为什么这个编号方程的 (1) 是蓝色的？我希望 (1) 是黑色的。我该怎么做？谢谢 代码：
\documentclass{article}
\usepackage{color}
\usepackage{amsmath}
\usepackage{stix}
\usepackage{xcolor}
\usepackage{tcolorbox}
\usepackage[customcolors,shade]{hf-tikz}
\usepackage{tikz-cd}
\newcommand{\Tonde}[1]{\left(#1\right)}
\newcommand{\Stirling}{\lim_{n\longrightarrow\infty}\dfrac{n!}{\Tonde{\dfrac{n}{e}}^n\sqrt{2n\pi}}=1}
\begin{document}
\section{Formula di Stirling}
\hfsetfillcolor{gray!30}
\hfsetbordercolor{red}
\begin{equation}\label{StirlingLim}
\tikzmarkin[disable rounded corners=true]{b}(0.25,-1.2)(-0.25,0.8)\color{blue}{\Stirling}\tikzmarkend{b}
\end{equation}
\end{document}
答案1
颜色可能会泄漏。添加另一组：
\documentclass{article}
\usepackage{color}
\usepackage{amsmath}
\usepackage{stix}
\usepackage{xcolor}
\usepackage{tcolorbox}
\usepackage[customcolors,shade]{hf-tikz}
\usepackage{tikz-cd}
\newcommand{\Tonde}[1]{\left(#1\right)}
\newcommand{\Stirling}{\lim_{n\longrightarrow\infty}\dfrac{n!}{\Tonde{\dfrac{n}{e}}^n\sqrt{2n\pi}}=1}
\begin{document}
\section{Formula di Stirling}
\hfsetfillcolor{gray!30}
\hfsetbordercolor{red}
\begin{equation}\label{StirlingLim}
\tikzmarkin[disable rounded corners=true]{b}(0.25,-1.2)(-0.25,0.8){\color{blue}{\Stirling}}\tikzmarkend{b}
\end{equation}
\end{document}