如何获取一个节点,该节点有一条边循环到同一个节点,但作为一条边而不是一条路径(即没有箭头)
这是我当前的代码:
\begin{tikzpicture}
[node distance = 20mm and 20mm,
main/.style = {draw, circle}]
every edge quotes/.style = {auto, font=\footnotesize}
\node[main] ({9}) {$v_1$};
\node[main] ({10}) [below right of = {9}] {$v_2$};
\node[main] ({11}) [below of = {10}] {$v_3$};
\node[main] ({13}) [below left of = {9}] {$v_4$};
\node[main] ({12}) [below of = {13}] {$v_5$};
\draw ({9}) edge[""] ({10});
\draw ({10}) edge[""] ({11});
\draw ({11}) edge[""] ({12});
\draw ({12}) edge[""] ({13});
\draw ({9}) edge[""] ({13});
\draw ({9}) edge[""] ({11});
\draw ({9}) edge[""] ({12});
\draw ({10}) edge[""] ({12});
\draw ({10}) edge[""] ({13});
\draw ({11}) edge[""] ({13});
\draw ({1}) edge [loop above] [""] (1);
尝试制作一个在顶部顶点有循环的五面体图,但使用此代码,循环是一条路径(有一个箭头}
谢谢