宏定义内的双重哈希值？

Question 1

每种方法\def...{body}都会将正文内部表示中的井号数量减半。每种方法\toks<num>={body}都会保留井号数量。每种方法\write都会\scantokens将井号数量翻倍。

\def\macro{This is some hashes: ##} % we have one # in internal representation

\scantokens\expandafter{\expandafter\toks\expandafter0\expandafter{\macro}} 
% \scantotkens does \write, we have two internal #, \toks0 keeps two #.

\edef\newmacro{\the\toks0}  % this keeps two # in internal representation

\message{\meaning\macro, \meaning\newmacro} % \meaning doubles the #, so we see:
%             ##              ####
% because there is:
%             #               ##     in internal representation

\bye

Answer

每种方法\def...{body}都会将正文内部表示中的井号数量减半。每种方法\toks<num>={body}都会保留井号数量。每种方法\write都会\scantokens将井号数量翻倍。

\def\macro{This is some hashes: ##} % we have one # in internal representation

\scantokens\expandafter{\expandafter\toks\expandafter0\expandafter{\macro}} 
% \scantotkens does \write, we have two internal #, \toks0 keeps two #.

\edef\newmacro{\the\toks0}  % this keeps two # in internal representation

\message{\meaning\macro, \meaning\newmacro} % \meaning doubles the #, so we see:
%             ##              ####
% because there is:
%             #               ##     in internal representation

\bye

Question 2

您可以\edef使用\unexpanded：

\documentclass{article}
\de\documentclass{article}
\def\safedef#1#2{\edef#1{\unexpanded{#2}}}
\begin{document}
\def\macro{This is some hashes: ##}
\safedef\Macro{This is some hashes: ##}
\typeout{\macro -\Macro}
\end{document}

节目

这是一些哈希：##-这是一些哈希：####

Answer

您可以\edef使用\unexpanded：

\documentclass{article}
\de\documentclass{article}
\def\safedef#1#2{\edef#1{\unexpanded{#2}}}
\begin{document}
\def\macro{This is some hashes: ##}
\safedef\Macro{This is some hashes: ##}
\typeout{\macro -\Macro}
\end{document}

节目

这是一些哈希：##-这是一些哈希：####

Question 3

和expl3：

\documentclass{article}

\ExplSyntaxOn
\cs_new_protected:Npn \doublehashes #1 #2
 {
  \tl_set_eq:NN \l_tmpa_tl #2
  \regex_replace_all:nnN { \cP. } { \cP\#\cP\# } \l_tmpa_tl
  \tl_set_eq:NN #1 \l_tmpa_tl
 }
\ExplSyntaxOff

\def\macro{This is some hashes: ####}

\doublehashes\Macro\macro

\frenchspacing

\begin{document}

\texttt{\string\macro=\meaning\macro}

\texttt{\string\Macro=\meaning\Macro}

\end{document}

当然，您知道，它\meaning会为在替换文本中找到的每个井号打印两个井号。因此\macro有两个井号，并且\Macro有四个井号。

Answer

和expl3：

\documentclass{article}

\ExplSyntaxOn
\cs_new_protected:Npn \doublehashes #1 #2
 {
  \tl_set_eq:NN \l_tmpa_tl #2
  \regex_replace_all:nnN { \cP. } { \cP\#\cP\# } \l_tmpa_tl
  \tl_set_eq:NN #1 \l_tmpa_tl
 }
\ExplSyntaxOff

\def\macro{This is some hashes: ####}

\doublehashes\Macro\macro

\frenchspacing

\begin{document}

\texttt{\string\macro=\meaning\macro}

\texttt{\string\Macro=\meaning\Macro}

\end{document}

当然，您知道，它\meaning会为在替换文本中找到的每个井号打印两个井号。因此\macro有两个井号，并且\Macro有四个井号。

Question 4

一种etl基于的方法。这将类别代码 1 和 2 标记规范化为括号 ( {})，否则应符合标准。

\documentclass{article}

\usepackage{etl}

\ExplSyntaxOn
\cs_generate_variant:Nn \etl_token_replace_all_deep:nNn { V }
\NewDocumentCommand \doublehashes { m m }
  { \cs_set_nopar:Npe #1 { \etl_token_replace_all_deep:VNn #2 ## { #### } } }
\ExplSyntaxOff

\def\macro{This is some hashes: ####}
\doublehashes\Macro\macro

\begin{document}
\texttt{\string\macro=\meaning\macro}

\texttt{\string\Macro=\meaning\Macro}
\end{document}

Answer

一种etl基于的方法。这将类别代码 1 和 2 标记规范化为括号 ( {})，否则应符合标准。

\documentclass{article}

\usepackage{etl}

\ExplSyntaxOn
\cs_generate_variant:Nn \etl_token_replace_all_deep:nNn { V }
\NewDocumentCommand \doublehashes { m m }
  { \cs_set_nopar:Npe #1 { \etl_token_replace_all_deep:VNn #2 ## { #### } } }
\ExplSyntaxOff

\def\macro{This is some hashes: ####}
\doublehashes\Macro\macro

\begin{document}
\texttt{\string\macro=\meaning\macro}

\texttt{\string\Macro=\meaning\Macro}
\end{document}

宏定义内的双重哈希值？

答案1

答案2

答案3

答案4

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