我正在尝试重现这个自动机：
这是我迄今为止所取得的成就：
这是我的 MWE：
\documentclass[12pt]{article}
\usepackage[english]{babel}
\usepackage[utf8x]{inputenc}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{arrows,automata,decorations.pathreplacing}
\begin{document}
\begin{tikzpicture}[->,>=stealth',shorten >=1pt,auto,node distance=3cm,scale = 1,transform shape,bend angle=10,accepting/.style={double distance=2pt, outer sep=0.75pt+\pgflinewidth}]
\node[state,initial] (p_0) {$p_0$};
\node[state] (p_1) [right of=p_0] {$p_1$};
\node[state] (p_2) [right of=p_1] {$p_2$};
\node (p_3) [right of=p_2] {$\dots$};
\node[state] (p_k) [right of=p_3] {$p_k$};
\path (p_0) edge node {$0$} (p_1)
(p_1) edge node {$0$} (p_2)
(p_2) edge node {$0$} (p_3)
(p_3) edge node {$0$} (p_k);
\draw[decorate,thick, decoration={brace, amplitude=10pt,mirror}] (p_0.south) -- (p_k.south)
node [midway,below=10pt] {$k+1$};
\end{tikzpicture}\\
\end{document}
问题是，在我的代码中，下括号的末尾有一个箭头（不需要）。
我做了一个测试，我明白这是由于括号->内的原因。 有没有人能给我一些提示？谢谢！\begin{tikzpicture}
答案1
->从 的选项移至相关路径 的。此外，使用tikzpicture（或可能）。optionspositioningchains
\documentclass[12pt]{article}
\usepackage[english]{babel}
\usepackage[utf8x]{inputenc}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{arrows,automata,decorations.pathreplacing,positioning}
\begin{document}
\begin{tikzpicture}[>=stealth',shorten >=1pt,auto,node distance=1.5cm,scale = 1,transform shape,bend angle=10,accepting/.style={double distance=2pt, outer sep=0.75pt+\pgflinewidth}]
\node[state,initial] (p_0) {$p_0$};
\node[state] (p_1) [right=of p_0] {$p_1$};
\node[state] (p_2) [right=of p_1] {$p_2$};
\node (p_3) [right=of p_2] {$\dots$};
\node[state] (p_k) [right=of p_3] {$p_k$};
\path[->] (p_0) edge node {$0$} (p_1)
(p_1) edge node {$0$} (p_2)
(p_2) edge node {$0$} (p_3)
(p_3) edge node {$0$} (p_k);
\draw[decorate,thick, decoration={brace, amplitude=10pt,mirror}] (p_0.south) -- (p_k.south)
node [midway,below=10pt] {$k+1$};
\end{tikzpicture}
\end{document}
