尝试将多行表转换为多行+多列

尝试将多行表转换为多行+多列

我有这张桌子

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我正在尝试将其转换为这个

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我的代码是这样的

\documentclass{article}
\usepackage{graphicx} % Required for inserting images
\usepackage{tabularray}

\begin{document}

\begin{table}
\centering
\begin{tblr}{hlines, vlines, colspec={ll}}
\SetCell[r=6]{} Expression
    & \SetCell[r=3]{} Modality
    & P                         \\
    & O                         \\
    & A                         \\
    & \SetCell[r=3]{} Expressive Symbols
    & P                         \\
    & O                         \\
    & A                         \\
\end{tblr}
\caption{The Audit CheckList}
\label{table:DesignPrinciples}
\end{table}


\end{document}

更新:

迄今为止

我不知道如何强制将只有 3 个元素的行除以 3 并避免出现任何空单元格。此外,无论我做什么,第一列都无法扩展它来为文本腾出空间

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\documentclass{article}
\usepackage{nicematrix}
\begin{document}

\begin{NiceTabular}{ccccccc}[hvlines]
\Block{4-2}{Expressiveness} &       & \Block{1-5}{Modality} \\
               &       &  P & O & A &  & \\
               &       & \Block{1-5}{Expressive Symbols} \\
               &       &  P & O & A &  & \\
\Block{6-2}{Replication} &       & \Block{1-5}{Placeholders} \\
               &       &  P & O & A & S & F\\
               &       & \Block{1-5}{Stacking} \\
               &       &  P & O & A &  & \\
               &       & \Block{1-5}{Afixing} \\
               &       &  P & O &  &  & \\
\Block{8-2}{Narration} &       & \Block{1-5}{Storyline Formation} \\
               &       &  1 & 2 & 3 & & \\
               &       & \Block{1-5}{Block Formation} \\
               &       &  (1 , 1) & (1 , 2) & (2 , 1) &  & \\
               &       & \Block{1-5}{Group Composition} \\
               &       &  P & O &  &  & \\
               &       & \Block{1-5}{Frame Fixation} \\
               &       &  P & O & A & Grouped P & Grouped A\\
\Block{8-2}{Connection} &       & \Block{1-5}{Progression} \\
               &       &  P & O & A & & \\
               &       & \Block{1-5}{Transition} \\
               &       &  P & O & A & & \\
               &       & \Block{1-5}{Aggregation} \\
               &       &  P & O & A & & \\
               &       & \Block{1-5}{Execution} \\
               &       &  P & O & A & & \\
\end{NiceTabular}

\end{document}

更新2 感谢 F. Pantigny:

问题在于空单元格

我怎样才能强制小单元格一直扩展并填充空间而没有空单元格

例如除以 2、3、4、5

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\documentclass{article}
\usepackage{nicematrix}
\begin{document}

\begin{NiceTabular}{lccccc}[hvlines,cell-space-limits=3pt]
\Block{4-1}{Expressiveness} & \Block{1-5}{Modality} \\
               &  P & O & A \\
               & \Block{1-5}{Expressive\\ Symbols} \\
               &  P & O & A \\           
\Block{6-1}{Replication} & \Block{1-5}{Placeholders} \\
               &  P & O & A & S & F\\
               & \Block{1-5}{Stacking} \\
               &  P & O & A \\
               & \Block{1-5}{Affixing} \\
               &  P & O \\
\Block{8-1}{Narration} & \Block{1-5}{Storyline Foundation} \\
               &  1 & 2 & 3\\
               & \Block{1-5}{Block Formation} \\
               &  (1 , 1) & (1 , 2) & (2 , 1) \\
               & \Block{1-5}{Group Composition} \\
               &  P & O \\  
               & \Block{1-5}{Frame Fixation} \\
               &  P & O & A & Grouped P & Grouped O\\
\Block{8-1}{Connection} & \Block{1-5}{Progression} \\
               &  P & O & A \\
               & \Block{1-5}{Transition} \\
               &  P & O & A \\
               & \Block{1-5}{Aggregation} \\
               &  P & O & A \\  
               & \Block{1-5}{Execution} \\
               &  P & O & A \\  
\end{NiceTabular}\newline\newline\newline


\end{document}

答案1

据我所知,这可以通过嵌套单元格来获得tabular例如tblr作为起点:

编辑:从OP评论可以看出,嵌套的s中的表tabular没有垂直线,因此代码现在稍微简单一些:

\documentclass{article}
\usepackage{array}
\usepackage{tabularray}

\begin{document}
    \begin{table}
\centering
\begin{tblr}{hlines, vlines, colspec={lc}, 
             row{even} = {rowsep=0pt}
            }
\SetCell[r=4]{} Expression
    & Modality              \\
    &   \begin{tabular}{@{} *{3}{w{c}{3.33 em}} @{}} % 3.33 = 10/3
        P & O & A                         
        \end{tabular}       \\
    & Expressive Symbols    \\
    &   \begin{tabular}{@{} *{5}{w{c}{2em}} @{}} % 2 = 10/5
        P & O & A & S & F
        \end{tabular}       \\
\end{tblr}
\caption{The Audit CheckList}
\label{table:DesignPrinciples}
    \end{table}
\end{document}

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答案2

与。{NiceTabular}nicematrix

\documentclass{article}
\usepackage{nicematrix}

\begin{document}

\begin{NiceTabular}{lw{c}{5cm}}[hvlines,cell-space-limits=3pt]
\Block{4-1}{Expressiveness} & Modality \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\
               & Expressive Symbols \\
               &  \omit\hfil P\hfil\vrule\hfil  O\hfil\vrule\hfil A\hfil \\           
\Block{6-1}{Replication} & Placeholders \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil\vrule\hfil S\hfil\vrule\hfil F\hfil \\
               &  Stacking \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\
               &  Affixing \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil \\
\Block{8-1}{Narration} & Storyline Foundation \\
               &  \omit\hfil 1\hfil\vrule\hfil 2\hfil\vrule\hfil 3\hfil \\
               &  Block Formation \\
               &  \omit\hfil (1 , 1)\hfil\vrule\hfil (1 , 2)\hfil\vrule\hfil (2 , 1)\hfil \\
               &  Group Composition \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil \\  
               &  Frame Fixation \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil\vrule\hfil Grouped P\hfil\vrule\hfil Grouped O\hfil \\
\Block{8-1}{Connection} & Progression \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\
               &  Transition \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\
               &  Aggregation \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\  
               &  Execution \\
               &  \omit\hfil P\hfil\vrule\hfil O\hfil\vrule\hfil A\hfil \\  
\end{NiceTabular}

\end{document}

上述代码的输出

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