答案1
我想到的答案(当克拉拉发布时)与克拉拉的类似,但使用常规表格和@{}
来消除表格两侧的额外填充。
\documentclass{article}
\begin{document}
\[
\left\{
\begin{tabular}{@{}c@{}}
morphisms~from~$V$~to~$W$\\
as~algebraic~sets
\end{tabular}
\right\}
\longleftrightarrow
\left\{
\begin{tabular}{@{}c@{}}
$k$-algebra homomorphisms\\
from $k[W]$ to $k[V]$
\end{tabular}
\right\}
\]
\end{document}
答案2
\documentclass{article}
\usepackage{tabularray}
\usepackage{amsmath}
\begin{document}
\section{array}
\begin{equation}
\left\{
\begin{array}{@{\hskip2pt}c@{\hskip2pt}}
\text{morphisms from } V \text{ to } W\\
k-\text{algebra blablabla}
\end{array}
\right\}
\longleftrightarrow
\left\{
\begin{array}{@{\hskip2pt}c@{\hskip2pt}}
\text{morphisms from } V \text{ to } W\\
k-\text{algebra blablabla}
\end{array}
\right\}
\end{equation}
\section{tabular}
\begin{equation}
\left\{
\begin{tabular}{@{\hskip2pt}c@{\hskip2pt}}
morphisms from $V$ to $W$\\
$k$-algebra blablabla
\end{tabular}
\right\}
\longleftrightarrow
\left\{
\begin{tabular}{@{\hskip2pt}c@{\hskip2pt}}
morphisms from $V$ to $W$\\
$k$-algebra blablabla
\end{tabular}
\right\}
\end{equation}
\section{tabularray}
\begin{equation}
\left\{
\begin{tblr}{colspec={c},colsep={2pt}}
\text{morphisms from } V \text{ to } W\\
k-\text{algebra blablabla}
\end{tblr}
\right\}
\longleftrightarrow
\left\{
\begin{tblr}{colspec={c},colsep={2pt}}
\text{morphisms from } V \text{ to } W\\
k-\text{algebra blablabla}
\end{tblr}
\right\}
\end{equation}
\end{document}