答案1
像这样:
\documentclass[margin=3mm]{standalone}
\usepackage{circuitikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{circuitikz}[american,
node distance = 24mm,
N/.style = {draw=teal, thick, align=left, minimum height=24mm}
]
\ctikzset{voltage/american font=\tiny,
}
bipole current style/.style={line width=1pt}
\draw (0,0) node [N] (in) {Linear\\ two-terminal\\ circuit}
([yshift=+6mm] in.east) coordinate (in-a)
([yshift=-6mm] in.east) coordinate (in-b)
node [N, right=of in] (out) {load}
(in-a) to [short,color=purple,f=$I$,-o]
++ (1.6,0) coordinate[label=above:$a$] (a)-- (a -| out.west)
(in-b) to [short,color=purple,-o]
++ (1.6,0) coordinate[label=below:$b$] (b)-- (b -| out.west)
(a) to [open,v=$V$] (b)
;
\end{circuitikz}
\end{document}
答案2
这会是您的起点吗?
\documentclass[tikz]{standalone}
\usepackage[oldvoltagedirection]{circuitikz}
\usetikzlibrary{calc}
\begin{document}
\begin{circuitikz}[american voltages] \draw (0,0)
node[draw,minimum width=2cm,minimum height=2.4cm] (load) {Load}
($(load.west)!0.75!(load.north west)$) coordinate (la)
($(load.west)!0.75!(load.south west)$) coordinate (lb)
(lb) to[short,-o] ++(-0.5,0) coordinate (b) node[below] {$b$}
to[short] ++(-4,0) coordinate (VThb)
to[V=$V_{\mathrm{Th}}$] (VThb |- la)
to[R=$R_{\mathrm{Th}}$] ++(2.5,0) coordinate (VTht)
to[short,-o,i=$I$] (VTht -| b) coordinate (a) node[above] {$a$}
to[short] (la);
\path (a) node[below] {$+$} -- node {$V$} (b) node[above] {$\vphantom{+}-$};
\end{circuitikz}
\end{document}