定义的命令latex 命令的参数数量不确定
\usepackage{tikz}
\usetikzlibrary{braids,backgrounds,arrows.meta,positioning,fit}
\tikzset{pics/planar/.style 2 args = {
code = {
\draw[color=red] (0,0) rectangle (#1*0.3+0.3,0.7);
\foreach \dot in {1,...,#1}{ % draw the dots
\filldraw (0.3*\dot,0) circle [radius=1pt];
\filldraw (0.3*\dot,0.7) circle [radius=1pt];
}
% draw the lines
\foreach \x/\y in #2
\draw[->,>=stealth](0.3*\x,0) .. controls +(0,0.2) and +(0,-0.2) .. (0.3*\y,0.7);
}
}
}
\usepackage{xparse}
\NewDocumentCommand\PlanarDiagram{ O{} D(){3} m }{%
\begin{tikzpicture}[#1]
\foreach \diag [count=\c] in {#3} {
\draw(0,\c*0.7) pic[#1]{planar={#2}{\diag}};
}
\end{tikzpicture}
}
我是否遗漏了什么或者我应该更改定义的命令?
答案1
与往常一样,有三条重要规则:
- 切勿嵌套
tikzpicture
! - 绝不!
- 如果您加载
pgf
,那么您就拥有了 LaTeX 世界中处理可选参数的最佳方法之一。(如果您不加载pgf
,当然xparse
对于可选参数来说也很棒。)
您可以将所有内容构建为一个,pic
只需使用键即可处理所有变体。如果您稍后决定添加某些功能,请添加一个键。旧语法仍然有效。我刚刚show labels
为您的 的(某些变体)添加了一个键pic
。
\documentclass{article}
\usepackage{tikz}
\newif\ifPlanarDiagamShowLabels
\usetikzlibrary{arrows.meta,bending}
\tikzset{pics/planar diagram/.style={code={
\tikzset{planar diagram/.cd,#1}%
\def\pv##1{\pgfkeysvalueof{/tikz/planar diagram/##1}}%
\draw[/tikz/planar diagram/frame] ({-(\pv{n}+1)*\pv{x}/2},-\pv{y}/2) rectangle
({(\pv{n}+1))*\pv{x}/2},\pv{y}/2);
\ifPlanarDiagamShowLabels
\path foreach \XX in {1,...,\pv{n}}
{({-(\pv{n}+1)*\pv{x}/2+\XX*\pv{x}},-\pv{y}/2)
node[circle,fill,inner sep=1pt,label=below:$\XX$] (-b-\XX){}
({-(\pv{n}+1)*\pv{x}/2+\XX*\pv{x}},\pv{y}/2)
node[circle,fill,inner sep=1pt,label=above:$\XX$] (-t-\XX){}};
\else
\path foreach \XX in {1,...,\pv{n}}
{({-(\pv{n}+1)*\pv{x}/2+\XX*\pv{x}},-\pv{y}/2)
node[circle,fill,inner sep=1pt] (-b-\XX){}
({-(\pv{n}+1)*\pv{x}/2+\XX*\pv{x}},\pv{y}/2)
node[circle,fill,inner sep=1pt] (-t-\XX){}};
\fi
\edef\localconnections{\pv{connections}}
\foreach \XX/\YY in \localconnections{%
\draw[-{Stealth[bend]}] (-b-\XX) to[out=90,in=-90] (-t-\YY);
}
}},planar diagram/.cd,n/.initial=5,x/.initial=0.3,y/.initial=0.7,
show labels/.is if=PlanarDiagamShowLabels,frame/.style={},
connections/.initial={1/1}
}
\begin{document}
\begin{equation}
\begin{tikzpicture}[baseline={(X.base)}]
\path node(X){\phantom{X}}
pic[nodes={scale=0.6},every circle node/.append style={scale=5/3}]
{planar diagram={n=5,% number of nodes
show labels,% show numbers
frame/.style={draw=red},% red box
connections={1/3,2/4,3/1,4/2,5/5}% which circles get connected
}};
\end{tikzpicture}
=1
\end{equation}
\[
\begin{tikzpicture}
\matrix[row sep=-3pt]{\pic{planar diagram={n=3,connections={3/1}}};\\
\pic{planar diagram={n=3,connections={2/3}}};\\
\pic{planar diagram={n=3,connections={2/2}}};\\
};
\end{tikzpicture}
\]
\end{document}
答案2
感谢薛定谔的猫,我又获得了一次机会。一旦我移除外层,我就可以使用原始代码了。
\documentclass[10pt,a4paper]{article}
\usepackage{tikz}
\usetikzlibrary{braids,backgrounds,arrows.meta,fit}
\tikzset{pics/planar/.style 2 args = {
code = {
\draw[color=red] (0,0) rectangle (#1*0.3+0.3,0.7);
\foreach \dot in {1,...,#1}{ % draw the dots
\filldraw (0.3*\dot,0) circle [radius=1pt];
\filldraw (0.3*\dot,0.7) circle [radius=1pt];
}
% draw the lines
\foreach \x/\y in #2
\draw[->,>=stealth](0.3*\x,0) .. controls +(0,0.2) and +(0,-0.2) .. (0.3*\y,0.7);
}
}
}
\usepackage{xparse}
\NewDocumentCommand\PlanarDiagram{ O{} D(){3} m }{%
\begin{tikzpicture}[#1]
\foreach \diag [count=\c] in {#3} {
\draw (0,\c*0.7) pic[#1]{planar={#2}{\diag}};
}
\end{tikzpicture}%
}
\NewDocumentCommand\planarDiagram{ O{} D(){3} m }{%
\foreach \diag [count=\c] in {#3} {
\draw (0,\c*0.7) pic[#1]{planar={#2}{\diag}};
}
}
\begin{document}
\begin{equation}
\begin{matrix}
\begin{tikzpicture}
\begin{scope}[shift={(0,-0.7)}]
\planarDiagram(5){{1/3,2/4,3/1,4/2,5/5}};
\end{scope}
\node[scale=0.6] at (0.3,-0.2) {3};
\node[scale=0.6] at (0.6,-0.2) {4};
\node[scale=0.6] at (0.9,-0.2) {1};
\node[scale=0.6] at (1.2,-0.2) {2};
\node[scale=0.6] at (1.5,-0.2) {5};
\node[scale=0.6] at (0.3,0.9) {5};
\node[scale=0.6] at (0.6,0.9) {1};
\node[scale=0.6] at (0.9,0.9) {2};
\node[scale=0.6] at (1.2,0.9) {3};
\node[scale=0.6] at (1.5,0.9) {4};
\end{tikzpicture}
\end{matrix}=1
\end{equation}
\end{document}