如何对齐两列论文中的方程式？

Question

我想在两栏纸上写方程式。但是，如果我的方程式太长，方程式看起来就不好看。方程式 1 是正确的方程式格式。我该如何更改方程式以匹配文本格式？例如，我应该将方程式写成两行。

\documentclass[journal,twoside,web]{IEEEtran}
%\usepackage{generic}
\usepackage{cite}
\usepackage{amsmath,amssymb,amsfonts}
\usepackage{algorithmic}
\usepackage{graphicx}
\usepackage{textcomp}
\usepackage{tabularx}
\usepackage{amsmath}
\usepackage{cite}
\usepackage{cuted}

\begin{document}
\title{Preparation of Papers for IEEE Trans on Industrial Informatics (February 2022)}
\author{\dots}

\maketitle

\begin{abstract}
One of the world's fashion capitals, \dots
\end{abstract}

\begin{equation}
C_m = (D_{m_1}, D_{m_2}, ..., D_{mk_m}), (m \in (1, j))\quad
\end{equation}


\begin{strip}
\begin{align*}
W_{imd} = \frac{\sigma_{md\_ind\_i3}}{\sum_{n=1}^{k_m} \sigma_{mn\_ind\_i}} ,   (d \in (0, k_m), k_m \in (k_11, k_j2), m \in (1, j), i \in (1, h33)) \label{eq:2}
\end{align*}
\end{strip}

\begin{equation}
W_{imd} = \frac{\sigma_{md\_ind\_i3}}{\sum_{n=1}^{k_m} \sigma_{mn\_ind\_i}} ,   (d \in (0, k_m), k_m \in (k_11, k_j2), m \in (1, j), i \in (1, h33)) \label{eq:2}
\end{equation}
The destiny of Milan, \dots
\end{document}

Answer 1

如果您接受两行以上，拆分索引定义可能会很有用

\documentclass[journal,twoside,web]{IEEEtran}
%\usepackage{generic}
\usepackage{cite}
\usepackage{amsmath,amssymb,amsfonts}
\usepackage{algorithmic}
\usepackage{graphicx}
\usepackage{textcomp}
\usepackage{tabularx}
\usepackage{amsmath}
\usepackage{cite}
\usepackage{cuted}
\usepackage{mathtools}

\usepackage{kantlipsum}   % <--- dummy text

\begin{document}
\title{Preparation of Papers for IEEE Trans on Industrial Informatics (February 2022)}
\author{\dots}

\maketitle

\begin{abstract}
\kant[10]
\end{abstract}

\kant[1][1]

\begin{equation}
C_m = (D_{m_1}, D_{m_2}, ..., D_{mk_m}), (m \in (1, j))\quad
\end{equation}

The destiny of Milan, \dots

\begin{gather}
    W_{imd} = \frac{\sigma_{md\_ind\_i3}}{\sum_{n=1}^{k_m} \sigma_{mn\_ind\_i}}, \label{eq:2} \\[6pt]
    \begin{array}{r @{\ \in\ } l}
          d & (0, k_m), \\
        k_m & (k_11, k_j2), \\
          m & (1, j), \\
          i & (1, h33)
    \end{array} \nonumber
\end{gather}

\kant[2-4]

\end{document}

Answer 2

您的文档加载了该amsmath包，但并未利用该包的机制来 (a) 在需要的地方插入换行符，以将较长的方程式拆分为两行，以及 (b) 定义方程式之间的对齐点。您可能希望实现类似以下的功能。

\documentclass[journal,twoside,web]{IEEEtran}
%\usepackage{generic}
\usepackage{cite}
\usepackage{amsmath,amssymb} %%,amsfonts}
\usepackage{algorithmic}
\usepackage{graphicx}
%%\usepackage{textcomp}
\usepackage{tabularx}
%%\usepackage{amsmath}
%%\usepackage{cite}
\usepackage{cuted}

\begin{document}
\title{Preparation of Papers for IEEE Trans on \\
Industrial Informatics (February 2022)}
\author{\dots}

\maketitle

\begin{abstract}
One of the world's fashion capitals, \dots
\end{abstract}

\begin{align}
C_m &= (D_{m_1}, D_{m_2}, \dots, D_{mk_m}), \quad (m \in (1, j)) \\[1ex]
W_{imd} &= \frac{\sigma_{\mathrm{md\_ind}\_i3}}{\sum_{n=1}^{k_m} \sigma_{\mathrm{mn\_ind}\_i}} , \quad \bigl(d \in (0, k_m), \label{eq:2}\\[1ex]
&\qquad  k_m \in (k_{11}, k_{j2}),\  m \in (1, j),\ i \in (1, h33)\bigr)  \notag
\end{align}

\end{document}

Answer 3

别管cuted了：这会让阅读论文变得非常困难。

也加载newtx，这样数学字体就会与文本字体匹配。但是，\_在这种情况下，该命令实际上并没有产生好的结果。

\documentclass[journal,twoside]{IEEEtran}
\usepackage{amsmath}
\usepackage{newtx}

\usepackage{lipsum}

\DeclareRobustCommand{\_}{\text{\kern.02em\vbox{\hrule width.3em}\kern.04em}}

\begin{document}
\title{Preparation of Papers for IEEE Trans on Industrial Informatics (February 2022)}
\author{\dots}

\maketitle

\begin{abstract}
\lipsum[2]
\end{abstract}

\lipsum[1][1-4]
\begin{equation}
C_m = (D_{m_1}, D_{m_2}, \dots, D_{mk_m}), (m \in (1, j))
\end{equation}
\lipsum[3][1-4]
\begin{equation}\label{eq:2}
\hspace{0.1em}
W_{imd} = \frac{\sigma_{md\_ind\_i3}}{\sum_{n=1}^{k_m} \sigma_{mn\_ind\_i}} ,
\hspace{1000pt minus 1fil}
\begin{aligned}[t]
(&d \in (0, k_m), k_m \in (k_{11}, k_{j2}), \\
 &m \in (1, j), i \in (1, h_{33}))
\end{aligned}
\end{equation}
\lipsum[4-12]

\end{document}

这个\hspace技巧可以覆盖数学方程式中关于间距的一些严格规则。

另一个技巧是使用split，这样方程编号就会居中，但我们需要欺骗 TeX 认为方程的主要部分的深度为零。

\begin{equation}\label{eq:2}
\begin{split}
\smash[b]{W_{imd} = \frac{\sigma_{md\_ind\_i3}}{\sum_{n=1}^{k_m} \sigma_{mn\_ind\_i}}} ,
\quad
(&d \in (0, k_m), k_m \in (k_{11}, k_{j2}), \\
 &m \in (1, j), i \in (1, h_{33}))
\end{split}
\end{equation}