\begin{equation}
\begin{split}
q_{\omega,sl}(z_p)=\frac{k_v^2\Theta\left(\omega,T_s\right)}{\pi^2}
Re\left(i\varepsilon_{rs}^{\prime\prime}(\omega)\int_{0}^{\infty}{k_\rho d k_\rho\int_{z_s}^{z_{s+1}}{dz_s}}
\left(g_{sl\rho\rho}^E\left(k_\rho,z_p,z_s,\omega\right)g_{sl\theta\rho}^{H^\ast}\left(k_\rho,z_p,z_s,\omega\right)
+g_{sl\rho z}^E\left(k_\rho,z_p,z_s,\omega\right)g_{sl\theta z}^{H^\ast}\left(k_\rho,z_p,z_s,\omega\right)
-g_{sl\theta\theta}^E\left(k_\rho,z_p,z_s,\omega\right)g_{sl\rho\theta}^{H^\ast}\left(k_\rho,z_p,z_s,\omega\right)
\right)\right)
\end{split}
\end{equation}
答案1
这是一个总体上与以下答案非常相似的答案@Zarko 的回答,主要是因为我还建议将长方程分成 4 行。然后我使用aligned
环境将底部 3 行彼此对齐。接下来,由于 TeX 不允许\left...\right
跨行,我建议使用\biggl[
和\biggr]
作为“外部”大括号,\Bigl[
使用和\Bigr]
作为“内部”大括号。此外,我会摆脱剩下的 7 个 [!] 对\left...\right
,它们除了造成代码混乱和弄乱水平间距外什么也不做。最后,您是否同意写起来''
比更容易^{\prime\prime}
?
\documentclass{article}
\usepackage{amsmath} % for split and aligned environments
\begin{document}
\begin{equation}
\begin{split}
q_{\omega,sl}(z_p)
&=\frac{k_v^2\Theta(\omega,T_s)}{\pi^2}\,
\Re\biggl[\,
i\varepsilon_{rs}''(\omega)
\int_{0}^{\infty}\!k_\rho \,dk_\rho
\int_{z_s}^{z_{s+1}}\!dz_s\\
&\qquad
\begin{aligned}\times\Bigl[\,
&g_{sl\rho\rho}^E(k_\rho,z_p,z_s,\omega)\,
g_{sl\theta\rho}^{H^\ast} (k_\rho,z_p,z_s,\omega) \\
{}+{}&g_{sl\rho z}^E(k_\rho,z_p,z_s,\omega)\,
g_{sl\theta z}^{H^\ast}(k_\rho,z_p,z_s,\omega) \\
{}-{}&g_{sl\theta\theta}^E(k_\rho,z_p,z_s,\omega)\,
g_{sl\rho\theta}^{H^\ast}(k_\rho,z_p,z_s,\omega)
\Bigr] \smash[t]{\biggr]}
\end{aligned}
\end{split}
\end{equation}
\end{document}
答案2
像这样?
在方程中,您需要手动插入断点。上图显示的方程使用了包multlined
中定义的数学环境mathtools
:
\documentclass[12pt]{article}
\usepackage{mathtools}
\begin{document}
\begin{equation}
\begin{multlined}
q_{\omega,sl}(z_p)
= \frac{k_v^2\Theta (\omega,T_st){\pi^2}
Re\biggl[i \varepsilon_{rs}^{\prime\prime}(\omega)\int_{0}^{\infty}{k_\rho d k_\rho\int_{z_s}^{z_{s+1}}{dz_s}} \\
\biggl(g_{sl\rho\rho}^E\left(k_\rho,z_p,z_s,\omega\right)g_{sl\theta\rho}^{H^\ast}
(k_\rho,z_p,z_s,\omega ) + \\
g_{sl\rho z}^E(k_\rho,z_p,z_s,\omega)g_{sl\theta z}^{H^\ast}
(k_\rho,z_p,z_s,\omega) - \\
g_{sl\theta\theta}^E (k_\rho,z_p,z_s,\omega) g_{sl\rho\theta}^{H^\ast} (k_\rho,z_p,z_s,\omega)\biggr)\biggr]
\end{multlined}
\end{equation}
\end{document}
或者通过使用split
环境:
\documentclass[12pt]{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{split}
q_{\omega,sl}(z_p)
= {} & \frac{k_v^2\Theta (\omega,T_st)} {\pi^2}
Re\biggl[i\varepsilon_{rs}^{\prime\prime}(\omega)\int_{0}^{\infty}{k_\rho d k_\rho\int_{z_s}^{z_{s+1}}{dz_s}}\cdot \\
& \biggl(g_{sl\rho\rho}^E\left(k_\rho,z_p,z_s,\omega\right)g_{sl\theta\rho}^{H^\ast}
(k_\rho,z_p,z_s,\omega ) \\
& + g_{sl\rho z}^E(k_\rho,z_p,z_s,\omega)g_{sl\theta z}^{H^\ast}
(k_\rho,z_p,z_s,\omega) \\
& - g_{sl\theta\theta}^E (k_\rho,z_p,z_s,\omega) g_{sl\rho\theta}^{H^\ast} (k_\rho,z_p,z_s,\omega)\biggr)\biggr]
\end{split}
\end{equation}
\end{document}
答案3
变体@Mico的回答。我倾向于不插入间距命令,除了在积分中分隔微分,有时在根号中。在所讨论的情况下,我喜欢 \multline 和 \aligned 的组合。我猜这纯粹是个人喜好问题。
\documentclass{article}
\usepackage{amsmath} % for split and aligned environments
\begin{document}
\begin{multline}
q_{\omega,sl}(z_p)
=\frac{k_v^2\Theta(\omega,T_s)}{\pi^2}
\Re\biggl[
i\varepsilon_{rs}''(\omega)
\int_{0}^{\infty}k_\rho\,dk_\rho
\int_{z_s}^{z_{s+1}}\,dz_s\\
\begin{aligned}
&\times\Bigl[g_{sl\rho\rho}^E(k_\rho,z_p,z_s,\omega)
g_{sl\theta\rho}^{H^*} (k_\rho,z_p,z_s,\omega) \\
&+g_{sl\rho z}^E(k_\rho,z_p,z_s,\omega)
g_{sl\theta z}^{H^*}(k_\rho,z_p,z_s,\omega) \\
&-g_{sl\theta\theta}^E(k_\rho,z_p,z_s,\omega)
g_{sl\rho\theta}^{H^*}(k_\rho,z_p,z_s,\omega)
\Bigr] \smash[t]{\biggr]}
\end{aligned}
\end{multline}
\end{document}